Deflection

The columns are shorter than the core

Every column in a tall building gets shorter as the building is built on top of it, and the core beside it gets shorter by a different amount. The floors between them tilt by the difference — and the difference is largest exactly half way up, because a floor near the top has almost nothing built above it and a floor near the bottom has almost nothing beneath it.

Assumes The deflection that arrives three years late, The structure that was never complete and Stiffness is not strength, and usually it is the one that governs.

A 40-storey concrete column at a working stress of 12 N/mm² shortens by about 26 mm elastically over its height. Creep takes that to 83 mm, and shrinkage adds another 43, so the column is about 127 mm shorter than the length of concrete that was cast into it.

That number is quoted often and it is almost never the number that matters. Every floor was built to its correct level on the day it was built, so the accumulated shortening beneath it had already happened and was already levelled out. What a finished building shows is only the part that arrived after each floor was set — and that part is much smaller, differently distributed, and shaped like nothing an intuition about accumulation would suggest.

Two differences up the same building, peaking in different placesDifferential shortening between a perimeter column and the core of a 40-storey building, plotted up the height. The part driven by load peaks at level 20 — exactly half way up, because a floor near the top has almost nothing built above it to shorten what is beneath, and a floor near the bottom has almost nothing beneath it to shorten. The part driven by shrinkage does not care what is above it at all and accumulates all the way to the roof. Their sum is worst at level 40, at 43 mm, which across a 9 m bay is a floor out of level by one in 208.-40-30-20-10010020406080100120140column shorter than core (mm)height (m)from loadfrom shrinkagethe sumworst 43 mmat level 40one in 208
Fig. 1 Differential shortening between a steel perimeter column and a concrete core, up a 40-storey building. Two curves with different shapes: the load-driven part peaks half way up, and the shrinkage-driven part accumulates all the way to the roof.

Why the middle and not the top

Take a floor at level kk of NN. It is built, levelled, and then the building above it continues.

What shortens the columns beneath it afterwards is the load from levels k+1k+1 to NN, which is a fraction (Nk)/N(N-k)/N of the final stress. That falls to zero as kk approaches the roof.

How many storeys of column are beneath it to do the shortening is kk, which rises from zero at the base.

The post-installation shortening at level kk is the product:

δ(k)    k(Nk)\delta(k) \;\propto\; k\,(N-k)

which is a parabola, zero at both ends and maximum at k=N/2k = N/2.

Two differences up the same building, peaking in different placesDifferential shortening between a perimeter column and the core of a 40-storey building, plotted up the height. The part driven by load peaks at level 20 — exactly half way up, because a floor near the top has almost nothing built above it to shorten what is beneath, and a floor near the bottom has almost nothing beneath it to shorten. The part driven by shrinkage does not care what is above it at all and accumulates all the way to the roof. Their sum is worst at level 20, at 20 mm, which across a 9 m bay is a floor out of level by one in 443.05101520020406080100120140column shorter than core (mm)height (m)from loadfrom shrinkagethe sumworst 20 mmat level 20one in 443
Fig. 2 The same building with a concrete column instead of a steel one, so the shrinkage of the two elements cancels and only the load-driven part is left. The curve is a clean parabola: 0.0 mm at the base, 8.9 at level 5, 19.1 at level 15, 20.3 at level 20, and back to 0.0 at the roof.

Both ends being zero is worth sitting with, because both are surprising for opposite reasons.

Zero at the base because there is no column beneath the ground floor to shorten. Obvious once stated.

Zero at the roof because nothing is built above the roof. The columns beneath the top floor do continue to creep and shrink, but the top floor was set at the very end of construction, and by then the elastic part of the movement had already happened. The top of a tall building is the one place where differential shortening is not a problem.

The difference, not the movement

The parabola above is the column’s post-installation shortening. The core does the same thing at its own stress, and the floor spans between them, so what matters is the difference.

For the building drawn, the column works at 12 N/mm² and the core at 6 — cores are sized for wind and lateral stiffness rather than for gravity, so they are habitually at half the stress of the columns they stand beside. That is the stiffest path taking the load inverted: the stiffest element here is deliberately the one carrying least. The differences run:

level column core difference
0 0.0 0.0 0.0 mm
10 30.5 15.2 15.2
20 40.7 20.3 20.3
30 30.5 15.2 15.2
40 0.0 0.0 0.0

The peak differential is 20.3 mm, over a 9 m bay from the core to the column. That is a floor out of level by one in 443, which is about twice the tilt a person can detect underfoot and roughly the tolerance a raised floor system is set to.

Which free body produced the number

Every quantity above is σL/E\sigma L/E, applied storey by storey, and the only difficulty is bookkeeping.

Take one storey of column, of height hh, at a stress σi\sigma_i once the building is complete. Its total elastic shortening is σih/E\sigma_i h/E. Multiply by (1+ϕ)(1 + \phi) for creep and add εshh\varepsilon_{sh} h for shrinkage, both of which act on the whole storey whatever the load history.

Then apply the sequence: for a floor at level kk, only the load applied after level kk was set contributes. The stress from that load is σ0(Nk)/N\sigma_0 (N-k)/N for every storey below, and summing over the kk storeys gives the parabola.

The arithmetic is elementary and the failure mode is not: using the total rather than the post-installation part overstates the problem by a factor of six for this building, and using the column’s movement rather than the difference from the core overstates it by a factor of two on top of that.

The deflection that arrives years lateThe multiplier on a concrete member's deflection under a sustained load, against time. The elastic deflection arrives on the day the load does and is the 1.0 at the left. After a year it has been multiplied by 3.00, after five years by 3.29, and it approaches 3.34. Nothing has been added to the load and nothing about the strength has changed: this is a serviceability failure arriving on a structure that passed every strength check on the day it was built.1 d8 d60 d1.3 yr9.9 yr00.511.522.533.5time under loaddeflection ÷ the deflection on day one1 year: ×3.005 years: ×3.29the deflection the calculation gives
Fig. 3 The deflection that arrives three years late: the multiplier on a concrete member’s movement under a sustained load. Creep takes the column’s elastic 26 mm to 83, which is where most of the 127 mm comes from — and it arrives over years, so a building measured at handover has not finished moving.

Shrinkage points the other way

The second curve on the hero figure is a different mechanism with a different shape.

Shrinkage does not care what is built above. A concrete element loses moisture and gets shorter on its own schedule, so its contribution accumulates with the number of storeys and is largest at the top:

δsh(k)=εshhk\delta_{sh}(k) = \varepsilon_{sh}\,h\,k

which is a straight line, zero at the base and largest at the roof.

When the column and the core are both concrete this cancels almost entirely — both shrink, both by roughly the same strain, and the difference is small. When they are different materials it does not. A steel perimeter column against a concrete core has no shrinkage at all on one side and 300 microstrain on the other, so the core gets shorter than the column by 43 mm at the roof, and the tilt reverses direction on the way up.

That is the crossing visible on the first figure: the load-driven part makes the column shorter, peaking in the middle; the shrinkage-driven part makes the core shorter, peaking at the top; and somewhere around two thirds of the height the sum passes through zero and changes sign. A floor that tilts one way at level 15 tilts the other way at level 35.

It moves, or it pushes. Never both, and never neitherA 30 m steel member 30 °C warmer than it was built, in three conditions. Free, it grows 10.8 mm and carries nothing. Held, it moves nothing and carries 75.6 MPa — which is E·α·ΔT and contains neither the length nor the area of the member, so the identical stress arises in a two-metre strut. Held by a spring it does some of each: 3.2 mm of movement and 53.2 MPa, and the split is decided by the spring rather than by the member.free at one end10.8 mmno stressheld at both ends75.6 MPaheld by a spring of 100 kN/mm53.2 MPaE·α·ΔT = 210000 × 12×10⁻⁶ × 30 = 75.6 MPa, at every length
Fig. 4 The family all of this belongs to. Creep, shrinkage and temperature are imposed deformations — the structure is asked to change length by something that is not a load, and what happens next depends entirely on what is restraining it.

What it does to the structure

The differential is a support settlement as far as the floor beams are concerned: one end goes down relative to the other, by 20 mm over 9 m, and an indeterminate floor system responds with forces.

One support too manyThe same uniformly loaded beam with three sets of restraints, and the bending moment in each. Adding restraint moves moment from mid-span to the supports and lowers the peak — but only the first case can be solved by statics.simply supportedstatics alonesag 40.0propped at one endneeds stiffnesssag 22.5hog 40.0built in at both endsneeds stiffnesssag 13.3hog 26.7the load never changes; only what is holding the endsthe built-in case peaks at two-thirds of the simple span's moment
Fig. 5 The support that moved, which is the same problem asked directly. A determinate member accommodates a support movement by tilting and carries nothing extra; a continuous one develops moments proportional to the movement and to its own stiffness, so the stiffer the floor the more it objects.
Which limit arrives firstUtilisation of the strength limit and of the deflection limit, against span. Strength grows as the square of the span and deflection as the fourth power, so the two cross — and past the crossing a beam is sized by how far it moves rather than by what it can carry.0.60.811.21.41.61.8200.511.5span, relative to the firstthey cross heredeflection runs out at 1.40strength runs out at 1.54the limitstrengthdeflection
Fig. 6 And which limit it threatens. Nothing on this page is a strength problem — the forces induced are modest and they relax by creep — but everything on it is a fit problem, and fit has no reserve factor.

The consequences that actually arise are all about things that are not structure:

Cladding. A curtain wall is fixed to the slab edges and has movement joints sized for a stated storey-to-storey change. A differential of 20 mm distributed over the height as a parabola means the joints at mid-height close and the ones near the top do not.

Lifts. A lift guide rail is fixed to the core and must stay straight and plumb over the full height. The core moving relative to the floors that brace the shaft is exactly the movement the rail brackets have to absorb.

Services. A riser fixed to the core and branching into a floor supported by columns crosses the differential at every level.

And finishes. Partitions, screeds and level thresholds all record a tilt that developed after they were installed.

The props decide where the stress ends upBottom-fibre stress in the steel of a 12 m composite beam carrying 12 kN/m of wet concrete and 18 kN/m afterwards. Unpropped, the bare steel takes the first stage alone and reaches 292 MPa; propped, the finished composite section takes everything and reaches 186 MPa — a ratio of 1.57. 62% of the unpropped beam's final stress was locked in before the slab was structural at all. The deflections differ by 1.73 times for the same reason, and no drawing of the finished beam distinguishes the two.292 MPaunpropped49.3 mm at midspansteel alonecomposite186 MPapropped28.6 mm at midspancomposite
Fig. 7 The same idea in a beam, where 62% of an unpropped composite beam’s final stress was locked in before the slab was structural. The sequence decides the answer in both cases, and in both cases the completed structure is not the structure that carried the load.

Compensation is the answer, and it is applied during construction

Nothing here is repaired by analysis. The remedy is to build each floor higher than its nominal level, by the amount it is predicted to drop after it is set.

Cambered against the wet loadA 12 m composite beam whose flexural rigidity rises from 94 to 260 kN·m² when the slab sets, so the first two loads are carried by the bare steel and the rest by the composite section. Fabricated with 25.3 mm of camber, it moves through -20.7, 0.0, 7.5, 12.7 mm as the four stages arrive — 0.0 mm on the day the slab is poured, and 12.7 mm at the end, which is one part in 947 of the span. The largest curvature it ever has is 25.3 mm of hog, and it has that with nothing on it. Every shape is drawn at the same exaggeration and the drawing is a diagram of a proportion: the vertical scale is 119484 times the horizontal.levelas fabricated: 25.3 mm of camber-20.70.07.512.7self-weight of the steel: 4.6 mm on EI = 94wet concrete: 20.7 mm on EI = 94finishes and services: 7.5 mm on EI = 260imposed load: 5.2 mm on EI = 260
Fig. 8 Cambering against the load that has not arrived, which is the beam version of the same operation: fabricate the member in the wrong shape so that the right shape arrives with the load. Compensation for shortening is that instruction, applied to a level rather than to a profile.

The compensation follows the parabola, so it is largest in the middle of the building and zero at both ends — floor levels near the top are set nominally, floors at mid-height are set 20 mm high, and the building arrives level. It is applied by the surveyor rather than by the designer, from a table the designer produces, and it depends on a prediction of creep and shrinkage made years before the movements finish — the same prediction a cambered beam depends on, and just as hard to check afterwards.

Which is the honest weakness of the whole exercise: the compensation is exact and the prediction is not. Creep coefficients carry an uncertainty of perhaps ±30%, and the compensation carries that uncertainty into the built levels.

Built as two beams, used as oneBending moments in a two-span beam erected as simple spans under 12 kN/m and made continuous before the remaining 18 kN/m arrived, against the same beam built continuous from the start. The support moment is 324 kNm rather than 540 — 60% of it — and the midspan moment is 378 rather than 270, which is 140%. Both diagrams are in equilibrium with the same total load; they differ only in when the joint was made, which appears nowhere on the drawing.540 kNm built continuous324 staged378270same beam, same load, different history
Fig. 9 And the general statement one more time: continuity made later is not continuity. Every quantity on this page depends on when a piece became structural, which is a fact about a programme rather than about a structure.

It gets worse with height, linearly

Two differences up the same building, peaking in different placesDifferential shortening between a perimeter column and the core of a 80-storey building, plotted up the height. The part driven by load peaks at level 40 — exactly half way up, because a floor near the top has almost nothing built above it to shorten what is beneath, and a floor near the bottom has almost nothing beneath it to shorten. The part driven by shrinkage does not care what is above it at all and accumulates all the way to the roof. Their sum is worst at level 40, at 41 mm, which across a 9 m bay is a floor out of level by one in 221.010203040050100150200250column shorter than core (mm)height (m)from loadfrom shrinkagethe sumworst 41 mmat level 40one in 221
Fig. 10 The same stresses and the same materials at 80 storeys instead of 40. The peak differential is 40.7 mm against 20.3 — exactly double, at exactly double the height — because the parabola’s peak is proportional to NN while its shape is not.
storeys peak differential tilt over a 9 m bay
20 10.2 mm 1 in 885
40 20.3 1 in 443
60 30.5 1 in 295
80 40.7 1 in 221

Half a millimetre per storey, for these stresses and this bay. That is why differential shortening is a subject for tall buildings and a footnote for short ones: at twelve storeys it is 6 mm and inside the construction tolerance; at eighty it is 41 and outside everything.

And it is one of the few problems in this collection that gets worse in proportion to the height rather than to some power of it. Span to the fourth is the usual shape of a serviceability limit, and this one is linear. Wind moments grow as the square of the height, overturning as the cube of it, and drift as the fourth power. Differential shortening grows linearly — which means that at some height it stops being the governing issue, and below that height it is a nuisance rather than a design driver.

Why the core and the columns differ at all

The whole subject exists because two vertical elements in the same building work at different stresses, and it is worth saying why they do rather than treating it as an accident.

A core is sized for lateral stiffness. Its walls are thick and long because the building has to resist wind and to keep its drift inside a limit, and what a tall building’s lateral system is for has almost nothing to do with how much gravity load the core carries. Having been sized that way, it has a great deal of area and a modest share of the weight, so its working stress is low.

Near the bottom the wall holds the frame. Near the top the frame holds the wallStorey shear carried by each system, up the height of a 30-storey building. At the base the wall takes 3% of nothing and the frame the rest; by level 22 the wall's share has gone negative — it is being dragged forward by the frame rather than restraining it, and the frame is carrying more than the whole applied shear. Neither system does that alone, and it is why the pair is stiffer than either: the top drift is 169 mm against 726 for the wall alone and 310 for the frame alone.-1000-50005001000020406080100storey shear carried (kN)height (m)the sign changeswallframe
Fig. 11 How a tall building stands still: a core and a frame tied together, with the core doing most of the work near the base. Every wall in that core was sized by the curve on that page, and its gravity stress is whatever is left over.

A column is sized for the gravity load it carries and nothing else. It is made as small as the load allows, because floor area is the product being sold and a column occupies some. So its working stress is as high as the code permits.

The ratio between the two is therefore not a design choice — it is a consequence of two elements being sized against two different criteria, and it is stable across buildings at around two to one. Which is why the differential is so reliably present, and why it is a core-against-column problem rather than a general one about columns.

Two ways of removing it exist and both cost something. Sizing the column for stiffness rather than strength wastes floor area on every storey. Sizing the core down until its stress matches the columns’ costs lateral stiffness, which is the thing the core was there for. Nobody does either, which is why compensation is the standard answer.

Where the model stops

The stress profile is assumed linear with height. Real columns are sized in groups, so the stress steps rather than tapers, and the steps put kinks in the parabola. The shape survives; the smoothness does not.

Creep is modelled by a single multiplier. Real creep depends on the age at loading, the member’s size, the humidity and the load history — and every storey is loaded at a different age. A proper calculation is a step-by-step integration with an ageing coefficient, and it gives a different number, usually larger near the base.

Reinforcement has been ignored. Steel in a concrete column does not creep or shrink, so it restrains the concrete around it and picks up load over time — which reduces the column’s shortening and increases the stress in the bars. A heavily reinforced column shortens appreciably less than this calculation says.

The core is treated as a single element at one stress. A real core has walls at different stresses, coupling beams between them, and openings, and its own shortening varies across its plan.

And nothing here is a temperature. A perimeter column exposed to outside air and a core in the middle of a heated building differ in temperature by tens of degrees, and αΔT\alpha \Delta T over 144 m is comparable with everything computed above.

What the pictures cannot show

The shortening figures plot millimetres against metres — 20 mm of differential against 144 m of height, which is a ratio of 1 in 7,000. Every one of them is drawn with the horizontal axis exaggerated by three orders of magnitude, and the honest statement is that none of this movement is visible in a building.

Nor can they show time. Every curve is the final state, and the movements arrive over five to ten years with the elastic part on the day and the creep part asymptotically. A building handed over at eighteen months has completed perhaps 60% of what these figures show.

And the parabola is drawn as though every floor were built on the same schedule. Construction pauses, floors are built out of order, and a slab cast in winter shrinks differently from one cast in summer.

The ladder from here

Later rungs on this anchor: step-by-step creep analysis with an ageing coefficient, and how much it moves the answer. The effect of reinforcement, and the long-term redistribution from concrete to steel inside a column. Outrigger structures, where the differential between core and columns is not merely a fit problem but a force — the outrigger is exactly the member that objects to it, and its forces can double over the life of the building. Compensation strategy: whether to compensate for elastic movement only, for elastic plus a fraction of creep, or for the predicted total. Composite megacolumns, where a steel core inside a concrete column changes the shortening and the fire rating at once. And the measurement question: what a building actually does, which is known from very few instrumented towers and differs from prediction by more than anybody would like.

Named alongside this one

Essays reaching for the same objects. Nobody chose these; they are what the concept index makes visible.

The objects this essay names

Each one links to every other essay that touches it.

Axial shorteningCompensationConstruction sequenceCoreCreepDifferential shorteningElastic modulusImposed deformationServiceabilityShrinkageSupport settlementTall building