Deflection

The support that moved

A redundant structure knows things statics cannot see. Settle one support by ten millimetres and a complete set of bending moments appears — in equilibrium with no load at all, and larger for a stiffer beam.

Assumes One support too many, and what it costs to know and The moment over the support, and what it buys.

Everything statics can determine about a structure comes from the sums cancelling. That is a powerful method and it has a boundary: when there are more unknowns than equations, the sums are satisfied by infinitely many force distributions and something other than equilibrium has to choose between them.

What chooses is compatibility — the requirement that the structure fit together after deforming — and the moment compatibility enters, the structure acquires a sensitivity that statics cannot describe at all. It begins to respond to things that are not loads.

3 continuous spans against 3 simple onesThe bending moment in a continuous beam whose support 1 has settled by 0.01. Three curves: the moment the load causes, the moment the settlement causes on its own — dashed, peaking at 73.5, and in equilibrium with no applied load at all — and their sum, which is what the beam carries, peaking at 73.5 against 24.5 without the settlement. The settlement field is proportional to EI: a stiffer beam is punished harder for the same movement, which is the opposite of every intuition load-carrying gives.this support 0.01 lowmoment19.6 sagging24.5 hogging30.6 if the spans were simplereactions 14.0 38.5 38.5 14.0 — the inner supports carry far more than a sharethe continuous case needed stiffness; the comparison did not
Fig. 1 Three continuous spans under a uniform load, with one interior support settled by ten millimetres. Three curves: the moments the load causes, the moments the settlement causes on its own — dashed, and in equilibrium with no applied load whatever — and their sum, which is what the beam carries. The settlement field is three times the size of the load field.

Ten millimetres is a construction tolerance. It is less than the depth of a screed, and it is invisible from the ground.

Why a moved support does nothing to a determinate beam

Take a simply supported beam and drop one of its supports by any amount. The beam rotates slightly as a rigid body and follows it down. No member changes length, no curvature is imposed, and the bending moments are unchanged to the last decimal place.

That is not a coincidence of the geometry. It is the definition of determinacy stated in the other direction: a determinate structure has exactly enough restraints to be held, so removing or moving one leaves the others free to accommodate it. The reactions are fixed by equilibrium alone, and equilibrium does not know where the supports are, only where the loads are and how far apart the reactions are.

Add a third support and everything changes. Now the beam cannot follow the moving support without bending, because the other two supports are holding the ends where they were. The imposed curvature is real, and curvature times EIEI is bending moment.

One support too manyThe same uniformly loaded beam with three sets of restraints, and the bending moment in each. Adding restraint moves moment from mid-span to the supports and lowers the peak — but only the first case can be solved by statics.simply supportedstatics alonesag 40.0propped at one endneeds stiffnesssag 22.5hog 40.0built in at both endsneeds stiffnesssag 13.3hog 26.7the load never changes; only what is holding the endsthe built-in case peaks at two-thirds of the simple span's moment
Fig. 2 The propped cantilever, which is the smallest interesting redundant structure. Its reactions cannot be found from statics: three unknowns, two useful equations, and the missing information supplied by the condition that the propped end does not move. That condition is the entry point for everything in this essay — it is a statement about a displacement, and a displacement is something a settlement can change.

The moments are proportional to EI

Here is the result that makes settlement genuinely counter-intuitive, and it is worth stating baldly:

MsettlementEIδM_{\text{settlement}} \propto EI \delta

A load-induced moment does not contain EIEI at all — for a determinate structure it is pure statics, and for a redundant one the EIEI terms cancel between spans of the same section. A settlement-induced moment is directly proportional to it. Double the beam’s stiffness and the settlement moments double, with the load moments unchanged.

This inverts the usual relationship between stiffness and safety. A stiffer structure deflects less under load and is therefore better; a stiffer structure resists imposed movement harder and is therefore worse. Which effect matters depends entirely on whether the action in question is a force or a displacement, and the two kinds of action live in the same structure at the same time.

3 continuous spans against 3 simple onesThe bending moment in a continuous beam whose support 1 has settled by 0.01. Three curves: the moment the load causes, the moment the settlement causes on its own — dashed, peaking at 146.9, and in equilibrium with no applied load at all — and their sum, which is what the beam carries, peaking at 122.5 against 24.5 without the settlement. The settlement field is proportional to EI: a stiffer beam is punished harder for the same movement, which is the opposite of every intuition load-carrying gives.this support 0.01 lowmoment19.6 sagging24.5 hogging30.6 if the spans were simplereactions 14.0 38.5 38.5 14.0 — the inner supports carry far more than a sharethe continuous case needed stiffness; the comparison did not
Fig. 3 The same beam and the same settlement with the flexural stiffness doubled. The load moments are identical — the load does not care about EI — and the settlement moments have doubled exactly. Every intuition built on load-carrying says the second beam is the better one, and for this action it is twice as badly affected.

The proportionality is exact and the figures verify it: doubling EIEI multiplies the settlement field by 2.0000, which is the check the generator is held to.

Which free body produced the number

The beam is three 7-metre spans, uniformly loaded at 5 per metre, with the second support pushed down 10 mm.

The settlement field is computed by superposition rather than by teaching the solver about prescribed displacements, and the argument is worth following because it is the standard way this class of problem is handled.

Release the vertical restraint at the settled support, leaving a two-span beam with a free point in the middle. Apply a downward trial force of 1 there and solve; the point deflects by some amount dd per unit force, which is a flexibility coefficient. The force that produces exactly 10 mm of deflection is then F=0.010/dF = 0.010/d, and because the system is linear, every moment in the structure under that force is the moment under the unit force scaled by the same factor.

For this beam that force comes out at 28.0, and the resulting moment field peaks at 73.5 — against a load-induced peak of 24.5. The free body behind the whole calculation is the released structure, and the released structure is determinate: what compatibility supplies is the single number that makes the released displacement match the imposed one.

The check available on it is that the settlement field must be in equilibrium with nothing. Set the load to zero and the beam still has a complete bending-moment diagram, with reactions at every support that sum to zero vertically and to zero in moment. That is a self-equilibrating stress field, and it is the same object as a state of self-stress in a redundant truss or a residual stress in a rolled section.

The assumption the figure rests on is that the beam remains elastic and the settlement is instantaneous. Both matter. A settlement that occurs over years is partly relaxed by creep in a concrete beam, sometimes by most of it; and a beam that yields locally sheds the settlement moment entirely, which is the argument the next section is about.

How big a settlement has to be to matter

The 10 mm in the figures produces settlement moments three times the load moments, which sounds like a designed-for-failure. The scaling explains why it is not quite as bad as that, and where the real threshold sits.

The settlement moment goes as EIδ/L2EI\delta/L^2 and the load moment as wL2wL^2, so the ratio between them goes as EIδ/wL4EI\delta/wL^4. The fourth power of the span is in the denominator, which is the same L4L^4 that governs deflection under load, and it means the sensitivity to settlement falls very fast as spans get longer. A long-span beam barely notices a support movement; a short stiff one is dominated by it.

That is the practical rule and it is the opposite of what an intuition about “big structures, big problems” would suggest. Settlement is a short-span, stiff-structure problem. Transfer structures, ground beams, stiff shear cores adjacent to flexible frames, and the short end bays of otherwise long-span floors are where it bites — all of them stiff, all of them short, and all of them commonly founded differently from what they connect to.

3 continuous spans against 3 simple onesThe bending moment in a continuous beam whose support 1 has settled by 0.01. Three curves: the moment the load causes, the moment the settlement causes on its own — dashed, peaking at 225.0, and in equilibrium with no applied load at all — and their sum, which is what the beam carries, peaking at 217.0 against 8.0 without the settlement. The settlement field is proportional to EI: a stiffer beam is punished harder for the same movement, which is the opposite of every intuition load-carrying gives.this support 0.01 lowmoment6.4 sagging8.0 hogging10.0 if the spans were simplereactions 8.0 22.0 22.0 8.0 — the inner supports carry far more than a sharethe continuous case needed stiffness; the comparison did not
Fig. 4 The same settlement and the same stiffness on spans of four metres rather than seven. The load moments fall as the square of the span and the settlement moments rise as its inverse square, so the ratio between them moves by the fourth power — and the settlement field now peaks at 225 against a load field of 8. Nothing about the ground changed; only the span it was asked to support.

What makes it survivable

The tone of this essay so far has been alarming, and the practice is not. Buildings settle differentially all the time and the great majority are unaffected. Three reasons, and they are the same three that make every imposed-deformation problem tolerable.

It is self-equilibrating. The settlement moments have no net resultant. They cannot cause a collapse mechanism on their own, because a mechanism requires work to be done by external loads and there are none.

It sheds when anything yields. The settlement moment exists because the structure is forced into a curvature. Let a section yield and the curvature is accommodated plastically at a constant moment; the moment stops growing and, as the rest of the structure redistributes, falls away. This is why plastic analysis ignores settlement entirely — at the collapse limit state it has gone, and the collapse load of a ductile structure is genuinely independent of how its supports have moved. That is one of the more remarkable results in the subject and it is a direct consequence of the upper-bound theorem.

It relaxes with time. Concrete creeps, soil consolidates slowly enough that much of the movement occurs during construction while the structure is still being adjusted, and steel connections slip. The sequence matters as much as the total: settlement that happens before a floor is cast is settlement the floor never experiences, which is why construction sequence appears in the calculation at all and why a structure’s history is part of its state.

The residue of concern is therefore in three specific places: at serviceability, where cracking and finishes care about the moment now rather than at collapse; in brittle structures, which cannot shed; and in prestressed or precast structures, where the design is finely balanced and a redistribution of reactions can uplift a support.

Which limit arrives firstUtilisation of the strength limit and of the deflection limit, against span. Strength grows as the square of the span and deflection as the fourth power, so the two cross — and past the crossing a beam is sized by how far it moves rather than by what it can carry.0.60.811.21.41.61.8200.511.5span, relative to the firstthey cross heredeflection runs out at 1.40strength runs out at 1.54the limitstrengthdeflection
Fig. 5 The two limit states plotted against span, and the reason settlement is a serviceability problem rather than a strength one. Strength has a plastic reserve that imposed deformations cannot exhaust; serviceability has none, because a crack that has opened has opened. Any action that yields away at the ultimate limit state and persists at the serviceability one belongs on the lower curve.

The same argument, four other actions

Settlement is the clearest member of a family, and every member behaves identically because the mechanism is the same: a deformation imposed on a structure that is not free to accommodate it.

Temperature. The load path for a temperature action is the restraint rather than the ground: a restrained member that is heated cannot expand, so it develops a force EAαΔTEA\alpha\Delta T — proportional to stiffness, unrelated to load, and capable of being very large indeed. A 30 metre restrained steel member at 30 degrees of temperature change carries a stress of about 70 N/mm² whatever its size.

Shrinkage. Concrete shrinks and its reinforcement does not, so the bars restrain the concrete and put it into tension with no external action at all.

Prestress. The same phenomenon used deliberately: a deformation imposed on the structure to create a stress field chosen in advance. In a redundant structure this produces secondary moments — the “parasitic” moments — which are precisely settlement moments generated on purpose, and which have to be computed by the same superposition.

Lack of fit. A member fabricated 5 mm too short and forced into place in a redundant frame produces a complete self-equilibrating force system before the structure has been loaded.

Maxwell's reciprocal theoremA load at one point and the deflection it causes at another, against the same load moved to the second point and the deflection read at the first. Both integrals return 63.7501, and neither calculation was told about the other. The two deflected shapes are entirely different; the two readings are identical.10 at 3δ at B = 63.75010 at 6δ at A = 63.750the shapes have nothing in commonand the two readings agree to 1e-14which is why an influence line can be measured by pushing the structure where it is easy to push
Fig. 6 Maxwell’s reciprocal theorem, which is the symmetry that makes the superposition calculation possible. The deflection at A due to a load at B equals the deflection at B due to the same load at A — so the flexibility matrix is symmetric, and the single coefficient needed to scale the settlement case is available from either direction. Every imposed-deformation calculation in this essay runs on that symmetry.

Where the model stops

Linear elastic. Everything superposes only because the structure is linear. Once anything yields or cracks, the load case and the settlement case interact and cannot be added.

Instantaneous. Real settlement is a time history, and the structure’s response to it depends on the creep occurring over the same period. For concrete the effective moments can be half the elastic prediction or less.

Known settlement. The calculation takes 10 mm as given, and the number is the least reliable quantity in the whole exercise. Everything downstream of it is computed to four figures from an input known to perhaps one, which is a common and slightly absurd shape for a structural calculation to have — and the correct response is not more precision in the analysis but a check of what happens across the plausible range. Predicting the actual differential settlement of a foundation is a geotechnical problem of considerably lower precision than anything in this essay, and the honest treatment is usually a range rather than a value.

Elastic supports throughout the rest of the structure. The calculation moves one support and holds the others exactly. Real foundations are all springs, so a settlement at one is accompanied by smaller ones everywhere else, and the differential — which is what matters — is smaller than the absolute movement by however much the others follow.

One direction. Only vertical movement is considered. Rotation of a footing, or horizontal spread — which is what an arch fears most — has the same character and different arithmetic.

The figures share a limitation, and it is the standard one for anything about deflection: the settlement is drawn at a scale that makes it visible, and it is 10 mm on a 21 metre beam. Drawn to scale the settled support would be a fifth of the thickness of the line representing the beam, and the deflected shape would be indistinguishable from a straight line. The moments the figure reports are real and the geometry it draws them on is exaggerated by a factor of several hundred.

The generalisation

The division that organises all of this is between actions that are forces and actions that are displacements, and it deserves to be a habit rather than a fact.

A force action produces effects proportional to the force and independent of stiffness. A displacement action produces effects proportional to stiffness and independent of any force. Load, self-weight, wind and snow are forces. Settlement, temperature, shrinkage, creep, prestress and lack of fit are displacements. The two families require opposite instincts: to resist a force, add stiffness; to survive a displacement, remove it.

That is why an expansion joint is a reduction in structure, and why articulating a long building into short independent blocks is a stability decision made in reverse. It is why a three-pinned arch is used where the abutments are doubtful: the hinges make it determinate, and a determinate structure cannot feel a settlement at all. Choosing determinacy is choosing insensitivity, and it is bought by giving up the robustness redundancy provides — the alternative load paths that let a continuous beam survive the loss of something a determinate one could not.

There is no free position on that trade, and the interesting engineering is in noticing that the choice is being made. A designer who adds a support to reduce a span has also added a sensitivity to that support’s foundation, and a designer who makes a frame continuous for robustness has made it responsive to temperature. Neither is wrong; both are decisions, and both are frequently made without being noticed.

Navier set out the analysis of redundant structures in 1826, and the settlement problem was well understood by the 1860s — Clapeyron’s three-moment equation handles it directly with a settlement term. What arrived later was the temperament: nineteenth-century practice tended to design out indeterminacy where foundations were uncertain, using hinges liberally, and the modern preference for continuity is a consequence of welding, of better foundation engineering, and of a plastic theory that showed the settlement moments disappear at collapse.

The ladder from here

Later rungs on this anchor: temperature and the restrained member, where the same argument has a different constant. Prestress secondary moments and the concordant profile that eliminates them. Lack of fit and the deliberate use of it to precamber a truss. Creep relaxation of imposed-deformation effects. Foundation stiffness as a spring rather than a rigid support, which is what a real analysis does and which converts settlement from an imposed displacement into a soil-structure interaction. And the robustness argument for redundancy, which is the counterweight to everything here and is the reason continuity is the default despite all of it.

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CompatibilityContinuityIndeterminacyMoment redistributionReaction distributionSelf equilibratingStiffnessSupport settlement