Equilibrium

The envelope is not a structure

A continuous beam whose imposed load may sit on any span has eight load cases, and every one of them is a genuine state of equilibrium. The curve the design is made against is not one of them — it is assembled from different cases at different stations, and it fails the identity all eight satisfy exactly.

Assumes The worst place to stand, The moment over the support, and what it buys and The load a beam is given is a decision.

A three-span continuous beam carries a permanent load that is always there and an imposed load that may or may not be. The imposed load is a use of the building — people, storage, a plant room — and it sits on whichever spans happen to be occupied.

That gives eight arrangements: each span loaded or not. Every one of them is a real state of the structure and every one is in equilibrium. The beam has to be designed for all of them at once, and the way that is done is to take the greatest sagging moment and the greatest hogging moment at every station over all eight, and design for those.

The result is called an envelope, it is drawn as a pair of curves, and it looks exactly like a bending-moment diagram. It is not one. Nothing produces it, nothing is in equilibrium with it, and the identity that every one of the eight satisfies exactly, it fails by nearly a quarter.

The envelope is not a state of the structureEvery arrangement of the imposed load on three spans — 8 of them, since each span is loaded or not — drawn faintly, with the greatest sagging and greatest hogging at each station drawn over them. Each faint curve is a real state of equilibrium and satisfies the free-moment identity exactly: mid-span ordinate minus the mean of the end moments is wL²/8, to 0e+0 of it. The envelope satisfies it nowhere, missing by up to 23% — because it is assembled from different load cases at different stations and no arrangement of load produces it. seven of the 8 arrangements are needed to build it; the rest never govern anywhere.024681012141618202224-200-100100200distance along the beam (m)bending moment (kNm, sagging up)the sagging envelopethe hogging envelopeeach case exact to 0e+0 · the envelope out by 23%
Fig. 1 All eight arrangements drawn faintly, with the greatest sagging and greatest hogging at each station drawn over them. The heavy curves touch a different faint one at different stations, which is the whole of what an envelope is — and the whole of why it is not a diagram.

Which free body produced the number

Take one span out of the beam with whatever moments the neighbouring spans apply at its ends.

The moment anywhere in it is the free moment of a simply supported span carrying that span’s own load, plus the straight line joining the two end values. At mid-span that gives an identity that holds for any end moments whatever:

MmidMA+MB2=wL28M_{mid} - \frac{M_A + M_B}{2} = \frac{wL^2}{8}

It is statics, it contains no stiffness, and it is true for every arrangement of load on every other span, because everything those spans do arrives here as MAM_A and MBM_B and nothing else.

Run it on all eight cases: the residual is machine zero in every one. Run it on the envelope, taking the sagging envelope at mid-span and the hogging envelope at the two supports, and the middle span misses by 23 per cent.

The reason is not subtle once stated. The mid-span ordinate of the envelope comes from the case with that span loaded and its neighbours empty; the support ordinates come from cases with the neighbours loaded. They are ordinates of different beams.

3 continuous spans against 3 simple onesThe bending moment in a continuous beam, solved by the stiffness method, drawn over the moment in the same spans made simply supported. The peak sagging moment falls from 280.0 to 179.2, and a hogging moment of 224.0 appears over the supports where there was none.moment179.2 sagging224.0 hogging280.0 if the spans were simplereactions 112.0 308.0 308.0 112.0 — the inner supports carry far more than a sharethe continuous case needed stiffness; the comparison did not
Fig. 2 One arrangement, drawn properly — every span loaded, which is the case the envelope is least like. The continuous solution against the simple one: the sagging peak falls and a hogging moment appears where there was none. Each of the eight faint curves on the first figure is one of these.

Which arrangement does what

The two patterns that matter are easy to state and worth deriving rather than remembering.

To maximise the sagging moment in a span, load that span and leave its neighbours empty — then load the next-but-one, and so on. A loaded neighbour puts hogging moment into the shared support, which pulls the whole diagram of the span under consideration downward. An empty neighbour offers the least restraint it can. The pattern that follows is alternate spans, and on this beam it raises the first span’s sagging peak from 179 to 199 kNm: 11 per cent above loading everything.

To maximise the hogging moment over a support, load both spans adjacent to it and leave the rest. Both contribute hogging at that support; a loaded third span puts sagging curvature into the second and relieves it. On this beam the adjacent pattern gives 240 kNm against 224 for the all-loaded case: 7 per cent above.

Neither maximum is produced by the arrangement carrying the most load. That is the counter-intuitive part, and it is a direct consequence of continuity: a load on one span produces moments of both signs in its neighbours, so adding load somewhere can reduce an effect somewhere else.

Influence line for the bending moment at x = 3The bending moment at one fixed station, plotted against the position of a unit load walking across the span. The beam was re-solved at 301 load positions. The worst position is x = 3.00, giving 2.100.the station being watched, x = 3unit load, at its worst position2.100shaded: where a spread load must stand to make this quantity worstthe horizontal axis is where the load is, not where the beam is cut
Fig. 3 The general tool for this question. An influence line is the value of one effect as a unit load walks the structure; where it is positive, load helps the effect, and where it is negative, load reduces it. Pattern loading is the influence line’s answer for a load that arrives in whole-span blocks rather than as a point.

Seven of the eight are needed

A natural question is how many of the arrangements actually matter. On these three spans, seven of the eight appear somewhere on the envelope. The only one that never governs anywhere is the empty case — and it would govern if the imposed load could act upward, or if there were a permanent action of the opposite sign anywhere in the problem.

On four spans it is ten of sixteen; on five spans, sixteen of thirty-two. The count grows, and so does the number of arrangements that never govern — which is what makes the practical rules worth having, because the alternative is 2n2^n analyses.

The rules used in practice — load all spans; load alternate spans; load adjacent pairs — are not an approximation to the full set. They are a selection of it, chosen because between them they contain the case that governs each effect. The envelope built from three rules and the envelope built from all 2n2^n arrangements agree at every station where a design number is taken.

The answer arrives in instalmentsThe hogging moment at support 1 of a three-span beam, cycle by cycle. It starts at the fixed-end moment of 186.7 kNm — the value with every joint clamped — and settles at 224.0 kNm against an exact 224.0. The error falls by about a factor of four per cycle: 49.00, 12.25, 6.84, 2.07 kNm after one, two, three and four. Two cycles is an engineering answer and nobody had to invert anything.012345678050100150200250cycles of distributionmoment at the support (kNm)exact: 224.0all joints clamped
Fig. 4 How the eight cases were solved before anybody could solve eight of them. Hardy Cross’s method distributes an out-of-balance moment around a joint and iterates, and its cost is linear in the number of load cases. Pattern loading is the reason that mattered: a designer was not solving one beam but eight.

Why the envelope is used anyway

Nothing above is an argument against the envelope. It is the correct design object, and the reason is the lower-bound theorem again.

A section provided for the envelope is a section that can carry every one of the eight cases, because at every station its capacity is at least what any of them demands. That is all a design has to establish. That no single case produces the envelope is irrelevant to the safety of the beam — the beam only ever experiences one case at a time.

What the envelope must not be used for is anything requiring a state. Three examples, all of them mistakes that get made:

Deflections. The deflected shape under the envelope is meaningless; the deflection has to come from whichever arrangement maximises it, which is generally alternate spans.

Reactions. Adding the envelope’s shears at a support gives a reaction no case produces, and column design uses reactions.

Redistribution. Moving moment from a support to a span requires equilibrium to be maintained, and it can only be done to a diagram that has it. Redistributing an envelope is a category error; the redistribution has to be applied case by case and the envelope taken afterwards.

Which limit arrives firstUtilisation of the strength limit and of the deflection limit, against span. Strength grows as the square of the span and deflection as the fourth power, so the two cross — and past the crossing a beam is sized by how far it moves rather than by what it can carry.0.60.811.21.41.61.8200.511.5span, relative to the firstthey cross heredeflection runs out at 1.40strength runs out at 1.54the limitstrengthdeflection
Fig. 5 Two limits crossing, and the question of which one the arrangement is being chosen for. The pattern that governs strength at a support is not the pattern that governs deflection in a span, and neither is the pattern that governs the reaction on a column. An envelope answers the first and hides the other two.

The load that is not all imposed

Everything so far has treated the permanent load as fixed. It is not quite, and the way it is handled is the second half of the subject.

The permanent load is also uncertain — a screed thickness, a partition allowance, a services load — and its uncertainty acts in both directions. Where it opposes the effect being maximised, its minimum credible value is the dangerous one. So the codes give permanent actions two partial factors, a large one and a small one, and require the small one on spans where the load relieves.

On a continuous beam that produces a further subdivision of every arrangement: the loaded spans get the full factored permanent load and the unloaded ones get the reduced value. It doubles the arithmetic and it moves the answers by a few per cent, and it is the same idea as the empty-jib case for a counterweight — a permanent action that helps is a permanent action whose minimum matters.

A triangular load and the force that replaces itA triangular distributed load with its resultant computed by integration: an area of 24.0 acting at 5.33 from the left. The two moment diagrams below show what the substitution costs — the reactions are identical and the peak moment is not.resultant 24.0at x = 5.33, the centroid of the areamomentspread: 24.6replaced: 42.7reactions agree exactly (8.00 and 8.00); the peak moment does not
Fig. 6 What “the load” is before any of this starts. Every arrangement above treats the imposed load as a uniform intensity that is either present or absent over a whole span. Real occupancy is neither uniform nor span-shaped, and the block pattern is a convention chosen to make the enumeration finite.

Where the arrangement stops being a choice

Pattern loading applies to loads that can be absent. Several important actions cannot, and the distinction is worth drawing sharply.

A wind load is not patterned span by span; it is a single action with a direction, and its arrangements are directions rather than subsets.

A temperature effect acts on the whole structure at once, and its magnitude rather than its position is the variable.

A settlement is an imposed deformation whose arrangement is which support moved, which is a different enumeration entirely and one where a single support settling is usually worse than all of them settling together.

And a moving load — a train, a crane, a vehicle — is not a subset at all but a continuum of positions, which is the influence line’s own problem and needs a different tool.

The common thread is that “the worst case” is a search over a set, and the shape of the set is decided by the physics of the action rather than by anything about the structure.

Where a beam's load comes fromA 8 × 6 m panel carrying 5 kN/m², divided at 45° from the corners. The long beams take a trapezoid of 15.0 m² each and the short beams a triangle of 9.0 m²; the four areas sum to 48.0 m², which is the panel, so no load has been invented or lost. The line loads quoted are the uniform equivalents; the real distributions peak at 15.00 kN/m at midspan.15.0 m²9.38 kN/m15.0 m²9.38 kN/m9.0 m²7.50 kN/m9.0 m²7.50 kN/m8 m6 m48.0 m² divided, 48.0 m² of panel — the division closes
Fig. 7 Where the load on a beam came from in the first place. The arrangement question exists one level up too: which bays of a floor are occupied, and the reduction factors applied to a column carrying many floors are an admission that not all of them are loaded at once.

Two spans, and the smallest example that shows it

Three spans is the smallest beam on which the alternate and adjacent patterns are genuinely different. Two spans is smaller still and is worth doing by hand, because everything above appears in it with nothing to hide behind.

Two equal spans, permanent load on both, imposed load available on either. Four arrangements: neither, first, second, both.

  • Both loaded gives the largest support moment, (g+q)L2/8(g+q)L^2/8, and a span moment of 9(g+q)L2/1289(g+q)L^2/128.
  • One loaded gives a smaller support moment — the unloaded span contributes only its permanent share — and a larger span moment in the loaded span, because the support is holding it back less.
  • Neither gives the permanent-load diagram, which governs nothing.

So the support is designed from the both-loaded case and each span from its own singly-loaded case, and the envelope is built from three of the four. Draw it and the middle of it is above the both-loaded curve while its support ordinate is on it — which is the 23 per cent discrepancy of the three-span beam, in miniature and unmistakable.

What the two-span case makes obvious is that the discrepancy is not a rounding or a conservatism introduced by the envelope. It is the envelope’s whole content: if every ordinate came from one case, the envelope would be that case and there would be no reason to compute it.

Where the model stops

The spans are equal and the load intensity is the same on each. Unequal spans change which pattern governs where, and can make a pattern that never governs on a regular beam the critical one — in particular where a short end span abuts a long interior one.

The beam is elastic and the analysis linear. Superposition is what makes eight separate solves legitimate. A beam that has cracked under one arrangement is a different beam under the next, and its stiffness distribution depends on its history.

And the arrangements are of one variable action. With two — an imposed floor load and a moveable partition load, say — the enumeration is over the product of the two sets, and the combination factors that reduce simultaneous variable actions arrive to keep the result from being absurd.

The arrangement that governs the deflection

Strength is not the only thing the arrangement decides, and the serviceability answer is the one most often taken from the wrong case.

The deflection of a span is largest when that span is loaded and its neighbours are not — the same alternate pattern that maximises its sagging moment, and for the same reason: the neighbours’ hogging restraint is what holds the span up. The difference is not small. On these spans the alternate arrangement deflects the outer spans appreciably more than the all-loaded case, and a deflection computed from the all-loaded arrangement is an underestimate of the number that will be measured.

There is a second reason the arrangement matters more for deflection than for strength, and it is about what the check is against. A strength check compares one number with a capacity that has a factor of safety in front of it. A deflection check compares one number with a span over three-hundred-and-sixty, and there is no factor anywhere — so an error of ten per cent in the arrangement is ten per cent of the answer, not ten per cent of a margin.

What the pictures cannot show

The eight faint curves are drawn together, which is the one thing the beam never does. Each is a photograph of a different Tuesday.

Nor can the figure show the reason any of this is more than an exercise, which is that the sagging steel and the hogging steel are different bars in different places. An envelope is not really a curve; it is a set of instructions about where reinforcement stops, and the stations at which two arrangements exchange places are the stations at which a bar has to run past.

A third thing the pictures leave out is the column. Every arrangement produces a set of reactions, and the arrangement that maximises a column’s axial load is not the one that maximises the moment the beam delivers into it — a column at the end of a run of spans gets its largest moment when the adjacent span is loaded and the next is not, which is a case in which its axial load is below the maximum. Designing a column from the beam’s worst reaction and the beam’s worst moment simultaneously is designing it for a case that does not exist, and the penalty is real: on an interaction curve the two extremes are far apart.

The assumption the figure rests on

Each span is either fully loaded or fully empty. That is a convention, and its justification is that partial loading of a span is bracketed by the two cases — which is true for the span’s own moment and not quite true for everything else. A load on half a span produces a slightly different set of end moments than the same total load spread over all of it, and for the support moment the half-span case can be marginally worse. The convention is defended by the margin rather than by the arithmetic, and it survives because the difference is smaller than the uncertainty in the load itself.

Load, shear and moment — a simple spanThe applied load, the shear force it produces and the bending moment that follows, drawn one above another to the same horizontal scale. Shear is the integral of the load and moment is the integral of shear.6 per unit lengthshear18.0moment27.0 at x = 3.00the moment peaks exactly where the shear passes through zero
Fig. 8 The diagram behind every one of the eight, for a load on part of a span. The moment curve’s curvature is the load, so an unloaded span’s diagram is a straight line between its end moments — which is why the faint curves on the envelope figure are straight wherever their span is empty, and why the envelope’s kinks are where a case changes.

The ladder from here

Later rungs on this anchor: the enumeration for two or more variable actions, and the combination factors that keep it finite. Pattern loading on a two-way slab and on a flat slab, where the “spans” are strips in two directions and the count grows quickly. Redistribution applied case by case, and why the envelope of redistributed diagrams is not the redistribution of the envelope. Reaction envelopes, and why a column cannot be designed from a beam’s moment envelope. And the whole question of what an envelope is for, which reaches past this subject into any design made against a set of scenarios rather than a state.

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Bending momentContinuityEnvelopeEquilibriumFree bodyImposed loadIndeterminacyInfluence lineLoad arrangementLoad combinationMoment redistributionPattern loadingPermanent loadServiceabilitySuperposition