Deflection

The addition everything else rests on

Influence lines add, the unit-load method adds, moment distribution adds, load combinations add, and a stiffness matrix is linear by construction. All of it stands on one sentence with three hypotheses in it — and when they fail, two of the failures point in opposite directions.

Assumes Where a deflection comes from, The load that makes itself worse and Stiffer than its cracked section says.

Nearly every method in this collection is an addition. An influence line is added up over the axles of a train. The unit-load method sums a product over members. Moment distribution passes corrections round a frame and adds them. A load combination adds actions with factors on them; a prestress is read as a load and added to the applied one; a stiffness matrix multiplies, which is addition in a different notation.

All of it rests on one sentence: the response to a sum of loads is the sum of the responses. That sentence is a theorem, not an axiom, and it has three hypotheses.

Two answers added, and the answer to the two together, drawn on top of each other. A 8 m beam under a 60 kN point load at mid-span (152.38 mm), under 12 kN/m of uniform load (152.38 mm), and under both at once (304.76 mm). The sum of the first two is 304.76 mm, and the residual between it and the third is zero — not small, zero, to the last bit of the arithmetic. That exactness is not a numerical accident: the governing equation is linear in the load, so the response is a linear operator applied to it, and a linear operator distributes over addition by definition. Everything on this site that adds is standing on that one line.
Fig. 1 An 8 m beam under a 60 kN point load (152.38 mm), under 12 kN/m of uniform load (152.38 mm), and under both at once (304.76 mm). The sum of the first two is 304.76 and the residual against the third is zero — not small, zero, to the last bit of the arithmetic. The two shapes are different and the sum is exact anyway.

Why it is exact rather than close

The exactness is worth a moment, because it is the difference between a theorem and a rule of thumb.

The governing equation of a beam is EIy=qEI\,y'''' = q. The operator on the left does not contain yy or qq anywhere except linearly, so if y1y_1 solves it for q1q_1 and y2y_2 for q2q_2, then y1+y2y_1 + y_2 solves it for q1+q2q_1 + q_2 by inspection. The boundary conditions are homogeneous — y=0y = 0 at a support, whatever the load — so they add too.

A linear operator distributes over addition by definition, and that is the whole proof. The residual is not small because the numbers are nice; it is zero because the statement is an identity.

That is why superposition is not on the same footing as the approximations elsewhere on this site. Plane sections staying plane is approximately true and the error can be estimated. A shear stress that is uniform across a thin wall is approximately true and gets worse as the wall thickens. Superposition is exactly true, or it is not available at all. There is no regime in which it is a few per cent out.

The three hypotheses

  1. The material is linear elastic. Stiffness must not depend on the load.
  2. The geometry does not change enough to matter. Equilibrium must be written on the undeformed shape.
  3. The boundary conditions do not depend on the load. What is supporting the structure must be the same in every case.

Each of them can fail, and this site has essays about all three failing — but never with the additivity error measured. Here it is, on one beam.

Three ways for the addition to stop working, and no safe direction. How far wrong it is to compute two load cases separately and add them, for the same beam under four sets of hypotheses. Under all three of superposition's conditions the residual is zero to machine precision. Break the material's linearity — let the section crack, so its stiffness depends on the total moment — and the sum is 62 per cent SMALLER than the truth. Break the boundary conditions — put a support a gap away, so whether the beam is touching it depends on the load — and the sum is 37 per cent LARGER. The two errors point opposite ways, so there is no direction to lean in and no version of the shortcut that is safe by construction. Second-order geometry costs only 0.32 per cent here, because the two load cases happen to have very nearly the same amplification.
Fig. 2 How far wrong it is to compute the same two load cases separately and add them, under four sets of hypotheses. Under all three the residual is zero. Break the material’s linearity and the sum is 62 per cent too small; break the boundary conditions and it is 37 per cent too large; break the geometry and it is 0.32 per cent too large. The first two point opposite ways.

Cracking, which is the big one

A reinforced concrete section’s stiffness depends on how far past cracking it is. Branson’s interpolation makes that explicit: the effective II falls from the uncracked value toward the cracked one as (Mcr/M)3(M_{cr}/M)^3, so it is a function of the total moment.

Compute the point load alone and the section sees a moment of 120 kNm, giving an effective stiffness of 0.543 of the gross. Compute the uniform load alone: 96 kNm, and 0.726. Compute them together: 216 kNm, and 0.383.

Each case computed alone is riding on a stiffer beam than the pair is, so:

deflection
point load alone 280.8 mm
uniform load alone 209.8 mm
the sum of those 490.7 mm
both loads together 795.7 mm

The sum is 62 per cent short of the truth, and it is short in the unsafe direction.

The beam is stiffer than its cracked section and softer than its gross one. Moment against mid-span deflection for a 300 × 550 mm beam spanning 8.0 m, with the two bounds it lies between. The uncracked line is what the gross transformed section gives; the cracked line is what the section at a crack gives; and the curve between them is the member, because between the cracks the concrete is still carrying tension and the average curvature is not either section's. At the service load the deflection is 34.2 mm — span over 234 — against 8.7 uncracked and 37.4 fully cracked, a factor of 4.30 between the bounds. The interpolation ζ = 1 − β(M_cr/M)² sits it 89 per cent of the way across, and β falls from one to a half under sustained or repeated load because the bond that does the dragging deteriorates.
Fig. 3 Where the nonlinearity comes from. A cracked member is stiffer than its cracked section, because the concrete between cracks is still carrying tension — and how much stiffer depends on how far past cracking the member is. A stiffness that is a function of the load is exactly what hypothesis 1 forbids.

This is why deflection checks on concrete are done at the service load combination as a whole and never by adding cases, and it is why the quasi-permanent combination is specified rather than left to the engineer: which loads are on at the same time changes the stiffness, and therefore changes the answer to all of them.

The gap, which points the other way

Put a support under the beam with a small clearance under it, so the beam is a cantilever until it lands and a propped one afterwards. That is hypothesis 3 failing.

For a 4 m cantilever with a 120 mm gap: the uniform load alone deflects 91.4 mm and never touches. The point load alone deflects past the gap, lands, and finishes at 131.5 mm. Both together land earlier and finish at 139.9 mm — against a sum of 223.0 mm.

The sum is 37 per cent too large, and it is too large because the case that was never touching had a much softer structure than the case that was. Adding the two adds a soft answer to a stiff one and produces a structure that is neither.

A cantilever and its fixing. A free body: the beam cut away from everything it touches, with the forces that were doing the touching drawn on it. The reactions are computed from the loads, so their arrows are to scale relative to each other.
Fig. 4 The support that only exists sometimes is a boundary condition that depends on the load, and it appears far more often than the phrase suggests: a bearing that lifts off under wind, a prop struck part way through a pour, a slab resting on a wall it is not connected to, a base plate whose bolts go into tension only past a certain moment. Each of them is a structure with two configurations and a load that decides which.

Second order, which is the small one and the famous one

This is the failure everybody names and it is the least of the three here.

The usual treatment amplifies the first-order deflection by 1/(1N/NE)1/(1 - N/N_E). That factor is a constant for a given axial load, so multiplying by it is a linear operation and a superposition check made with it comes out exact — proving nothing.

The real nonlinearity is subtler. The exact beam-column solutions are

δP=P2Nk(tanuu),δw=wNk2(secu1)wL28N,\delta_P = \frac{P}{2Nk}\left(\tan u - u\right), \qquad \delta_w = \frac{w}{Nk^2}\left(\sec u - 1\right) - \frac{wL^2}{8N},

with u=kL/2u = kL/2 and k=N/EIk = \sqrt{N/EI}, and they are different functions. Their amplifications at N/NE=0.62N/N_E = 0.62 come out at 2.5925 and 2.6208 — the uniform load is amplified slightly more, because its deflected shape is slightly closer to the buckling half-sine than the point load’s is.

Using one factor for the combination therefore gets it wrong by 0.32 per cent. Small, and it grows: at N/NE=0.9N/N_E = 0.9 it is several per cent, and the direction is that the single-factor answer is too small.

The load that makes itself worse. The amplification of a deflection against the ratio of applied load to buckling load. A structure at half its buckling load deflects twice as far as first-order analysis predicts, and the curve runs away well before the load is reached.
Fig. 5 Where the amplifier comes from, and why it is so nearly right. The amplification depends on how close the deflected shape is to the buckling mode, and every ordinary deflected shape is close to it — which is why one factor works for everything and why the residual it leaves is a fraction of a per cent rather than a fraction.

What is really being assumed when a designer adds

Superposition’s practical importance is not in deflections. It is in the envelope, and there the assumption being made is a different one and larger.

The envelope is not a state of the structure. Every arrangement of the imposed load on three spans — 8 of them, since each span is loaded or not — drawn faintly, with the greatest sagging and greatest hogging at each station drawn over them. Each faint curve is a real state of equilibrium and satisfies the free-moment identity exactly: mid-span ordinate minus the mean of the end moments is wL²/8, to 0e+0 of it. The envelope satisfies it nowhere, missing by up to 23% — because it is assembled from different load cases at different stations and no arrangement of load produces it. seven of the 8 arrangements are needed to build it; the rest never govern anywhere.
Fig. 6 The envelope is not a structure — it is assembled from different load cases at different stations, so no single equilibrium state produces it. Superposition is what licenses building it: each arrangement is computed alone and the results are combined station by station. That licence holds exactly for a linear frame and fails for a cracking one, and every reinforced concrete envelope in the world is drawn as though it did not.

The chain is worth spelling out because each link is usually invisible:

  • a design is checked against a combination of actions;
  • the combination’s effects are found by adding the effects of the actions;
  • which requires the structure’s response to be linear;
  • which requires its stiffness not to depend on what is on it;
  • which for a cracked concrete member it does.

Every step of that is standard practice, and the fourth is false for most of the world’s buildings. What saves it is that the forces in a statically determinate member do not depend on stiffness at all, and that in an indeterminate one the redistribution caused by unequal cracking is usually small — but “usually small” is a different kind of claim from “exactly zero”, and the two are routinely conflated.

The one place it is not optional

There is a use of superposition on which the whole practice of structural design depends and which has no alternative, and it is worth separating from the deflection arithmetic above.

Design is done against combinations, and combinations are enumerated. A building has permanent load, imposed load in several patterns, wind from four directions, snow, thermal actions and an accidental case; the number of combinations runs to dozens and sometimes hundreds. Every one of them is analysed by taking the results of a handful of unit analyses — dead, imposed, wind X, wind Y — and adding them with factors.

If that were not legitimate, each combination would need its own full analysis of the structure, and the number of analyses would be the number of combinations rather than the number of actions. For a large model that is the difference between an afternoon and a fortnight.

The largest action is not the governing one. Utilisation of three load combinations against the size of the variable action, each checked against the strength that belongs to its own shortest-duration load — 0.60 of the short-term resistance for a permanent case, 0.80 for a medium one, 0.90 for a short one. The lines cross. Below a variable action of about 52 units the permanent-only case governs even though it is by far the smallest load on the structure, because it is checked against the smallest strength. At the case drawn the governing combination is permanent + wind at 0.888, and the combination with the largest action is permanent + wind. A duration factor is not a safety margin: it moves which arithmetic decides the member, and it can hand the decision to the load nobody thought was severe.
Fig. 7 Which actions can be on at the same time is a separate question again, and it is answered by convention rather than by mechanics. What superposition supplies is only the arithmetic once the set has been chosen; it has no opinion about whether a full snow load and a full wind can arrive together.

So the licence is load-bearing in the most literal sense. It is also the one nobody re-derives, because the alternative is unthinkable rather than merely expensive.

Which free body produced the number

None. Superposition is not a statement about a free body; it is a statement about an operator, and it is proved by inspecting the differential equation rather than by cutting anything.

That makes it unlike every other result in this collection, and it is why the failures are so hard to notice. A free body that is wrong is usually visibly wrong — a force missing, a support in the wrong place. An operator that is not linear looks exactly like one that is, and the only symptom is that two calculations which ought to agree do not.

What breaks it in practice, ranked

The four rows on the chart are one beam’s illustration. Ranked by how often each one actually bites in a design office, the order is different and worth stating:

1. Cracking, and every other load-dependent stiffness. Reinforced concrete, composite decks with partial interaction, timber connections that slip, bolted joints before they slip. Anything whose stiffness is a function of what is on it.

2. Boundary conditions that switch. A bearing that lifts off, a base plate whose bolts take tension only past a moment, a gap at a movement joint that closes, a slab that is resting rather than fixed. These are common, they are almost never modelled as switches, and the error is large.

3. Plasticity and history. A hinge that has formed does not un-form, and the response depends on the order the loads arrived in. This is why shakedown is a statement about a sequence rather than about a combination, and why any structure that has yielded has left the linear world permanently.

4. Second-order geometry. The one that gets a clause, a factor and a name, and the smallest of the four for anything a designer would build — because a structure at N/NEN/N_E high enough for the shape effect to matter is a structure that has failed another check first.

Yielding one way makes it easier to yield the other. Mild steel taken to a strain of 0.60% and then pushed back the other way. The stress falls by 550 N/mm² before it yields again, against a yield stress of 275 — the elastic range is twice the yield stress and not once it, which is the Bauschinger effect and is a consequence of the yield surface sliding rather than growing.
Fig. 8 And the fifth, which is the whole subject of a different field: a material with a hysteresis loop has a response that depends on where it has been, not merely on where it is. Superposition needs the response to be a function of the load, and a loop is not a function.

Where the model stops

The four cases are one beam. The residuals measured are for the specific loads, span and section drawn; they are illustrations of a direction and a magnitude, not coefficients anybody should carry away. Change McrM_{cr} and the cracking error moves by tens of per cent.

Branson’s interpolation is itself a fitted curve. A more careful cracked-member calculation integrates the curvature along the span with the stiffness varying station by station — and it gives a different number, though the same sign and roughly the same size.

The gap case is idealised as two stiffnesses. A real beam landing on a support does so progressively, through a contact that starts at a point and grows, and the transition is smooth rather than a switch.

Nothing here is about plasticity. A member with a plastic hinge in it has abandoned superposition entirely and permanently, and the sequence in which the loads were applied now matters — which is a fourth failure, of a different kind, since it makes the response depend on the load’s history and not merely on its total.

And the pictures show only deflections. The forces in a determinate structure superpose whatever the material does, because they come from equilibrium alone. Everything on this page is about the quantities that need a stiffness, which is deflections and the internal forces of indeterminate structures — and the second of those is where it matters most and is drawn least.

The habit worth taking away

There is a single question that catches all four failures and it takes ten seconds to ask.

Does the structure that carries load case B know that load case A is on?

If it does not — if the stiffness, the supports and the geometry it presents to B are the same whether or not A is there — the results add exactly. If it does, they do not, and the size of the error is the size of the difference between the two structures.

That formulation also says where to look for the failure, which a list of hypotheses does not. Cracking makes the beam softer for B when A is on; a gap makes it stiffer; an axial load makes it softer by a little; a hinge makes it a different structure entirely. In every case the question is answered by asking what B’s structure is, and noticing that it has two answers.

The ladder from here

Later rungs on this anchor: reciprocity, which is superposition’s close relative and says something stronger — that the deflection at A from a load at B equals the deflection at B from a load at A, and which needs the same three hypotheses. Load-history dependence in plastic analysis, and why shakedown is a statement about a sequence rather than about a combination. Nonlinear analysis in practice, where the answer is obtained by loading in increments and superposition survives only within each increment. The cracked-frame problem properly solved, with the stiffness of every member updated to the combination being analysed and the whole envelope recomputed for each. And the modelling question this raises and does not answer: if the answer depends on which loads are on at once, what is the right set of combinations to analyse — a question with no structural content and a great deal of consequence.

Named alongside this one

Essays reaching for the same objects. Nobody chose these; they are what the concept index makes visible.

The objects this essay names

Each one links to every other essay that touches it.

Boundary conditionsCrackingInfluence lineLinearityLoad arrangementSecond orderStiffnessSuperposition