Sections and stress

The stress nobody restrained

A bridge deck lying loose on its bearings, with nothing holding it anywhere, develops four newtons per square millimetre when the sun comes out. The stress is not caused by restraint. It is caused by plane sections, and it is invisible to every equilibrium check that could be made on the member.

Assumes Plane sections stay plane, and what the assumption costs, The movement nobody applied and The stress that was there before the load.

Every thermal argument in this collection so far has been about restraint. Heat a member and it wants to grow; stop it and it pushes; let it go and nothing happens. The whole subject seemed to be a question about bearings.

It is not, and the reason is the assumption that runs under every other page here. A section is required to stay plane. The temperature is under no such obligation.

Where the two disagree, the material is stressed — and on a concrete deck with the sun on it the disagreement is worth four newtons per square millimetre, in a member nobody is holding.

Where plane sections stop staying planeStrain across a cut face at four span-to-depth ratios, with the straight line the theory assumes drawn faintly behind. For a slender beam the two coincide; for a beam as deep as its span the real distribution is nothing like a straight line, and beam theory has no claim on it.span ÷ depth = 8plane sections holdspan ÷ depth = 4plane sections holdspan ÷ depth = 2off by 19%span ÷ depth = 1off by 31%the assumption is the theory — everything else is arithmetic on top of it
Fig. 1 The assumption itself, which this whole page is a consequence of. A section stays plane, so its strain is ε0+κy\varepsilon_0 + \kappa y and nothing else — two numbers for a whole cross-section, however complicated the thing that is trying to strain it.

Which free body produced the number

Take the cross-section as the free body, with no external force on it at all.

The temperature at height yy is T(y)T(y), so the material there would like to strain by αT(y)\alpha T(y). It is only allowed to strain by ε0+κy\varepsilon_0 + \kappa y. The stress is EE times the difference:

σ(y)=E(ε0+κyαT(y))\sigma(y) = E\left(\varepsilon_0 + \kappa y - \alpha T(y)\right)

and ε0\varepsilon_0 and κ\kappa are whatever they have to be for that stress to have no resultant. Two conditions, two unknowns:

ε0=1AαTdAκ=1IαTydA\varepsilon_0 = \frac{1}{A}\int \alpha T\,dA \qquad \kappa = \frac{1}{I}\int \alpha T\, y\,dA

which is to say: the mean is the axial strain and the first moment is the curvature, and everything left over is stress.

For the deck drawn — 1.4 m deep, a 3 m slab on a 400 mm web on a bottom flange, with 18 °C at the top face falling away over the top 140 mm — that gives ε0=32\varepsilon_0 = 32 microstrain and κ=6.3×105\kappa = 6.3 \times 10^{-5} per metre. The residual stress field reaches 3.98 N/mm² of compression at the top face and 1.83 of tension 140 mm below it.

Its resultant force is 8×10148 \times 10^{-14} kN and its resultant moment 3×10123 \times 10^{-12} kNm. Those are not small numbers; they are zero, and the fact that they are zero is exactly why no equilibrium check anybody could make on the deck would ever find this stress.

The strain it wants, the strain it is allowed, and the differenceA bridge deck 1.40 m deep with 18 °C at the top face falling away over 10% of the depth. The left curve is the free thermal strain αT(y); the straight line beside it is what a plane section will actually take, ε₀ + κy with ε₀ = 32.0 microstrain and κ = 0.063 per km. The right-hand block is E times the difference, and it reaches -3.98 N/mm² of compression at the surface and 1.83 of tension 140 mm below it. Its resultant force is 8.3e-14 kN and its resultant moment 3.0e-12 kNm, which is what self-equilibrating means: the field is invisible to every equilibrium check that could be made on the member.the sectionstrainfreeplanestress-3.98+1.83resultant force 8.3e-14 kN · resultant moment 3.0e-12 kNmno restraint anywhere, and the member is stressed from end to end
Fig. 2 The three curves, side by side: the strain the temperature wants, the strain a plane section will give it, and EE times the gap. The third is a genuine stress in the material — it cracks concrete, it yields steel, it adds to whatever else is there — and it exists with nothing touching the member.

The linear profile is the exception, and it is the one everybody uses

Put a straight line into the integrals above. A linear profile is ε0+κy\varepsilon_0 + \kappa y divided by α\alpha for some ε0\varepsilon_0 and κ\kappa — so the plane section can follow it exactly, the difference is zero at every fibre, and the stress is zero everywhere.

Measured rather than asserted: with a linear profile the peak self-stress computes to 101410^{-14} N/mm², which is a double-precision zero.

That is why the subject has been about restraint until now. Uniform and linear are the two profiles under which a free member carries no stress, and they are the two profiles every simple treatment uses. Neither is what the sun does.

It moves, or it pushes. Never both, and never neitherA 30 m steel member 30 °C warmer than it was built, in three conditions. Free, it grows 10.8 mm and carries nothing. Held, it moves nothing and carries 75.6 MPa — which is E·α·ΔT and contains neither the length nor the area of the member, so the identical stress arises in a two-metre strut. Held by a spring it does some of each: 3.2 mm of movement and 53.2 MPa, and the split is decided by the spring rather than by the member.free at one end10.8 mmno stressheld at both ends75.6 MPaheld by a spring of 100 kN/mm53.2 MPaE·α·ΔT = 210000 × 12×10⁻⁶ × 30 = 75.6 MPa, at every length
Fig. 3 The restraint picture, which is correct and is about the other half of the problem. Uniform heating of a held member gives EαΔTE\alpha\Delta T with no length in it; uniform heating of a free one gives movement and no stress. Everything on this page happens in a case that figure has no axis for.

Two temperature fields no analysis can tell apart

Here is the sharpest way to put it.

Take the real profile and compute its ε0\varepsilon_0 and κ\kappa. Now construct the straight line with exactly those two: for this deck it runs from +6.28 °C at the top to −2.57 °C at the bottom.

The two profiles produce:

the real profile the straight line
axial strain ε0\varepsilon_0 32.0 µε 32.0 µε
curvature κ\kappa 6.33 × 10⁻⁵ /m 6.33 × 10⁻⁵ /m
camber over 25 m 4.9 mm 4.9 mm
restraint moment if held 283 kNm 283 kNm
peak self-stress 3.98 N/mm² 0

Every quantity a structural analysis computes is identical. The deck moves the same distance, bends by the same amount, pushes on its bearings with the same force and, if it is continuous, generates the same moment over its piers. And one of them cracks the deck soffit and the other does not.

The stress is a measure of how far the temperature profile is from being a straight line, and of nothing else.

Two temperature fields no analysis can tell apartThe temperature through the depth of the deck, and beside it the straight line with exactly the same mean and exactly the same gradient — from 6.28 °C at the top to -2.57 °C at the bottom. The two produce the same axial strain, the same curvature of 0.063 per km, the same 4.9 mm of camber over a 25 m span and the same restraint moment of 283 kNm if the deck is held. The straight one leaves no stress at all. The real one leaves 3.98 N/mm², and the difference between them is the only place it can have come from.510150200400600800100012001400temperature above ambient (°C)height above the soffit (mm)as it isthe straight linewith the samemean and gradientpeak 3.98 N/mm²against nothing at all
Fig. 4 The two fields drawn together. Their means agree, their first moments agree, and the shaded distance between them is the entire cause of a stress field that reaches four newtons per square millimetre.

Why the profile is never straight

Concrete conducts heat badly and stores a great deal of it. The sun heats the top surface over a few hours; the heat diffuses downward at a rate set by the thermal diffusivity of concrete, which is about 0.05 m² per day; and over an afternoon it penetrates a few hundred millimetres.

So the profile through a 1.4 m deck at four o’clock is not a gradient. It is a hot skin over a body that has not yet noticed, and the thinner the skin the further the profile is from a straight line.

The thinner the heated layer, the more stress it leaves behindSelf-equilibrating stress against the depth the heat reaches, at a fixed surface temperature of 18 °C. At the right-hand edge the whole section is heated on a straight line and the stress is **exactly zero** — a plane section can follow a straight profile with no stress at all. Everywhere left of it the profile is bent, the section cannot follow it, and the difference is a stress field with no resultant force and no resultant moment. The surface compression climbs without limit as the layer thins; the tension underneath peaks at 2.84 N/mm² when the heat reaches 24% of the depth, which is about where a summer afternoon puts it.0%20%40%60%80%100%012345depth the heat reaches, as a fraction of the sectionself-equilibrating stress (N/mm²)compression at the facetension below ita straight profileleaves nothing
Fig. 5 The one-parameter family that makes the point. Hold the surface temperature and shrink the depth it reaches: at the right-hand edge the whole section is heated on a straight line and the stress is exactly zero; every value to the left of it is a measure of the bend in the profile. The surface compression climbs without limit as the layer thins, and the tension underneath peaks near a fifth of the depth.

The night-time case is the mirror image and is often worse. The deck radiates to a clear sky, the surface cools below the body, the sign of everything reverses — tension at the top face, where the deck slab is already in tension over a pier, and the two add.

The section’s own shape decides how much

The two integrals that fix ε0\varepsilon_0 and κ\kappa are weighted by width, so a section whose material is not evenly distributed through its depth gets a different answer from a rectangle of the same depth under the same profile.

That matters more than it sounds. The deck here has 3,000 mm of slab in its top 200 mm and 400 mm of web underneath, so the hot layer coincides almost exactly with the widest part of the section — the mean is dragged up and the curvature with it, and both are much larger than a rectangle of the same depth would have given. A box girder with a thin top slab and a heavy bottom flange behaves the other way round.

There is no shortcut here and no coefficient. The profile has to be integrated over the section that exists.

Every strip counts by the square of its distanceA rectangular section divided into equal strips, with each strip's contribution to the second moment of area drawn beside it. The strips are identical in size; only their distance from the neutral axis differs.neutral axiscontribution of each striptotal I = 205.05 × 10⁶the outer strips do almost all of the work
Fig. 6 The same integral the second moment of area is, with temperature in place of yy. Both are first and second moments of the section’s width, and a shape chosen to make one of them large has already decided the other.
Moving the flanges apartThe second moment of area of an I-section against its depth, with the flange and web areas held constant. The growth is close to quadratic, because the parallel-axis term dominates everything the flanges contribute about their own centres.1001502002503000M50M100M150Moverall depth1.0×2.5×4.7×7.7×13.3×20.6×same steel, moved apart
Fig. 7 And the theorem that assembles it from pieces. The thermal integrals decompose the same way — slab, web and bottom flange each contribute their own area times their own mean temperature — which is how the deck’s numbers above were actually got.

Where it actually matters

Four newtons per square millimetre is not a strength problem. On a deck whose concrete has a cylinder strength of 40 it is a tenth of the compression capacity, and no member has ever failed because of it.

It is a cracking problem, and cracking problems are decided by tensile strength, which is about 3 N/mm² for the same concrete. A tension of 1.8 from the thermal field alone is more than half of it, and it is a bonus term added to whatever the load is already doing.

Three places it bites:

The soffit of a deck slab, at night. The cooling profile puts tension at the top and compression at the bottom in the slab, but the same profile through a box girder puts tension in the bottom flange of the box — which is where a prestressed deck’s designer has spent his whole budget keeping the tension out.

The web of a deep girder. The self-equilibrating field is largest where the profile is most curved, which for a heating case is a few hundred millimetres below the top face. On a box girder that is inside the web, where there is generally the least reinforcement.

Anywhere the section changes. The field depends on the section’s own AA and II, so a deck that widens or a web that thickens has a different self-stress field in each part, and the transition between them is a region this model says nothing about.

The neutral axis is wherever the first moment vanishesA 3000 by 1556 section with 6000 mm² of steel at a depth of 1400, carrying 0 kNm after the tension side has cracked. The neutral axis is no longer at mid-depth: it has risen to 178.2 mm from the top, which is where the first moment of the compression zone plus the transformed steel vanishes. The compression is 0.0 N/mm² at the top fibre and the steel carries 0 N/mm²; the resulting couple is 0 kN on a lever arm of 1341 mm, which multiplies back to the 0 kNm applied. The uncracked section would have had 953702×10⁶ mm⁴ against the cracked 63878×10⁶ — a loss of 93% of the stiffness.x = 1786000 mm² of steel, n = 6.5b = 30000.0 N/mm²0 kN in the steelz = 1341C = T = 0 kN · C·z = 0.0 kNm = the applied momentcracked I 63878×10⁶ mm⁴ against uncracked 953702×10⁶ — 93% of the stiffness gone
Fig. 8 Once it has cracked, the whole calculation above is about the wrong section — and it is a self-relieving problem, because a cracked section is more compliant and the same profile leaves less stress in it. The stress that cracks the deck reduces itself in the act.

The history that made it a load case

Self-equilibrating thermal stress was not discovered by anybody looking for it. It arrived with the first generation of long prestressed concrete box girders in the nineteen-sixties, as cracks in places where the calculations said there was compression to spare — soffits of spans that had never carried more than their own weight, webs of boxes at mid-height, the tops of decks over piers.

The measurements that settled it were made by instrumenting real bridges and reading the strain gauges through a day, which is how the standard profiles now in the codes came to be shaped the way they are: a hot skin over a body, with a kink in it, rather than a gradient. The shape is a summary of thermocouple readings and not a solution to anything.

What is worth carrying from that is the order in which it was understood. The stress came first, as cracks; the mechanism came second; and the reason it took so long is that every tool available for finding it — a moment diagram, a reaction, an equilibrium check on any free body at all — is blind to a field with no resultant.

Restraint is a separate question, and it adds

Nothing above needed a bearing. If the deck is restrained — continuous over piers, or built into abutments — the curvature κ\kappa is resisted, and a restraint moment EIκEI\kappa appears on top of everything else.

For this deck EIEI is 8.9 × 10⁶ kNm², so full restraint of the curvature would give 566 kNm and continuity over one pier of a long viaduct gives about half of it — 283 kNm, and stresses of ±0.75\pm 0.75 N/mm² at the extreme fibres.

The important part is that the two effects are additive and independent. The self-equilibrating field depends only on the shape of the profile; the restraint moment depends only on its first moment and on the boundary conditions. A designer who computes one and calls it the thermal effect has computed half the problem, and which half depends on which textbook was open.

Warmer on top: the same two limits, one field alongA 30 m deck 15 °C warmer on top than underneath, over a depth of 1400 mm. Free to move, it takes a curvature of 0.129 per km and lifts 14.5 mm at midspan, carrying no stress at all. Held down, it carries 9 kNm and ±18.9 MPa at the extreme fibres and does not move. Every real deck is somewhere between, and where it sits is decided by the bearings rather than by the deck.free: 14.5 mm of camber, no stressheld: 9 kNm and ±18.9 MPa, no movementκ = α·ΔT/d = 0.129 × 10⁻⁶ per mm either way
Fig. 9 The restraint half: free to bend and it cambers with no stress; held and it carries a moment and does not move. Both statements are about κ\kappa alone, and both are true of the straight-line profile that leaves no self-stress whatever.
2 continuous spans against 2 simple onesThe bending moment in a continuous beam, solved by the stiffness method, drawn over the moment in the same spans made simply supported. The peak sagging moment falls from 1562.5 to 878.9, and a hogging moment of 1562.5 appears over the supports where there was none.moment878.9 sagging1562.5 hogging1562.5 if the spans were simplereactions 187.5 625.0 187.5 — the inner supports carry far more than a sharethe continuous case needed stiffness; the comparison did not
Fig. 10 Where the restraint moment lands. A continuous beam resists curvature at its interior supports, so a deck that wants to hog under solar gain hogs harder over its piers — a load case with no load in it, sitting on top of the one that has.

Where the model stops

The temperature profile is an input. Getting it is a heat-conduction problem with the sun, the sky, the wind and the surfacing in it, and codes supply standard profiles precisely because nobody wants to solve it. Every number on this page is downstream of a curve somebody else drew.

The material is linear and its modulus is one number. Concrete’s is not, and worse, the stress here is applied slowly and sustained for hours — so creep relieves a good part of it, and the peak that a linear elastic calculation gives is an upper bound on what is actually there after an afternoon.

And the profile varies only through the depth. A box girder is hotter on its south web than its north one, which puts a horizontal curvature and a twist into the same section and needs a two-dimensional version of every integral above.

What the pictures cannot show

The stress block is drawn as a static shape. It is a moving one: the profile changes hour by hour, so the field peaks, reverses overnight and does it again tomorrow. It is a cyclic action, which puts it in the same family as fatigue rather than in the family of static load cases, and the number that governs is a range rather than a value.

Nor can they show that it is invisible. A stress field with no resultant does not appear in any bending-moment diagram, any shear diagram, or any reaction. Every figure on this site that draws a load path is drawing something this field is not on.

Cambered against the wet loadA 25 m composite beam whose flexural rigidity rises from 94 to 260 kN·m² when the slab sets, so the first two loads are carried by the bare steel and the rest by the composite section. Fabricated with 476.2 mm of camber, it moves through -389.6, 0.0, 140.9, 238.7 mm as the four stages arrive — 0.0 mm on the day the slab is poured, and 238.7 mm at the end, which is one part in 105 of the span. The largest curvature it ever has is 476.2 mm of hog, and it has that with nothing on it. Every shape is drawn at the same exaggeration and the drawing is a diagram of a proportion: the vertical scale is 13214 times the horizontal.levelas fabricated: 476.2 mm of camber-389.60.0140.9238.7self-weight of the steel: 86.6 mm on EI = 94wet concrete: 389.6 mm on EI = 94finishes and services: 140.9 mm on EI = 260imposed load: 97.8 mm on EI = 260
Fig. 11 And the movement it comes with. Camber as a running total: the 4.9 mm here appears in the afternoon and is gone by morning, which is why a deck’s measured level depends on the time of day it was surveyed.

The assumption the figures rest on

Plane sections, and only plane sections. Take that away — allow the section to warp out of its own plane — and there is no constraint left for the temperature to violate, and no self-stress.

That is not an idle observation. A very deep member, or one whose profile varies rapidly along the span, does not obey plane sections, and the real self-stress in it is smaller than these integrals say. So is the stress near a free end, where the field has to die out over a Saint-Venant length: the end face carries no stress at all, the full field exists a depth or so in, and the transition between them is a region none of this describes.

The practical form of that observation is worth having. The self-stress field is largest where the member is most beam-like, which is the middle of a long uniform span, and it fades wherever the assumptions this site is built on fade.

Two mechanisms, and they add up to the torque at every sectionSaint-Venant torque and warping torque along a 305 by 165 mm I-section of 6 m, twisted by 0.5 kN·m with the ends fixed-free. J is 1.31×10⁵ mm⁴ and I_w 1.63×10¹¹ mm⁶, so k = √(GJ/EI_w) gives kL = 3.34 and a decay length of 1.80 m — 30% of the member. At the built-in end the shearing mechanism is exactly zero and all 0.5 kN·m is carried by the flanges bending in opposite directions; a decay length along, that share has fallen to 37%, and at the far end it is 7.1%. The two curves sum to the flat line at 0.5 kN·m at every one of the 161 stations, to the last bit of the arithmetic, which is the equilibrium of a slice of the member and is the only reason the split may be believed.012345600.10.20.30.40.5distance along the member (m)torque (kN·m)1/k = 1.80 msum = 0.5 kN·mSaint-Venantcirculating shearwarpingthe flanges bending
Fig. 12 What happens when a section does not stay flat, in the setting where it is unavoidable. The warping stresses there and the thermal stresses here are the same kind of object — self-equilibrating fields that no equilibrium check contains — reached from two different violations of the same assumption.

The ladder from here

Later rungs on this anchor: the cooling profile and why it is the governing one for a prestressed deck. The heat-conduction problem that produces the profile in the first place, and how much of it a surfacing layer changes. Creep relief of a sustained self-stress, which is the same calculation as relaxation in a tendon. Differential temperature between two materials in a composite section, where the mismatch is in α\alpha rather than in TT. Two-dimensional profiles in a box girder, with a transverse curvature and a warping stress. And the general statement this is one case of — an eigenstress, the stress left by any imposed strain field a plane section cannot follow, which covers shrinkage gradients, differential creep and welding residuals with the same three integrals.

Named alongside this one

Essays reaching for the same objects. Nobody chose these; they are what the concept index makes visible.

The objects this essay names

Each one links to every other essay that touches it.

Bridge deckCrackingCurvatureEigenstressPlane sectionsResidual stressRestraintSection propertiesSelf equilibratingServiceabilitySuperpositionThermal gradientThermal movement