Sections and stress

Where the steel is, not how much of it

A section in bending resists a moment with a couple, and a couple is a force times a distance. The force is bought — it is an area of steel at a stress. The distance is free, decided by where the bars were put, and it is the variable almost nobody optimises because it does not appear on an order.

Assumes Bending is a pair of forces, pushing and pulling, Plane sections stay plane, and what the assumption costs and Deliberately the wrong shape.

Bending is a pair of forces. A section carrying a moment has a compression resultant somewhere in its upper part and an equal tension resultant somewhere in its lower part, and the moment is the product of one of them with the distance between the two.

M=Cz=TzM = C z = T z

Two quantities, and they are bought on entirely different terms. The force is an area of material at a stress, ordered by the tonne and priced accordingly. The distance is a dimension on a drawing, and it costs nothing at all.

The neutral axis is wherever the first moment vanishesA 300 by 600 section with 1800 mm² of steel at a depth of 540, carrying 250 kNm after the tension side has cracked. The neutral axis is no longer at mid-depth: it has risen to 234.5 mm from the top, which is where the first moment of the compression zone plus the transformed steel vanishes. The compression is 15.4 N/mm² at the top fibre and the steel carries 301 N/mm²; the resulting couple is 541 kN on a lever arm of 462 mm, which multiplies back to the 250 kNm applied. The uncracked section would have had 6673×10⁶ mm⁴ against the cracked 3809×10⁶ — a loss of 43% of the stiffness.x = 2341800 mm² of steel, n = 15b = 30015.4 N/mm²541 kN in the steelz = 462C = T = 541 kN · C·z = 250.0 kNm = the applied momentcracked I 3809×10⁶ mm⁴ against uncracked 6673×10⁶ — 43% of the stiffness gone
Fig. 1 A cracked reinforced section carrying 250 kNm. The neutral axis has risen to where the first moment of the compression zone and the transformed steel vanishes; the couple is 541 kN on a lever arm of 462 mm.

Which free body produced the number

Cut the beam and take everything on one side. Two conditions have to hold on the cut face: the axial forces sum to zero, and their moment equals the applied moment.

The first condition is what fixes the neutral axis. It says the compression in the concrete equals the tension in the steel, and since the compression grows with the depth of the compression zone, there is exactly one depth at which the two balance. Nothing about the applied moment enters that calculation for a cracked elastic section — the neutral axis is a property of the geometry and the modular ratio alone.

The second condition then gives the moment, and it does so by multiplying the resultant found in the first by the distance between the two resultants. That distance is the internal lever arm zz, and everything in this essay is about it.

On the section drawn, z=462z = 462 mm against an effective depth of 540 — a ratio of 0.856, which is where the familiar rule of thumb z0.9dz \approx 0.9d comes from. It is not a constant, and its variation is the interesting part.

Two integrals, and no third

A concrete compression zone has a curved stress distribution whose shape depends on the material’s own law, and every design office replaces it with a rectangle. That substitution is exact for the only two things the moment equation asks about.

Wrong in shape, right in two integralsThe compression zone of a C45 section with its neutral axis 150 mm down, drawn twice. The curved outline is the real parabolic-rectangular stress distribution — the material's own law read off the linear strain profile plane sections supplies. The rectangle over it is what every design office uses instead: intensity η f_cd = 24.8 MPa over a depth λx = 125 mm. The two shapes are visibly different and give the same answer, because a bending calculation asks a stress distribution only two questions — how much compression there is, and where its resultant acts. Both are 1084 kN at 62.4 mm from the face. The factors are α = 0.8095 and β = 0.4160, and λ = 2β follows from wanting the same centroid. A triangle and a full rectangle match neither integral and are nowhere near.neutral axisC = 1084 kNat βx = 62.4 mmf_cd = 25.5 MPaα = 0.8095 β = 0.4160η f_cd over λxλ = 0.832, η = 0.973same resultant, same position ⇒ same moment, to machine precisiona triangle would be -37% out, a full rectangle 20%
Fig. 2 The real parabolic-rectangular compression zone with the design rectangle over it. The two shapes are visibly different and give the same total force at the same position.

The equilibrium equations need the area under the stress distribution — the total compression — and its centroid — where that compression acts. Any two distributions with the same two integrals are indistinguishable to a bending calculation, and the rectangle was constructed from the curve’s own integrals precisely so that they match.

Deliberately the wrong shape is the essay about that construction. The consequence here is worth stating positively: the lever arm is not a property of the stress block’s shape. It is a property of two integrals, and the only way to change it is to change where the material is.

What adding steel actually does

Follow the two conditions through and the answer to “what does more reinforcement buy” is not what the linear intuition says.

Adding steel increases TT at a given stress. Equilibrium then requires a larger CC, which requires a deeper compression zone, which lowers the compression resultant and therefore shortens the lever arm. So the capacity TzT z grows less than in proportion to the steel area, and the shortfall accelerates.

A rectangle at 90% of its plastic momentThe same rectangle drawn three ways: the shape, the strain across its depth, and the stress that strain produces in mild steel. The strain diagram is a straight line, because plane sections stay plane whatever the material is doing. The stress diagram is not: 45% of the area has yielded, working inward from both faces, and the neutral axis sits at 250.0 mm against a centroid at 250.0 mm. The compression resultant is 299.5 kN and the tension resultant 299.5 kN, on a lever arm of 309.9 mm, which multiplies back to the 92.8 kNm the section is carrying.neutral axisrectanglestrainalways a straight linestressthe material's own curve, sidewaysC = 299.5 kN · T = 299.5 kN · lever arm 310 mm · M = 92.8 kNm45% of the area has yielded — 111 mm from the top, 111 mm from the bottom · Mp = 103.1 kNm · shape factor 1.50
Fig. 3 A rectangle at 90% of its plastic moment, with the strain, the stress and the two resultants. The compression and tension resultants are 299.5 kN each on a lever arm of 309.9 mm, which multiplies back to the moment applied.

Push it far enough and the lever arm collapses toward zero while the steel is still elastic: the compression zone reaches most of the depth, the concrete crushes before the steel yields, and the section fails without warning. That is the over-reinforced case, and every design standard forbids it by putting a limit on the neutral axis depth rather than on the steel area — a limit on the lever arm, expressed in the variable that decides it.

The mirror image is what makes the depth so much better a variable. Increasing dd increases the lever arm in proportion and does nothing to the force at all.

Every strip counts by the square of its distanceA rectangular section divided into equal strips, with each strip's contribution to the second moment of area drawn beside it. The strips are identical in size; only their distance from the neutral axis differs.neutral axiscontribution of each striptotal I = 5400.00 × 10⁶the outer strips do almost all of the work
Fig. 4 A rectangle in strips, each contributing by the square of its distance from the neutral axis. The elastic version of the same statement — where the material is beats how much there is.

Where the effective depth is actually decided

If capacity is proportional to dd, then the design of a reinforced beam is largely the design of dd, and it is worth listing who decides it. It is not the structural engineer.

d=hcoverϕlinkϕbar/2d = h - \text{cover} - \phi_{\text{link}} - \phi_{\text{bar}}/2

Cover is a durability requirement, set by the exposure class and the fire period. The link diameter is set by the shear design, or by a minimum. The bar diameter is set by what is available and by crack width rules. On a 600 mm deep beam with 25 mm cover, an 8 mm link and 25 mm bars, d=554d = 554. Change the cover to 50 for an aggressive exposure and d=529d = 529 — 4.5% of the capacity, gone, for a reason that has nothing to do with structure.

Put the bars in two layers, because they will not fit in one, and the centroid of the steel drops another 30 mm or so: another 5%. Ten per cent of a beam’s bending capacity can be decided by a cover requirement and a bar spacing rule between them, and neither appears in any equation a structural calculation contains.

Depth is in the answer twice, and the size effect takes some of it backPunching resistance against the effective depth of the slab, everything else held. The depth enters three times over — the perimeter stands 2d from the face and so grows with it, the resistance is a stress times that perimeter times the depth, and the empirical size-effect factor shrinks as the slab gets thicker. Fitted over this range the resistance goes as d to the power 1.44, which is neither the square the first two terms suggest nor the linear dependence a shear check on a beam would give.15020025030035040045050005001000150020002500effective depth (mm)punching resistance (kN)fitted power1.44not 2, andnot 1
Fig. 5 The same quantity in a different check. Punching resistance goes as the effective depth to the power 1.44 over this range — the depth is in the answer three times over and a size effect takes some of it back.

The bar has to be anchored to be worth anything

A tension resultant is only there if the bar can develop the force. That is a bond question, and it is the one place where the amount of steel and its position interact.

The bond stress is crowded against the loaded endA 25 mm bar embedded 1157 mm, with the force in it and the bond stress on it plotted along the embedment. Uniform bond — the assumption behind every development length ever tabulated — is a flat stress and a straight line of force. An elastic bond of the same peak strength is neither: the slip is largest where the bar is pulled and dies away over 1/α = 527 mm, so the far end of the bar is doing almost nothing. At the code's own length of 46 diameters the elastic bond is 44 per cent used. The uniform answer is what the bond looks like after it has yielded along the whole length, which is a statement about ductility rather than about strength.245 kN1157 mm = 46φ00.20.40.60.8100.20.40.60.81along the embedded length÷ its own peakelastic forceuniform forceelastic bond stressuniform bond
Fig. 6 A bar embedded 1157 mm, with the force in it and the bond stress along it. Uniform bond is a flat stress and a straight line; an elastic bond is neither, and the far end of the bar is doing almost nothing.

The development length grows with the bar diameter, so a section reinforced with a few large bars needs longer anchorages than one with many small ones at the same area — and the large bars also sit further from the face, lowering dd. Both effects push the same way, which is why heavily reinforced members are detailed with more, smaller bars than an area calculation alone would suggest.

The distribution matters as much as the length. At a code’s own development length the elastic bond is only 44% used, because the slip is concentrated at the loaded end and dies away over a decay length. The uniform-bond assumption behind every tabulated anchorage is a statement about what happens after the bond has yielded along the whole length, which is a claim about ductility rather than about strength.

Two section moduli, and only one of them is a strength

The lever arm has an elastic counterpart, and for an asymmetric section there are two of them.

A section modulus for each face, and only the smaller one is a strengthFour profiles of equal area with the second moment divided by BOTH distances to an extreme fibre rather than by the larger of them. A symmetric section has one section modulus and an asymmetric one has two, differing here by as much as 1.00 to one — so the same member has two bending strengths, and which of them applies is decided by the sign of the moment rather than by anything about the section. The bar is the smaller of the two, which is the one that governs when the moment can go either way.the same, laid flatZ top 21.3 × 10³Z bottom 21.3 × 10³the same both wayssquareZ top 119.3 × 10³Z bottom 119.3 × 10³the same both waystall rectangleZ top 666.7 × 10³Z bottom 666.7 × 10³the same both waysI-sectionZ top 1033.6 × 10³Z bottom 1033.6 × 10³the same both waysthe two solid lines are the extreme fibresthe bar is the smaller section modulus, to scale
Fig. 7 Four profiles of equal area with the second moment divided by both distances to an extreme fibre. A symmetric section has one modulus; an asymmetric one has two, and only the smaller is a strength.

Z=I/yZ = I/y is a lever arm in disguise: it is the second moment divided by the distance to the fibre being checked, and a section with material concentrated near one face has a large modulus for that face and a small one for the other. Which one governs is decided by the sign of the moment rather than by anything about the section — so a member that can be bent either way has the smaller of the two as its capacity, and the extra material on one side is dead weight.

That is why a tee is an efficient shape for a slab and a poor one for a beam that can hog, and it is the same trade two strengths depending which way up is about.

Prestress, where the lever arm is a profile

The same variable appears in prestressed concrete under a different name and with much more freedom.

The zone the tendon has to stay insideThe eccentricities that keep the top fibre out of tension at transfer and the bottom fibre out of tension in service, along a 16 m beam. The two limits cross the section at different rates, and the parabolic profile drawn between them is the tendon: 220 mm at midspan, where the zone is -4 mm deep, and on the centroid at the ends, where a tendon left low would crack the top of a beam carrying nothing but itself.0246810121416-300-200-1000100200300distance along the span (m)eccentricity below the centroid (mm)above this line the top cracks at transferbelow this line the bottom cracks in service
Fig. 8 The eccentricities that keep the top fibre out of tension at transfer and the bottom out of tension in service. The tendon is drawn inside them, at 220 mm at midspan and on the centroid at the ends.

A tendon’s eccentricity is a lever arm the designer draws, and unlike a reinforcing bar it can vary along the member. It is largest where the moment is largest and zero where the moment is zero, which is the profile in the figure — and the limits it has to stay within are four inequalities and a wedge, two at transfer and two in service.

The freedom has a price. A tendon low at the ends would crack the top of a beam carrying nothing but itself, which is a stage that exists on a casting bed and nowhere in the finished structure.

What a stiff material does to the share

There is one further way in which position beats quantity, and it is about which material carries what.

A stiff material takes what its modulus asks for, not what its area doesA steel plate of growing thickness beside a 150 × 300 timber joist, with the plate's share of the area and its share of the moment plotted against each other. The two curves are nowhere near one another: at 6.5 mm the plate is 4.2% of the section's area and carries 45% of its moment, because stress follows strain times modulus and the strains are equal by assumption. The gap is the modular ratio and nothing else. It is also why a stiff repair attracts the very load it was added to relieve.246810120%20%40%60%80%100%thickness of the steel plate (mm)shareof the momentof the area
Fig. 9 A steel plate of growing thickness beside a timber joist, with its share of the area plotted against its share of the moment. At 6.5 mm the plate is 4.2% of the area and carries 45% of the moment.

Because plane sections stay plane, the strain at a height is fixed and the stress follows the modulus. A stiff material at a large distance therefore takes a share of the moment out of all proportion to its area — the modular ratio times the lever arm ratio, and nothing else.

The practical corollary is uncomfortable: a stiff repair attracts the very load it was added to relieve. Bond a steel plate to the soffit of a cracked beam and it picks up load in proportion to its modulus, which is exactly what was wanted; add a stiff element beside a soft one anywhere in a structure and the same thing happens whether it was wanted or not.

The number that says how much is left

There is a single ratio that carries most of what a designer needs to know about a bending section, and it is the lever arm written as a fraction of the effective depth.

At z/dz/d close to 0.95 the section is very lightly reinforced: the compression zone is shallow, the concrete is barely working, and adding steel is almost perfectly efficient because the lever arm hardly moves. This is the state of a slab, and it is why slabs are designed with a rule of thumb rather than an iteration.

At z/dz/d around 0.85 — the section in the figure at the top — the section is doing what it was designed to do. Adding steel still helps, at a diminishing rate.

Below about 0.82 the neutral axis has descended past the limit standards impose, and the section is refused rather than being allowed to be inefficient. The refusal is about ductility: a section whose concrete crushes before its steel yields gives no warning, and the depth limit is how that is prevented. It is also, incidentally, the point past which adding steel has stopped being good value.

So a single dimensionless number tells a designer where a section sits between three quite different regimes, and it is a ratio of two lengths with no material in it. That is characteristic of this subject and worth noticing: the quantities that generalise are ratios of lengths, and the ones that do not are stresses.

The corresponding statement for a steel section is the shape factor, which is the ratio of the plastic lever arm to the elastic one and is 1.5 for a rectangle, about 1.15 for an I-section, and 1.7 for a solid circle. Same question, same kind of answer, and again a pure geometric ratio.

Where the model stops

The lever arm is not constant along the member. Everything here is a cross-section calculation at one station, and zz changes as the moment changes and as bars are curtailed. Near a support it is not even a bending quantity — the chord carries half the shear as tension, and the force in the bar is the moment diagram shifted rather than divided.

Plane sections is doing all the work. The whole construction depends on the strain varying linearly across the depth, which is the assumption underneath and which fails in deep members, near openings and next to concentrated loads.

The steel may not reach its yield stress. Everything above assumed the tension resultant was the area times the design strength, which requires the steel to have strained past yield — and whether it has depends on where the neutral axis ended up, which is the quantity being computed. The check closes on itself and, in the region where it does not close, what is left after the first fibre yields is the correct question.

The neutral axis moves as the material yields. The elastic result above and the plastic one are different calculations with different lever arms, and the ratio between the two moments is the shape factor — 1.50 for a rectangle, and reached only at several times the curvature at first yield.

What it costs to reach the plastic moment, for one shapeMoment against curvature for one cross-section of identical area (6000 mm²) and identical depth (500 mm), in mild steel, each divided by its own first-yield moment and its own first-yield curvature. The rectangle has a shape factor of 1.50 and reaches 98% of its plastic moment at 4.3 times the curvature at first yield. The dashed lines are the rigid-plastic moments, computed from the equal-area axis rather than read off the curves, and no curve reaches its own.02468101200.511.5curvature ÷ curvature at first yieldmoment ÷ moment at first yieldrectangle: 1.50× the yield moment, at 4.3× the yield curvature
Fig. 10 Moment against curvature for one section, normalised by its own first-yield values. The rectangle reaches 98% of its plastic moment at 4.3 times the curvature at first yield.

What the picture cannot show

A section drawing shows bars as circles at positions, and the positions are nominal. What is built is decided by chairs, spacers, the sequence of fixing, and whether the top steel was walked on before the pour — and effective depth is measured to the real position rather than the drawn one.

The consequence is that dd is the least reliably delivered quantity in a reinforced concrete member and the one its capacity is most directly proportional to. Bars in the top of a slab pushed down 20 mm by a boot lose 10% of a 200 mm slab’s hogging capacity, in the region where the hogging moment is largest.

Nor does the drawing show the fixing tolerance running the other way, which it also does. This is a quantity with a scatter and a mean, applied to a capacity that is linear in it, and the scatter has a bigger effect than any material variability in the section.

The generalisation

The habit worth carrying is to look for the distance in every capacity, because there is nearly always one and it is nearly always the cheap variable.

A section’s bending capacity is a force times a lever arm. A truss’s chord force is a moment over a depth. A shear wall’s overturning resistance is a weight times a width. A bolt group’s moment capacity is a force times a distance to the group’s centroid. In every one of them the force is a material quantity that costs money and the distance is a geometric quantity that costs a decision.

The reason it is under-used is the same in every case: the force appears in a specification and the distance appears on a drawing, and only one of those is checked by the calculation. Where the material sits beats how much of it there is, and the whole of the difficulty is that nobody is asked the question in those terms.

Named alongside this one

Essays reaching for the same objects. Nobody chose these; they are what the concept index makes visible.

The objects this essay names

Each one links to every other essay that touches it.

BondCoverCracked sectionEffective depthEquilibriumLever armModular ratioNeutral axisPlane sectionsPrestressReinforcementSecond moment of areaSection modulusShape factorStress block