Sections and stress

Two moments and a neutral axis that obeys neither

Tilt the load on a rolled beam by five degrees and the neutral axis swings by seventy. The section is doubly symmetric, its product of inertia is exactly zero, and none of that helps — because what decides the axis is the moment ratio multiplied by a stiffness ratio of thirty.

Assumes The material far from the middle does nearly all the work, Bending is a pair of forces, pushing and pulling and Loaded straight down, and it moves sideways.

A rolled beam is a machine for being strong in one direction. A 305 by 102 universal beam has a second moment of 5.91×107mm45.91 \times 10^7\,\mathrm{mm^4} about its strong axis and 1.92×1061.92 \times 10^6 about its weak one — a factor of thirty-one — and that ratio is the entire reason the shape exists.

It is also the reason the section is so easy to ruin. Turn the load five degrees out of the plane of the web and the stress in the worst corner goes up by ninety per cent.

The neutral axis obeys neither the load nor the momentA 305 × 102 mm I-section carrying a moment 5° out of the plane of its web. The moment vector is the short arrow; the neutral axis is the long line, at 69.7° to the strong axis. They do not line up, and the reason is that the neutral axis follows the moment ratio *scaled by the stiffness ratio*: tan α = (M_z/M_y)(I_y/I_z), and I_y ÷ I_z is 30.8 here. So a 5° tilt of the load puts the neutral axis 70° over, the corner that ends up furthest from it carries 489 N/mm² against the 258 the straight-down case would give, and the section has lost 47 per cent of its capacity to a misalignment nobody would draw on a detail.neutral axis, 70°moment, 5°489 N/mm²tan α = (M_z/M_y)(I_y/I_z), and I_y ÷ I_z = 30.8489 N/mm² at the corner against 258 for the same moment straight down
Fig. 1 A moment applied five degrees out of the plane of the web, and the neutral axis it produces. The two do not line up and are not close to lining up: the axis sits at 69.7° to the strong axis while the moment is at 5°, because the axis follows the moment ratio scaled by the stiffness ratio, and that ratio is 31.

Which free body produced the number

Cut the section and impose the assumption everything here rests on: plane sections stay plane. The strain at a point is then a linear function of position, so the stress is too, and the general linear function of two coordinates is

σ=MyyIy+MzzIz\sigma = \frac{M_y\,y}{I_y} + \frac{M_z\,z}{I_z}

for a section whose product of inertia is zero — which for a doubly symmetric shape it is, exactly, by symmetry. The two bending problems superpose and nothing couples them.

The neutral axis is where that expression vanishes, which gives z/y=(MyIz)/(MzIy)z/y = -(M_y I_z)/(M_z I_y), or

tanα=MzMyIyIz\tan\alpha = \frac{M_z}{M_y}\cdot\frac{I_y}{I_z}

measured from the strong axis. Two ratios multiply: how much of the moment went the weak way, and how much less stiff the section is that way. The first is small and the second is thirty-one, so the product is not small.

At one degree of tilt the axis is already at 28°. At five it is at 70. At ten it is at 80, and past that it barely moves, because the section has effectively given up bending about its strong axis at all.

The difference from the section next door

This is a different argument from the one about unsymmetric sections, and the two are worth separating carefully, because they look alike and share a page in most textbooks.

There, the load is straight down, the section is an angle or a zed, its product of inertia IyzI_{yz} is not zero, and the consequence is that a vertical load produces a horizontal movement. The coupling is a property of the section.

Here, IyzI_{yz} is exactly zero and there is no coupling at all. What produces the answer is that the load is not straight down — and the section’s response to the part of it that is not is enormously more compliant than its response to the part that is. The coupling is a property of the load.

The two can happen together, and an angle carrying a load off the vertical is genuinely both. The reason for keeping them apart is that the fixes are different: the first is fixed by rotating the section or restraining it laterally, and the second is fixed by making sure the load is where it was said to be.

The second moment of area is a function of directionSecond moment of area of an equal angle against the angle of the axis it is taken about, with the product of inertia beneath it. The maximum is 2.866 × 10⁶ mm⁴ and the minimum 0.734 × 10⁶, a ratio of 3.90, and they occur where the product of inertia passes through zero — at 45.0° from the drawn axis. The value the drawing suggests, 1.800 × 10⁶, is neither of them.020406080100120140160180-1.00.01.02.03.0angle of the axis (degrees from the drawn one)second moment of area (10⁶ mm⁴)principal at 45.0°I about the axisproduct of inertia
Fig. 2 The other mechanism, for the contrast. There the second moment varies with the angle of the axis and has a maximum and a minimum that are not the axes the section was drawn about. Here the axes are the principal ones already, and everything comes from the load.

Where the weak axis takes over

The stress at the worst corner is

σ=M(cosθZy+sinθZz)\sigma = M\left(\frac{\cos\theta}{Z_y} + \frac{\sin\theta}{Z_z}\right)

and the two terms are equal when tanθ=Zz/Zy\tan\theta = Z_z/Z_y. For this section that is 5.5 degrees.

Past five and a half degrees the beam is a weak-axis member with a strong-axis correction, which is an odd sentence about a section chosen entirely for its strong axis, and it is why the tilt matters so much more than the geometry suggests.

Five degrees is not five per centThe corner stress on a 305 mm I-section, against how far the load is off the plane of the web, as a multiple of the stress with the load straight down. The two terms add — M cos θ ÷ Z_y and M sin θ ÷ Z_z — and Z_y ÷ Z_z is 10.3 for this section, so the weak-axis term catches the strong-axis one at only 5.5°. At the 5° drawn the stress is 1.90 times what a designer who ignored the tilt would have computed. A purlin on a roof pitch, a crane girder taking a lateral surge, a beam whose bearing is not quite level: none of them is five per cent worse than the calculation done for it.0510152025300123456load direction off the web (degrees)corner stress ÷ the straight-down answerthe two terms are equal at 5.5°1.90× at 5°Z_y ÷ Z_z = 10.3 · I_y ÷ I_z = 30.8
Fig. 3 The corner stress against the tilt of the load, as a multiple of the straight-down answer. The curve leaves one almost vertically: a single degree costs eighteen per cent, five costs ninety, and ten costs a factor of 2.8. The vertical line is where the two terms are equal, and it is at five and a half degrees.

The purlin, which is the case this is really about

Nothing on a building site is five degrees out of plane by accident. What is out of plane by design is a purlin.

A purlin sits on a sloping rafter and carries a vertical load — snow, wind, its own roof — through a section whose web is perpendicular to the roof rather than to the ground. The angle between the load and the web is therefore the roof pitch, and roof pitches are not five degrees. At twenty degrees the corner stress on this section is 4.5 times what a strong-axis calculation gives.

That is why purlins have sag bars. A sag bar is a rod running up the slope between the purlins at mid-span, and its only job is to hold the purlin against moving down the slope — which halves the effective span for the weak-axis component while leaving the strong-axis span alone. It is the cheapest possible response to the arithmetic above: it does not make the section stronger, it removes the term.

And it explains a detail that looks arbitrary from outside. Sag bars are put in at mid-span for one row and at the third points for two, in a pattern decided by the weak-axis moment and having nothing to do with the vertical load at all.

One restraint, and several times the loadThe same portal — the same columns, the same beam, the same steel — buckling with its head held against sway and with its head free to sway. The braced frame's critical load is 16.46 EI/L² and the swaying one's is 5.69 EI/L², a factor of 2.89, and the effective length factor that comes out of each eigenvalue is 0.774 against 1.317. Both are eigenvalues of the assembled frame at a beam-to-column stiffness ratio of G = 1.00; the buckled shapes are the mode vectors themselves, drawn at 18 per cent of the storey height so that the movement can be seen.the storey that cannot driftk = 0.774N꜀ᵣ = 16.46 EI/L²the storey that cank = 1.317N꜀ᵣ = 5.69 EI/L²the same column, 2.9 times the load — the restraint is the whole of the difference
Fig. 4 What the sag bar does, in the language of the member it does it to. One restraint at mid-span quarters the weak-axis moment and does nothing whatever to the strong-axis one — a restraint that acts on one term of a sum and not on the other, which is the cheapest kind there is.

The beam moves the way the axis says, not the way the load does

The deflection follows the same arithmetic and gets less attention.

A member deflects perpendicular to its neutral axis, so a load five degrees off the web moves this beam at 70 degrees to the vertical — sideways nearly as much as down. The magnitudes are the two components computed separately, δycosθ/Iy\delta_y \propto \cos\theta/I_y and δzsinθ/Iz\delta_z \propto \sin\theta/I_z, and the ratio of the second to the first is again the tilt times the stiffness ratio.

For a purlin that is the sag: a purlin without sag bars does not deflect downwards, it slides down the slope, and the visible symptom is a roof whose lines are wrong rather than a roof that is sagging. On a twenty-degree pitch the down-slope movement of this section is eleven times the movement normal to the roof.

And the serviceability check is nearly always written about the wrong one. A deflection limit of span over two hundred applied to the vertical component passes a member whose real movement is several times that, in a direction nobody measured.

The deflected shape is the moment, integrated twiceA loaded beam with its deflected shape above and its bending-moment diagram below. The shape was obtained by integrating the moment twice and fitting the constants to the supports; the vertical scale is exaggerated enormously.24the largest movement, at x = 4.00momentdrawn at roughly three hundred times the real deflection —a beam at its serviceability limit moves about a three-hundredth of its span
Fig. 5 The shape itself, which is the same curve whichever axis it belongs to. What biaxial bending adds is that there are two of these at once, at right angles, in a ratio the tilt of the load fixes — and the resultant is a line at the same angle as the normal to the neutral axis.

Four corners, and only one of them is the answer

Superposing two bending stresses on a doubly symmetric section gives four corner values, and they are not symmetric in any useful way: two corners have both terms of the same sign and two have them opposed.

The corner where they add is the one that decides the section, and the corner diagonally opposite it is its mirror in tension. The other two carry the difference of the two terms, which for a small tilt is nearly the strong-axis stress alone and for a large one is nearly the weak-axis stress with the sign the other way.

That is worth stating because it decides where a strain gauge goes and where a crack starts, and because it is the reason a biaxially bent section that is asymmetric in one direction — a channel, a zed, a section with unequal flanges — has no single governing corner at all. It has one for each combination of signs, and the check is four checks.

Bending is a push and a pullA section carrying a bending moment, with the stress at every height computed as the moment times the distance from the neutral axis divided by the second moment of area. It is compression above and tension below, and zero exactly at the neutral axis.neutral axiscompressiontensionI = 28.42 × 10⁶Z = 284.2 × 10³peak stress 183.0σ = M y ÷ I, at every height
Fig. 6 The stress block one of the two terms produces. The biaxial answer is two of these at right angles, added at each corner — which is why the arithmetic is a sum rather than anything more interesting, and why the interesting part is the ratio the two are in.

The elastic check is a plane and the plastic one is a curve

Set the corner stress to the yield stress and the capacity is

MyMy,el+MzMz,el=1\frac{M_y}{M_{y,el}} + \frac{M_z}{M_{z,el}} = 1

which is a straight line in the two moments — a diamond, if both signs are drawn. That is the elastic answer and it is exact, because the two stresses genuinely add at the corner.

The plastic answer is not a straight line, and the reason is worth stating precisely: the plastic neutral axes for the two cases are not the same line. Bending about the strong axis puts the whole top half in compression; bending about the weak axis puts the whole of one side in compression. Combine them and the yielded region is a wedge whose boundary is neither — so the section carries more of the combination than the sum of the parts suggests, and the interaction bulges outward with an exponent of about two on the strong axis.

For the section here the elastic capacity at five degrees is 73 kNm and the plastic one is 114, a ratio of 1.58 — against a strong-axis shape factor of only 1.13. Biaxial bending is where the plastic reserve is largest, precisely because it is where the elastic corner stress is most pessimistic about what the rest of the section is doing.

Two ways to fail, and the curve between themThe exact plastic interaction between axial force and moment for two sections of identical area, both normalised by their own squash load and their own plastic moment. The rectangle stands 25.0% of its plastic moment outside the straight line at an axial ratio of 0.50; The I-section stands 14.6% of its plastic moment outside the straight line at an axial ratio of 0.29. Every section here is symmetric about its centroid, so the equal-area axis and the centroid coincide and it makes no difference which the moments are taken about. The straight line is the rule that says the two capacities share out in proportion, and everything between it and a curve is capacity that rule gives away.00.20.40.60.8100.20.40.60.81moment ÷ plastic momentaxial force ÷ squash loadrectangle: 25.0% of Mp outside the lineI-section: 14.6% of Mp outside the linethe straight-line rule
Fig. 7 The interaction diagram, in its more familiar setting. The straight line is what adding the stresses gives; the bulge is what asking the section for its plastic capacity gives. Biaxial bending has the same shape and a larger bulge, for the same reason: the two limiting cases do not share a neutral axis.

The shape factors are not the same either

A doubly symmetric I-section has a strong-axis shape factor of about 1.13 — the plastic modulus is thirteen per cent more than the elastic one, because most of the material is already near the extreme fibre and there is little left to recruit.

About the weak axis the same section has a shape factor of 1.54, which is close to a rectangle’s 1.5, because about that axis the section is essentially two rectangles laid flat. The flanges, which are the reason the strong-axis factor is small, are the reason the weak-axis factor is large.

So the two directions differ not only in capacity but in kind: the strong axis is an elastic section with a little reserve and the weak axis is a plastic one. A designer who reaches for a plastic check to recover margin recovers more of it in the direction that was not supposed to be carrying anything.

A section modulus for each face, and only the smaller one is a strengthFour profiles of equal area with the second moment divided by BOTH distances to an extreme fibre rather than by the larger of them. A symmetric section has one section modulus and an asymmetric one has two, differing here by as much as 1.00 to one — so the same member has two bending strengths, and which of them applies is decided by the sign of the moment rather than by anything about the section. The bar is the smaller of the two, which is the one that governs when the moment can go either way.the same, laid flatZ top 8.7 × 10³Z bottom 8.7 × 10³the same both wayssquareZ top 42.2 × 10³Z bottom 42.2 × 10³the same both waystall rectangleZ top 203.3 × 10³Z bottom 203.3 × 10³the same both waysI-sectionZ top 430.4 × 10³Z bottom 430.4 × 10³the same both waysthe two solid lines are the extreme fibresthe bar is the smaller section modulus, to scale
Fig. 8 Where the two moduli come from. The same material distributed for one axis is distributed badly for the other, and the factor between the two section moduli is the number every argument on this page multiplies by.

The crane girder, where the tilt is a load rather than a geometry

A purlin is out of plane because the roof is. A crane girder is in plane and gets its second moment from the crane.

A travelling crane applies a horizontal surge along the rail — from accelerating the crab, from skewing on the rails, from the load swinging — and that surge acts at the top flange, several hundred millimetres above the section’s centroid. So the girder carries a vertical wheel load, a horizontal load at the top flange, and the torsion the offset between them produces, all at once and all at their maxima at the same instant.

The arithmetic on this page prices the first two. A horizontal surge of a tenth of the vertical wheel load is a five- or six-degree tilt of the resultant, and this section’s curve says that costs it most of a factor of two. Which is why crane girders are almost never plain I-sections: they are I-sections with a channel or a plate on the top flange, and the extra piece is there to carry the horizontal component about an axis the plain section is bad at.

The shear centre of a channelA channel of 80 by 200, with the shear flow in its flanges drawn. Those flows form a couple, so the load has to be applied 31.7 outside the web to leave the section untwisted — a point in the air, outside the material entirely.web centrelineshear centree = 31.7no twisttwiststhe flange flows are equal, opposite, and separated — which is a coupleand nothing about the section's 20.19 × 10⁶ second moment predicts it
Fig. 9 The third action the crane applies. A horizontal load at the top flange misses the shear centre by the whole depth of the section, so the girder twists as well as bending both ways — which is why the top flange is the part that gets reinforced.

Where the model stops

Nothing here is about torsion, and a load out of plane usually brings some. A vertical load on a sloping purlin acts through a line that misses the shear centre, so the section twists as well as bending both ways, and the twist adds a warping stress the superposition above has no term for. The check is honest only while the member is torsionally restrained — by the sheeting, by the sag bars, by the cleats — which for a purlin it largely is and for a crane girder taking a lateral surge it is not.

Lateral-torsional buckling is left out entirely. A member bent about its strong axis and pushed sideways at the same time is being asked the lateral-torsional question in its most direct form, and the resistance to that is not the section’s weak-axis modulus but a curve of its own.

The section is taken as doubly symmetric. A channel is not, and a channel bent about both axes is both essays at once, with IyzI_{yz} non-zero and a shear centre outside the section.

And the corner is treated as a point. A rolled section has a root radius, and the fibre furthest from a neutral axis at 70 degrees is the tip of a flange rather than the corner of a rectangle, which is a per cent or two rather than a mechanism.

What the pictures cannot show

The first figure draws the neutral axis as a line through the section. That line is a construction: nothing along it is unstressed in any measurable sense, because the section is also carrying shear, and often axial force, and the axis of zero bending stress is not the axis of zero anything else.

Nor can any of these figures show what actually happens on site, which is that the load is rarely exactly at the pitch either. A purlin picks up a component from the sheeting’s own restraint, from the wind blowing up the slope, and from the fact that snow does not lie normal to a roof. The five degrees this essay opens with is not an error bar; it is a design case that is usually specified and often exceeded.

The assumption the figure rests on

The moment is assumed to be applied about a known direction, and the section to be free to bend about whichever axis the arithmetic gives it.

Neither is quite true when a member is sheeted. Trapezoidal roof sheeting screwed to a purlin restrains it in the plane of the roof, which does not remove the weak-axis moment so much as change what carries it — part goes into the sheeting as a diaphragm and part stays in the purlin, in a proportion nobody computes and everybody assumes. The consequence is that the honest range of answers for a real purlin runs from the number in this essay down to something like a strong-axis calculation, and which end of that range a particular roof sits at depends on fixings, on sheet thickness, and on whether the sheeting has been replaced since.

Every section has one, and they are not alikeThe kern of three sections, shaded: the region a compressive resultant has to land in if no part of the section is to go into tension. A rectangle's is a rhombus reaching a sixth of the depth, 16.7% of it; a circle's is a disc of a quarter of its radius; an I-section's is 1.77 times the rectangle's in the strong direction and much smaller across it. The shape follows from the section's own radii of gyration and nothing else — no material property enters anywhere.rectangle±51 of 305 mm33.3% of the depthcircle±38 of 305 mm25.0% of the depthI-section±90 of 305 mm58.9% of the depth
Fig. 10 The same two-axis arithmetic, asked as a question about where a force may land. A kern is the biaxial interaction diagram of a section with no tensile strength, drawn in the plane of the section rather than in the plane of two moments — the same expression, plotted against a different pair of variables.

Named alongside this one

Essays reaching for the same objects. Nobody chose these; they are what the concept index makes visible.

The objects this essay names

Each one links to every other essay that touches it.

Bending stressBiaxial bendingInteraction diagramNeutral axisPlastic modulusPrincipal axesPurlinRestraintSecond moment of areaSection modulusServiceabilityShape factorSuperpositionTorsionWeak axis