Sections and stress

The one length a section takes into a column

A section has an area, a second moment, two section moduli, a shear centre and a torsion constant. A column has heard of exactly one of them, and it is none of those — it is the length √(I/A), which is where the whole area would have to sit to give the section the stiffness it has.

Assumes The material far from the middle does nearly all the work, Strong enough and still falls over and The ends decide the length that matters.

A cross-section is a rich object. It has an area, a centroid, a second moment about every axis through that centroid, a product of inertia, two section moduli, a plastic modulus, a shear centre, a torsion constant, a warping constant. Bending uses several of them. Shear uses another. Torsion uses two more.

A column uses one, and it is not on that list. It is r=I/Ar = \sqrt{I/A}, a length, and every other property of the section reaches a column only through it.

The one length a section carries into a columnFive profiles of equal area, with the radius of gyration r = √(I/A) drawn as the distance it is — a pair of lines either side of the centroid, at the depth the whole area would have to sit at to give the section the second moment it has. As a 4 m pin-ended column the same 3000 mm² of material carries between 7 and 3146 kN, in the ratio of the squares of those radii and of nothing else.the same, laid flatr = 4.3 mmλ = 9247 kNsquarer = 15.8 mmλ = 25397 kNtall rectangler = 57.7 mmλ = 691295 kNteer = 61.2 mmλ = 651454 kNI-sectionr = 90.0 mmλ = 443146 kNthe dashed pair is ±r about the centroidthe bar is the Euler load at 4 m, to scale
Fig. 1 Five profiles of equal area, with the radius of gyration drawn as the distance it is: a pair of lines either side of the centroid, at the depth the whole area would have to sit at to give the section the second moment it actually has. As a 4 m pin-ended column, the same 3,000 mm² of steel carries between 7 and 3,146 kN.

Why only one property gets through

The Euler load is Pcr=π2EI/L2P_{cr} = \pi^2 EI / L^2, which contains II and not rr, so it is fair to ask where the radius of gyration comes in at all.

It comes in the moment the question becomes which failure arrives first. A column has two limits: it crushes at Py=AfyP_y = A f_y, and it buckles at π2EI/L2\pi^2 EI/L^2. Divide both by the area to turn them into stresses:

σsquash=fy,σcr=π2EIAL2=π2E(L/r)2\sigma_{squash} = f_y, \qquad \sigma_{cr} = \frac{\pi^2 E I}{A L^2} = \frac{\pi^2 E}{(L/r)^2}

and the section has vanished. What is left is EE, which is a material, and L/rL/r, which is a single number called the slenderness. Two columns with the same slenderness fail at the same stress whatever their shapes, whatever their sizes, whatever their areas.

The column curveFailure load against slenderness, as a fraction of the squash load. A stocky column crushes; a slender one buckles at the Euler load; the crossover is where the two curves meet, and real columns fall below both near it.5010015020000.20.40.60.811.2slenderness (effective length ÷ radius of gyration)they cross at λ = 76squashingEuler bucklingreal columns, which are neither
Fig. 2 The column curve, which is the whole of the above drawn: squash stress and Euler stress against slenderness, with the lower governing. The horizontal axis is L/r and nothing else, which is why every column in the world can be put on one picture.

That reduction is worth pausing on because it is unusually complete. A beam needs II for deflection, ZZ for strength, ZZ again for the other face if the section is asymmetric, the shear area for the shear check, and the shear centre if it might twist. A column needs a length.

What the length is

r=I/Ar = \sqrt{I/A} has an interpretation that makes it far less arbitrary than the formula suggests.

Take all the material in the section and imagine it condensed into two equal lumps, symmetrically placed either side of the centroid. Put them at ±d\pm d. Their second moment is Ad2A d^2. Ask what dd gives the same second moment as the real section, and

Ad2=I    d=I/A=rA d^2 = I \implies d = \sqrt{I/A} = r

So the radius of gyration is the distance at which the whole area would have to sit to be as stiff as the real section is. It is a summary of how far away the material is, measured in the only way a second moment cares about — root mean square distance from the axis.

Every strip counts by the square of its distanceA rectangular section divided into equal strips, with each strip's contribution to the second moment of area drawn beside it. The strips are identical in size; only their distance from the neutral axis differs.neutral axiscontribution of each striptotal I = 79.86 × 10⁶the outer strips do almost all of the work
Fig. 3 The construction that gives the number its meaning: each strip’s area times the square of its distance from the axis. The radius of gyration is the root-mean-square of those distances, weighted by area — a single length standing for a whole distribution.
Moving the flanges apartThe second moment of area of an I-section against its depth, with the flange and web areas held constant. The growth is close to quadratic, because the parallel-axis term dominates everything the flanges contribute about their own centres.1001502002503000M10M20M30M40M50M60Moverall depth1.0×2.6×4.9×7.9×13.8×21.3×same steel, moved apart
Fig. 4 And the theorem that makes the distances count. Moving a flange outward raises II as the square of the distance and leaves the area alone, so it raises rr linearly — which is the sense in which making a section deeper is exactly making its column better.

For simple shapes it comes out as a fixed fraction of a dimension, and the fractions are worth having by heart:

section r, about the strong axis
solid rectangle, depth hh h/12=0.289hh/\sqrt{12} = 0.289h
solid circle, diameter DD D/4=0.250DD/4 = 0.250D
thin ring, diameter DD D/22=0.354DD/2\sqrt{2} = 0.354D
I-section, depth hh about 0.42h0.42h
I-section, about its minor axis, width bb about 0.22b0.22b

Every one of them is a fraction of a dimension of the section, and none is far from a quarter. That is why designers can estimate slenderness from a drawing: an I-section 300 mm deep has rxr_x near 125 mm, and a 6 m length of it is at a slenderness of about 48 without opening a catalogue.

The section that is worse as a beam is better as a column

The tee and the rectangle in the hero figure have the same area, 3,000 mm², and the same depth, 200 mm.

rectangle tee
II 10.00×10610.00 \times 10^6 11.23×10611.23 \times 10^6
ZminZ_{\min} 100.0×103100.0 \times 10^3 75.3×10375.3 \times 10^3
rr 57.7 mm 61.2 mm

As a beam the tee is a quarter weaker, because its centroid has moved toward the flange and the far fibre is now further away. As a column it is six per cent better, because the same movement of material raised the second moment and the area did not change.

The reason the two rankings differ is exactly one division. Strength is I/cmaxI/c_{\max} and stiffness-in-compression is I/AI/A; concentrating material near one face raises II, raises cmaxc_{\max}, and leaves AA alone. So it helps one ratio and hurts the other.

Bending is a push and a pull on a lever arm, and the lever arm reaches to the furthest fibre; compression has neither. A column has no extreme fibre. Nothing about compression buckling asks how far the furthest material is from the axis, only how far the average material is — and that is the whole of the difference.

A section modulus for each face, and only the smaller one is a strengthThree profiles of equal area with the second moment divided by BOTH distances to an extreme fibre rather than by the larger of them. A symmetric section has one section modulus and an asymmetric one has two, differing here by as much as 2.92 to one — so the same member has two bending strengths, and which of them applies is decided by the sign of the moment rather than by anything about the section. The bar is the smaller of the two, which is the one that governs when the moment can go either way.tall rectangleZ top 100.0 × 10³Z bottom 100.0 × 10³the same both waysteeZ top 220.1 × 10³Z bottom 75.3 × 10³2.92 : 1I-sectionZ top 242.9 × 10³Z bottom 242.9 × 10³the same both waysthe two solid lines are the extreme fibresthe bar is the smaller section modulus, to scale
Fig. 5 The beam ranking of the same shapes, by section modulus. The tee is behind the rectangle here and ahead of it in the hero figure, at the same weight and the same depth — two orderings from one second moment, divided by different things.

The range, and what it costs

Across the five shapes of equal area, rr runs from 4.33 mm to 89.98 mm — a factor of 20.8. As a 4 m pin-ended column the Euler loads therefore run from 7 kN to 3,146 kN, a factor of 432, because the load goes as r2r^2.

Nothing about the amount of material changed anywhere in that range. It is the same 3,000 mm² of steel, and the difference between the worst arrangement and the best is nearly three orders of magnitude of load — which is the geometry-beats-material argument at its most extreme anywhere in this collection.

The same material, five waysFive cross-sections of identical area, so identical weight and cost, with the second moment of area computed from each profile's own geometry. Only the arrangement differs, and the stiffest is many times the flattest.the same, laid flatI = 0.06 × 10⁶1.0× the firstsquareI = 0.75 × 10⁶13.3× the firsttall rectangleI = 10.00 × 10⁶177.8× the firstteeI = 11.22 × 10⁶199.6× the firstI-sectionI = 24.29 × 10⁶431.8× the firstevery section here has an area of 3000 — only the shape differsthe bar is the second moment of area, to scale
Fig. 6 The same five, ranked by second moment of area. It is the same ranking as the hero figure and by the same factor — since the areas are equal, r2r^2 and II differ by a constant, and the two pictures are one picture with different axes.
Length costs more than it looksThe same column section at four lengths, with the buckling capacity of each drawn as a bar. Capacity falls as the inverse square of the length, so a column three times as long carries a ninth as much.1× the length100% of the capacity1.5× the length44% of the capacity2× the length25% of the capacity3× the length11% of the capacityidentical section, identical material, identical end conditions
Fig. 7 And the other half of the slenderness, which costs the same way. Capacity goes as the inverse square of the length exactly as it goes as the square of the radius — so a column three times as long, or with a third of the radius of gyration, carries a ninth as much.

The smaller radius is the only one that matters

A section has a radius of gyration about every axis through its centroid, and it has a smallest one.

Loaded straight down, and moving sidewaysAn equal angle with a moment applied about the horizontal axis. Its principal axes lie at 45.0° to the drawn ones, so the neutral axis runs at -30.6° rather than horizontally, and the section moves 59% as far sideways as it moves down. The product of inertia that causes it is -1.066 × 10⁶ mm⁴, and it is zero for every section drawn in this field until now.the axis the drawing suggestsneutral axis, -30.6°it moves this wayprincipal axes at 45.0° · I₁/I₂ = 3.90
Fig. 8 Every section has principal axes, and the radius of gyration takes its extreme values on them. An angle’s are at 45° to the legs, which is why a single-angle strut buckles diagonally — the direction is not a choice and is not the direction anything was applied in.

An I-section chosen for bending is a poor column and the arithmetic says how poor. Its second moment about the minor axis is a small fraction of the major one, so ryr_y is a small fraction of rxr_x, and a member with a slenderness of 45 about the axis it was chosen for has 100 or more about the axis nobody looked at. That is how a member strong enough for its load falls over anyway.

The consequences are entirely practical. A column section is a different shape from a beam section — square hollow sections, circular hollow sections, and universal columns whose flanges are as wide as they are deep, rather than universal beams. And a beam pressed into service as a column needs restraint about its minor axis, which is the brace that need not be strong doing its familiar job of halving a length rather than adding a strength.

The ends decide the length that mattersFour columns of identical height and section, buckling under four sets of end conditions. The effective length factor is the fraction of the column that behaves like a pin-ended one, and the buckling load goes as its inverse square.K = 0.5both ends fixedK = 0.7one fixed, one pinnedK = 1both ends pinnedK = 2fixed at the base, free at the topsame column, same section, four ways of holding the endsthe load at which each buckles goes as 1 ÷ K² — a factor of sixteen across this row
Fig. 9 The other factor in the same ratio. Slenderness is Le/rL_e/r, and the effective length depends on what holds the ends — so improving a column is a choice between a better section, a shorter length and a better restraint, and the three are exchangeable at a fixed rate.

A third radius, for a mode that is not bending

The reduction to a single number is not quite complete, and the exception is worth stating because it is the one case where a section’s other properties come back.

A channel has three critical loads, not oneThe three critical loads of a channel in compression, against its length, with the load it actually buckles at drawn over them. At 3000 mm the flexural loads are 19014 kN about the major axis and 3139 kN about the minor, while twisting about the shear centre takes 1962 kN. The lowest root is 1879 kN, and the column twists. The shear centre sits 109.7 mm from the centroid, so the modes cannot happen separately: the lowest root of the coupled problem is 4.2 per cent below the lowest of the three, and the Wagner coefficient β is 0.60. The governing mode changes at 5813 mm: below that length the column twists, above it, it bends — because the torsional resistance keeps a term that does not grow when the member is shortened, and the flexural loads have none.4000600080001000012000140000500100015002000length of the column (mm)critical load (kN)flexural about ytorsionalflexural about zthe mode changes at 5813 mmthe lowest root — what the column actually does
Fig. 10 A channel has three critical loads. Two are flexural, about the two principal axes, and use the two radii of gyration; the third is torsional, about the shear centre, and uses the torsion constant, the warping constant and the polar radius of gyration about the shear centre. The lowest of the three governs, and here it is the twist.

For a section whose shear centre is not at its centroid — a channel, an angle, a tee, any singly symmetric shape — the flexural and torsional modes couple, and the governing critical load is below the lowest of the three uncoupled ones. The quantity that decides it is the polar radius of gyration about the shear centre, which is a fourth length and involves the distance between the two centres.

So the honest statement is: a doubly symmetric section takes one length into a column; anything else takes three or four. The single-number reduction holds for the sections most columns are made of, and fails for exactly the sections that are not.

Making the radius larger without adding material

The last consequence is the one that produced a whole family of members.

Since rr rewards distance and AA does not, a section can be improved as a column by moving its material apart — and if the material is moved apart far enough, the pieces stop being one section and become two chords joined by something.

The chords can be moved apart for ever and the answer stops movingCritical load against the spacing of the two chords, with the lacing at a constant 60°. The Euler load rises with the square of the spacing because the chords are lever arms; the shear stiffness of the lattice does not rise at all, because at a fixed angle every length in the lacing scales together and the stiffness is scale-free. Their harmonic sum therefore runs into a ceiling at 31500 kN, and the spacing at which the column has spent half of what it will ever get is 1478 mm.50010001500200025003000020000400006000080000100000120000spacing of the chords (mm)critical load (kN)Euler, P_Elattice, S_vthe columnceiling 31500 kN
Fig. 11 Where that ends: a column built out of two columns, whose radius of gyration is essentially half the spacing of its chords and can be made as large as the connections allow. The Euler load climbs with the square of the spacing exactly as r2r^2 says it should — and runs into a ceiling that has nothing to do with the section at all.

That figure is the proper end of this essay’s argument. The radius of gyration is the whole of what a column knows about its section, so the way to make a better column is to make rr bigger; and pushed to its limit, that instruction stops being about sections and becomes about lattices.

Where the quantity came from

The radius of gyration is borrowed, and the borrowing shows in the name.

It arrives from dynamics, where a rigid body rotating about an axis has a moment of inertia Im=mr2I_m = \sum m r^2 and the radius of gyration is the distance at which the whole mass would give the same moment of inertia. The second moment of area is the same sum with area in place of mass, and it appears in bending for a completely different reason — it is the integral of y2dAy^2\,dA that turns a linear stress distribution into a couple, and nothing in that derivation is rotating.

Two quantities with the same algebra and no shared physics, sharing a name and a symbol. This collection has met the pattern before, and it is worth naming again: the word “inertia” in “moment of inertia of a section” is a fossil, and a reader who takes it literally spends some time looking for the motion.

What the borrowing did supply is the summary idea. A distribution of area about an axis is a complicated object; the second moment collapses it to one number, and dividing by the area collapses it to one length, which can be compared with the member’s own length. That comparison is the whole of column design, and it was not available until somebody noticed that the ratio of two lengths was the governing variable.

The intervening history is instructive about what a good variable is worth. Euler published the buckling load in 1744 and it was widely disbelieved, because it predicts an infinite capacity for a short column and real short columns crush. Rankine and Gordon’s formula of the 1860s, which combines the two limits into 1/P=1/Py+1/Pcr1/P = 1/P_y + 1/P_{cr}, was the practical answer for the best part of a century — and it works precisely because it is a function of L/rL/r alone. Every empirical column formula of that period is a curve on the same axis, and the axis is this quantity.

Note the shape of that combination, incidentally: two capacities in series, the smaller governing, exactly as the built-up column’s two stiffnesses add as flexibilities rather than as strengths. It is the same arithmetic doing the same job in two places a century apart.

Where the model stops

rr is elastic. The reduction to L/rL/r comes from the Euler load, which assumes the material is still on its elastic modulus. A stocky column yields first, at which point the governing stiffness is a tangent modulus and the column has already partly failed before it was loaded.

The area in I/A\sqrt{I/A} is the gross area. A section with holes has a smaller area and, usually, a smaller second moment, and the two do not shrink in the same proportion — so the net section that decides the tension capacity is not the section that decides the slenderness.

And a slenderness is only meaningful with an effective length beside it. L/rL/r where LL is the member’s own length is a number about a pin-ended column and nothing else; every real column needs the LeL_e its restraints deserve, and getting that wrong moves the answer far more than any choice of section does.

What the pictures cannot show

The hero figure draws rr as a pair of dashed lines either side of the centroid, which is the honest geometric reading and looks like an edge of something. There is no material at that distance in any of the five sections; it is where the material would have to be.

Nor can any of these figures show that the ranking they draw is for one axis of each section. The I-section, which is best by a wide margin in every picture here, is the worst of the five about its own minor axis — and that is the axis its column would buckle about.

The ladder from here

Later rungs on this anchor: the polar radius of gyration and the torsional modes that need it. The effective radius of a built-up section, and why a code adds a term to the slenderness of a laced column rather than letting the geometry speak. The slenderness limits that appear in design codes as absolute numbers — 180, 250 — which are not calculations at all but conventions about handling, transport and vibration. Local slenderness, b/tb/t, which is the same idea applied to a plate rather than a member and decides whether the section can reach its own strength. And the historical case: Euler published in 1744, Lamarle showed in 1845 which of the two limits applies where, and the intervening century of empirical column formulae was spent inventing the quantity this essay is about.

Named alongside this one

Essays reaching for the same objects. Nobody chose these; they are what the concept index makes visible.

What links here

Every essay whose body links to this one.

The objects this essay names

Each one links to every other essay that touches it.

Asymmetric sectionBucklingBuilt up columnBuilt up sectionEffective lengthEuler loadMinor axisPrincipal axesRadius of gyrationSecond moment of areaSection shapeSlendernessSquash loadTorsional buckling