Sections and stress

The one length a section takes into a column

A section has an area, a second moment, two section moduli, a shear centre and a torsion constant. A column has heard of exactly one of them, and it is none of those — it is the length √(I/A), which is where the whole area would have to sit to give the section the stiffness it has.

Assumes The material far from the middle does nearly all the work, Strong enough and still falls over and The ends decide the length that matters.

A cross-section is a rich object. It has an area, a centroid, a second moment about every axis through that centroid, a product of inertia, two section moduli, a plastic modulus, a shear centre, a torsion constant, a warping constant. Bending uses several of them. Shear uses another. Torsion uses two more.

A column uses one, and it is not on that list. It is r=I/Ar = \sqrt{I/A}, a length, and every other property of the section reaches a column only through it.

The one length a section carries into a column. Five profiles of equal area, with the radius of gyration r = √(I/A) drawn as the distance it is — a pair of lines either side of the centroid, at the depth the whole area would have to sit at to give the section the second moment it has. As a 4 m pin-ended column the same 3000 mm² of material carries between 7 and 3146 kN, in the ratio of the squares of those radii and of nothing else.
Fig. 1 Five profiles of equal area, with the radius of gyration drawn as the distance it is: a pair of lines either side of the centroid, at the depth the whole area would have to sit at to give the section the second moment it actually has. As a 4 m pin-ended column, the same 3,000 mm² of steel carries between 7 and 3,146 kN.

Why only one property gets through

The Euler load is Pcr=π2EI/L2P_{cr} = \pi^2 EI / L^2, which contains II and not rr, so it is fair to ask where the radius of gyration comes in at all.

It comes in the moment the question becomes which failure arrives first. A column has two limits: it crushes at Py=AfyP_y = A f_y, and it buckles at π2EI/L2\pi^2 EI/L^2. Divide both by the area to turn them into stresses:

σsquash=fy,σcr=π2EIAL2=π2E(L/r)2\sigma_{squash} = f_y, \qquad \sigma_{cr} = \frac{\pi^2 E I}{A L^2} = \frac{\pi^2 E}{(L/r)^2}

and the section has vanished. What is left is EE, which is a material, and L/rL/r, which is a single number called the slenderness. Two columns with the same slenderness fail at the same stress whatever their shapes, whatever their sizes, whatever their areas.

The column curve. Failure load against slenderness, as a fraction of the squash load. A stocky column crushes; a slender one buckles at the Euler load; the crossover is where the two curves meet, and real columns fall below both near it.
Fig. 2 The column curve, which is the whole of the above drawn: squash stress and Euler stress against slenderness, with the lower governing. The horizontal axis is L/r and nothing else, which is why every column in the world can be put on one picture.

That reduction is worth pausing on because it is unusually complete. A beam needs II for deflection, ZZ for strength, ZZ again for the other face if the section is asymmetric, the shear area for the shear check, and the shear centre if it might twist. A column needs a length.

What the length is

r=I/Ar = \sqrt{I/A} has an interpretation that makes it far less arbitrary than the formula suggests.

Take all the material in the section and imagine it condensed into two equal lumps, symmetrically placed either side of the centroid. Put them at ±d\pm d. Their second moment is Ad2A d^2. Ask what dd gives the same second moment as the real section, and

Ad2=I  ⟹  d=I/A=rA d^2 = I \implies d = \sqrt{I/A} = r

So the radius of gyration is the distance at which the whole area would have to sit to be as stiff as the real section is. It is a summary of how far away the material is, measured in the only way a second moment cares about — root mean square distance from the axis.

The construction underneath it is the ordinary one: each strip’s area times the square of its distance from the axis, summed. What the division by AA adds is that the sum becomes a root-mean-square of those distances rather than a total of them — a single length standing for a whole distribution, and one that does not grow when the section does. And because moving material outward raises II as the square of the distance while leaving the area alone, it raises rr linearly: making a section deeper is exactly making its column better, at a rate of one for one.

The same material, five ways. Five cross-sections of identical area, so identical weight and cost, with the second moment of area computed from each profile's own geometry. Only the arrangement differs, and the stiffest is many times the flattest.
Fig. 3 The same five profiles ranked by second moment of area, which for equal areas is the same ranking as by r2r^2 and differs from it by a constant. Identical area means identical weight and identical cost; only the arrangement differs, and the stiffest is many times the flattest.

For simple shapes it comes out as a fixed fraction of a dimension, and the fractions are worth having by heart:

section r, about the strong axis
solid rectangle, depth hh h/12=0.289hh/\sqrt{12} = 0.289h
solid circle, diameter DD D/4=0.250DD/4 = 0.250D
thin ring, diameter DD D/22=0.354DD/2\sqrt{2} = 0.354D
I-section, depth hh about 0.42h0.42h
I-section, about its minor axis, width bb about 0.22b0.22b

Every one of them is a fraction of a dimension of the section, and none is far from a quarter. That is why designers can estimate slenderness from a drawing: an I-section 300 mm deep has rxr_x near 125 mm, and a 6 m length of it is at a slenderness of about 48 without opening a catalogue.

The section that is worse as a beam is better as a column

The tee and the rectangle in the hero figure have the same area, 3,000 mm², and the same depth, 200 mm.

rectangle tee
II 10.00×10610.00 \times 10^6 11.23×10611.23 \times 10^6
Zmin⁡Z_{\min} 100.0×103100.0 \times 10^3 75.3×10375.3 \times 10^3
rr 57.7 mm 61.2 mm

As a beam the tee is a quarter weaker, because its centroid has moved toward the flange and the far fibre is now further away. As a column it is six per cent better, because the same movement of material raised the second moment and the area did not change.

The reason the two rankings differ is exactly one division. Strength is I/cmax⁡I/c_{\max} and stiffness-in-compression is I/AI/A; concentrating material near one face raises II, raises cmax⁡c_{\max}, and leaves AA alone. So it helps one ratio and hurts the other.

Bending is a push and a pull on a lever arm, and the lever arm reaches to the furthest fibre; compression has neither. A column has no extreme fibre. Nothing about compression buckling asks how far the furthest material is from the axis, only how far the average material is — and that is the whole of the difference.

The one length a section carries into a column. Two profiles of equal area, with the radius of gyration r = √(I/A) drawn as the distance it is — a pair of lines either side of the centroid, at the depth the whole area would have to sit at to give the section the second moment it has. As a 4 m pin-ended column the same 3000 mm² of material carries between 1295 and 1454 kN, in the ratio of the squares of those radii and of nothing else.
Fig. 4 The same two profiles alone, with each one’s radius of gyration drawn where it falls. As 4 m pin-ended columns the rectangle carries 1,295 kN and the tee 1,454 — the tee ahead by 12% on the load, which is the 6% on rr squared. The section a beam designer would reject is the one a column designer would choose.

Put the same two on the beam ranking and the order reverses, without a single number about either section changing.

A section modulus for each face, and only the smaller one is a strength. Three profiles of equal area with the second moment divided by BOTH distances to an extreme fibre rather than by the larger of them. A symmetric section has one section modulus and an asymmetric one has two, differing here by as much as 2.92 to one — so the same member has two bending strengths, and which of them applies is decided by the sign of the moment rather than by anything about the section. The bar is the smaller of the two, which is the one that governs when the moment can go either way.
Fig. 5 The beam ranking of the same shapes, by section modulus. The tee is behind the rectangle here and ahead of it in the hero figure, at the same weight and the same depth — two orderings from one second moment, divided by different things.

The range, and what it costs

Across the five shapes of equal area, rr runs from 4.33 mm to 89.98 mm — a factor of 20.8. As a 4 m pin-ended column the Euler loads therefore run from 7 kN to 3,146 kN, a factor of 432, because the load goes as r2r^2.

Nothing about the amount of material changed anywhere in that range. It is the same 3,000 mm² of steel, and the difference between the worst arrangement and the best is nearly three orders of magnitude of load — which is the geometry-beats-material argument at its most extreme anywhere in this collection.

The length costs in the same currency, and the arithmetic is the same arithmetic. Capacity goes as the inverse square of the length exactly as it goes as the square of the radius, so a column three times as long, or with a third of the radius of gyration, carries a ninth as much. Doubling the length is therefore indistinguishable from halving rr, and the picture says so.

The one length a section carries into a column. Five profiles of equal area, with the radius of gyration r = √(I/A) drawn as the distance it is — a pair of lines either side of the centroid, at the depth the whole area would have to sit at to give the section the second moment it has. As a 8 m pin-ended column the same 3000 mm² of material carries between 2 and 787 kN, in the ratio of the squares of those radii and of nothing else.
Fig. 6 The same five sections, unchanged, as 8 m pin-ended columns instead of 4 m. Every radius of gyration on the drawing is exactly what it was; the loads have fallen from 7–3,146 kN to 2–787, a quarter of each, because the only thing that moved was the square of the length. The ratio between best and worst is untouched at 432 to one.

The same length generates the kern

The radius of gyration is not confined to columns, and the place it turns up next is one this collection has already visited under a different name.

The kern is the region within which the resultant of a compression must fall if no part of the section is to be pulled, and its boundary sits at Z/AZ/A from the centroid in each direction. Substituting Z=I/cZ = I/c:

k=ZA=IAc=r2ck = \frac{Z}{A} = \frac{I}{Ac} = \frac{r^2}{c}

The kern distance is the radius of gyration squared, divided by the distance to the opposite extreme fibre. For a rectangle, r2=h2/12r^2 = h^2/12 and c=h/2c = h/2, so k=h/6k = h/6 — the middle third, arrived at from a column property. For a thin ring, r2=D2/8r^2 = D^2/8 and c=D/2c = D/2, so k=D/4k = D/4, and the generous kern of a chimney is a consequence of its generous radius of gyration.

The relation is worth having for what it says about the two quantities. They are the same information read for two purposes: rr measures how far the material is from the axis in a root-mean-square sense, and cc measures how far the furthest material is. Their ratio decides how much eccentricity a no-tension section tolerates, and their absolute values decide how a column behaves — so a shape that is good as a column is, by the same arithmetic, a shape with a generous kern.

It also connects the two subjects on one member. A column carrying its load at an eccentricity ee has no tension anywhere provided e<r2/ce < r^2/c — and a slender column bends, which adds its own deflection to ee. So a column that starts inside its kern can leave it as it deflects, and the section that was wholly in compression at the ends is not at mid-height. For a material that can be pulled this is a stress question; for masonry it is a contact question, and the same r2/cr^2/c decides both.

Which explains a pairing that looks like a coincidence in the catalogue. A circular hollow section is the best common shape as a column and the best common shape for an eccentrically loaded masonry-like member, and it is both for one reason: it has the largest rr for its outline and its cc is no larger than anything else’s.

The axis every code plots against

There is a second reduction on top of the first, and it is the one that lets a single curve serve every material.

The two limits cross where the squash stress equals the Euler stress:

fy=π2E(L/r)2⟹λ1=πEfyf_y = \frac{\pi^2E}{(L/r)^2} \quad\Longrightarrow\quad \lambda_1 = \pi\sqrt{\frac{E}{f_y}}

which is 93.9 for S235 steel, 76.4 for S355, and 67.1 for S460. It contains no section: it is a property of the material alone, and it is the slenderness at which the shape stops deciding and the strength starts.

So the two variables separate cleanly. The section enters through rr and nothing else; the material enters through λ1\lambda_1 and nothing else; and the ratio

λˉ=Le/rλ1=AfyNcr\bar\lambda = \frac{L_e/r}{\lambda_1} = \sqrt{\frac{A f_y}{N_{cr}}}

is dimensionless in both — the second form being the one codes write, and being the square root of the ratio of the two capacities the first form compares. Every modern column curve is plotted against that quantity, with 1.0 at the crossover, and one picture then serves every steel and every profile.

Two things follow that are worth stating plainly. The ratio, not the slenderness, is what a designer should carry. A slenderness of 80 is stocky in mild steel and slender in a high-strength grade, and quoting it without the grade says nothing. And the normalisation is why the design curves look like curves rather than a corner: with the two straight-line limits scaled to meet at λˉ=1\bar\lambda = 1, everything the real data does — the imperfections, the residual stresses, the rounding of the knee — shows up as a single family of curves in the neighbourhood of one, which is the only region a test programme needs to cover.

It is a small piece of bookkeeping and it is the reason a column can be designed from a table rather than from an argument.

The smaller radius is the only one that matters

A section has a radius of gyration about every axis through its centroid, and it has a smallest one.

Loaded straight down, and moving sideways. An equal angle with a moment applied about the horizontal axis. Its principal axes lie at 45.0° to the drawn ones, so the neutral axis runs at -30.6° rather than horizontally, and the section moves 59% as far sideways as it moves down. The product of inertia that causes it is -1.066 × 10⁶ mm⁴, and it is zero for every section drawn in this field until now.
Fig. 7 Every section has principal axes, and the radius of gyration takes its extreme values on them. An angle’s are at 45° to the legs, which is why a single-angle strut buckles diagonally — the direction is not a choice and is not the direction anything was applied in.

An I-section chosen for bending is a poor column and the arithmetic says how poor. Its second moment about the minor axis is a small fraction of the major one, so ryr_y is a small fraction of rxr_x, and a member with a slenderness of 45 about the axis it was chosen for has 100 or more about the axis nobody looked at. That is how a member strong enough for its load falls over anyway.

The consequences are entirely practical. A column section is a different shape from a beam section — square hollow sections, circular hollow sections, and universal columns whose flanges are as wide as they are deep, rather than universal beams. And a beam pressed into service as a column needs restraint about its minor axis, which is the brace that need not be strong doing its familiar job of halving a length rather than adding a strength.

Which puts the other factor of the same ratio into view. Slenderness is Le/rL_e/r, and the effective length depends on what holds the ends, so improving a column is a choice between a better section, a shorter length and a better restraint — three routes to one number, exchangeable at a fixed rate, and the cheapest of them is usually not the section.

A third radius, for a mode that is not bending

The reduction to a single number is not quite complete, and the exception is worth stating because it is the one case where a section’s other properties come back.

A channel has three critical loads rather than one. Two are flexural, about the two principal axes, and use the two radii of gyration this page is about; the third is torsional, about the shear centre, and uses the torsion constant, the warping constant and the polar radius of gyration about that centre. The lowest of the three governs, and on a channel of ordinary proportions it is the twist.

For a section whose shear centre is not at its centroid — a channel, an angle, a tee, any singly symmetric shape — the flexural and torsional modes couple, and the governing critical load is below the lowest of the three uncoupled ones. The quantity that decides it is the polar radius of gyration about the shear centre, which is a fourth length and involves the distance between the two centres.

So the honest statement is: a doubly symmetric section takes one length into a column; anything else takes three or four. The single-number reduction holds for the sections most columns are made of, and fails for exactly the sections that are not.

Making the radius larger without adding material

The last consequence is the one that produced a whole family of members.

Since rr rewards distance and AA does not, a section can be improved as a column by moving its material apart — and if the material is moved apart far enough, the pieces stop being one section and become two chords joined by something.

Where that ends is a column built out of two columns, whose radius of gyration is essentially half the spacing of its chords and can be made as large as the connections allow. The Euler load climbs with the square of the spacing exactly as r2r^2 says it should — and then runs into a ceiling that has nothing to do with the section at all, because the lacing that holds the chords apart has a stiffness of its own and it is that stiffness the member eventually fails on.

That limit is the proper end of this essay’s argument. The radius of gyration is the whole of what a column knows about its section, so the way to make a better column is to make rr bigger; and pushed to its limit, that instruction stops being about sections and becomes about lattices.

Where the quantity came from

The radius of gyration is borrowed, and the borrowing shows in the name.

It arrives from dynamics, where a rigid body rotating about an axis has a moment of inertia Im=∑mr2I_m = \sum m r^2 and the radius of gyration is the distance at which the whole mass would give the same moment of inertia. The second moment of area is the same sum with area in place of mass, and it appears in bending for a completely different reason — it is the integral of y2 dAy^2\,dA that turns a linear stress distribution into a couple, and nothing in that derivation is rotating.

Two quantities with the same algebra and no shared physics, sharing a name and a symbol. This collection has met the pattern before, and it is worth naming again: the word “inertia” in “moment of inertia of a section” is a fossil, and a reader who takes it literally spends some time looking for the motion.

What the borrowing did supply is the summary idea. A distribution of area about an axis is a complicated object; the second moment collapses it to one number, and dividing by the area collapses it to one length, which can be compared with the member’s own length. That comparison is the whole of column design, and it was not available until somebody noticed that the ratio of two lengths was the governing variable.

The intervening history is instructive about what a good variable is worth. Euler published the buckling load in 1744 and it was widely disbelieved, because it predicts an infinite capacity for a short column and real short columns crush. Rankine and Gordon’s formula of the 1860s, which combines the two limits into 1/P=1/Py+1/Pcr1/P = 1/P_y + 1/P_{cr}, was the practical answer for the best part of a century — and it works precisely because it is a function of L/rL/r alone. Every empirical column formula of that period is a curve on the same axis, and the axis is this quantity.

Note the shape of that combination, incidentally: two capacities in series, the smaller governing, exactly as the built-up column’s two stiffnesses add as flexibilities rather than as strengths. It is the same arithmetic doing the same job in two places a century apart.

Where the model stops

rr is elastic. The reduction to L/rL/r comes from the Euler load, which assumes the material is still on its elastic modulus. A stocky column yields first, at which point the governing stiffness is a tangent modulus and the column has already partly failed before it was loaded.

The one length a section carries into a column. Five profiles of equal area, with the radius of gyration r = √(I/A) drawn as the distance it is — a pair of lines either side of the centroid, at the depth the whole area would have to sit at to give the section the second moment it has. As a 2 m pin-ended column the same 3000 mm² of material carries between 29 and 12585 kN, in the ratio of the squares of those radii and of nothing else.
Fig. 8 The same five sections at 2 m, where the reduction quietly stops meaning anything. The Euler loads run from 29 to 12,585 kN, and 3,000 mm² at 355 N/mm² squashes at 1,065 — so only the flat is still an Euler column, and the best of the five is being credited with nearly twelve times a load its material cannot reach. Every radius of gyration on the drawing is correct and four of the five numbers beside them are fiction.

The area in I/A\sqrt{I/A} is the gross area. A section with holes has a smaller area and, usually, a smaller second moment, and the two do not shrink in the same proportion — so the net section that decides the tension capacity is not the section that decides the slenderness.

And a slenderness is only meaningful with an effective length beside it. L/rL/r where LL is the member’s own length is a number about a pin-ended column and nothing else; every real column needs the LeL_e its restraints deserve, and getting that wrong moves the answer far more than any choice of section does.

What the pictures cannot show

The hero figure draws rr as a pair of dashed lines either side of the centroid, which is the honest geometric reading and looks like an edge of something. There is no material at that distance in any of the five sections; it is where the material would have to be.

Nor can any of these figures show that the ranking they draw is for one axis of each section. The I-section, which is best by a wide margin in every picture here, is the worst of the five about its own minor axis — and that is the axis its column would buckle about.

The ladder from here

Later rungs on this anchor: the polar radius of gyration and the torsional modes that need it. The effective radius of a built-up section, and why a code adds a term to the slenderness of a laced column rather than letting the geometry speak. The slenderness limits that appear in design codes as absolute numbers — 180, 250 — which are not calculations at all but conventions about handling, transport and vibration. Local slenderness, b/tb/t, which is the same idea applied to a plate rather than a member and decides whether the section can reach its own strength. And the historical case: Euler published in 1744, Lamarle showed in 1845 which of the two limits applies where, and the intervening century of empirical column formulae was spent inventing the quantity this essay is about.

Named alongside this one

Essays reaching for the same objects. Nobody chose these; they are what the concept index makes visible.

What links here

Every essay whose body links to this one.

The objects this essay names

Each one links to every other essay that touches it.

Asymmetric sectionBucklingBuilt-up columnBuilt-up sectionEffective lengthEuler loadMinor axisPrincipal axesRadius of gyrationSecond moment of areaSection shapeSlendernessSquash loadTorsional buckling