Materials

The material that has a direction

Every material in this collection so far has had one modulus and one strength. Timber has three of each, differing by more than an order of magnitude, and the consequence is not a correction to steel design — it is a different set of checks with a different one governing.

Assumes The one number a stronger steel does not change, The deflection that is not bending and The flaw that sets the strength.

Steel has one modulus and one yield stress. That is not a simplification made for teaching; it is very nearly exactly true, and it is the reason a steel section can be described by a handful of geometric properties and a grade.

Timber has three moduli, three strengths in compression, three in tension and three in shear, and the ratios between them run to thirty. What follows from that is not a correction to the arithmetic of a steel beam. It is a different arithmetic, with a different check governing and a limit state that steel design does not contain.

Strength at an angle, and the straight line that is not itCompressive strength against the angle between the load and the grain. Hankinson's formula — f₀f₉₀ ÷ (f₀sin²α + f₉₀cos²α) — is an interpolation rather than a failure theory, and what makes it worth having is how far it sits from the straight line anyone would otherwise draw between 21 and 2.5 N/mm². At forty-five degrees it gives 4.5 N/mm² against the line's 11.8: 38 per cent of it, and 21 per cent of the strength along the grain. The curve drops away in the first twenty degrees because the weak direction starts governing as soon as it has any component at all, which is the same arithmetic as a section's weak axis and the reason a skewed bearing detail is a real loss rather than a small one.02040608005101520angle to the grain (degrees)strength (N/mm²)Hankinsona straight linetension4.47 at 45°, not 11.821 per cent of the strength along the grain, at half a right angle
Fig. 1 Compressive strength against the angle between the load and the grain. Hankinson’s formula gives 4.47 N/mm² at forty-five degrees against the 11.75 a straight line between the two extremes would predict — 38 per cent of it. The curve leaves the parallel value almost immediately, because the interpolation happens in the reciprocals.

Which free body produced the number

Hankinson’s formula is

fα=f0f90f0sin2α+f90cos2αf_\alpha = \frac{f_0\,f_{90}}{f_0\sin^2\alpha + f_{90}\cos^2\alpha}

and it is worth being honest about what it is: an interpolation that fits, not a failure theory. Nothing derives it, and its exponent is 2 for compression and closer to 1.5 or 2.5 for other actions depending on whose tests are being fitted.

What makes it worth using is the shape. At forty-five degrees, where sin2=cos2=12\sin^2 = \cos^2 = \tfrac12, it collapses to

f45=2f0f90f0+f90f_{45} = \frac{2f_0f_{90}}{f_0 + f_{90}}

the harmonic mean of the two strengths — which for 21 and 2.5 N/mm² is 4.47. A harmonic mean is dominated by the smaller of its arguments in a way an arithmetic mean is not, and that is the entire content of the formula: in a material with a weak direction, having any component in the weak direction is most of the way to being in the weak direction.

That is the same arithmetic as a biaxially bent section, where a five-degree tilt costs ninety per cent of the stress. Both are a small angle multiplying a large ratio.

Three moduli, and a logarithm to draw them on

The stiffnesses are as lopsided as the strengths and are less often discussed.

Three moduli and three strengths, on a scale that needs a logarithmThe properties of one piece of timber, drawn on a logarithmic axis because a linear one would put four of the six bars on the floor. The modulus along the grain is 30 times the modulus across it, the compressive strength 8.4 times, and the tensile strength 35 times. E over G is 16 against steel's 2.6, which is why the shear deflection that is a one per cent correction for a steel beam is six times that here. Every one of these differences is a limit state somewhere, and the smallest numbers are the ones that decide.E along11000E across370G690f_c along21f_c across2.5f_v410100100010000N/mm², logarithmicE along ÷ E across = 30 · f_c along ÷ f_c across = 8.4
Fig. 2 The properties of one piece of timber, on a logarithmic axis because a linear one would put four of the six bars on the floor. The modulus along the grain is 30 times the modulus across it, the compressive strength 8.4 times, and the tensile strength 35.

The number that does the most damage quietly is E/GE/G. For steel it is 2.6; for this timber it is 15.9.

Shear deflection is the term every beam calculation drops, and its size goes as E/GE/G times the square of the depth over the span. Six times the ratio means six times the term — so the correction that is worth one per cent on a rolled steel beam is worth six or more on a timber joist of the same proportions, and on a short deep one it is worth a great deal more than that.

Which means a timber beam’s deflection cannot be computed from its second moment alone, and the codes that govern it say so explicitly, with a shear term written into the serviceability check rather than mentioned in a footnote.

The check with no steel equivalent

Bearing across the grain is where a timber structure is usually decided, and it has no counterpart in steel design at all.

A support reaction arrives perpendicular to the member. In steel that is a stress against fyf_y and is never critical. In timber it is a stress against fc,90f_{c,90}, which is 2.5 N/mm² — a twelfth of the strength along the grain — and it is applied over whatever bearing length the detail happens to provide.

A short timber beam is a shear problem, and a steel one never isUtilisation of the bending and shear checks on one beam, against span-to-depth. The two cross where the ratio equals f_m ÷ f_v exactly — no load, no width and no span survives the cancellation — which for this timber is 6.0 and for steel is 1.73. So a timber beam shallower than about six times its depth is governed by shear parallel to the grain, and a steel beam would have to be shorter than twice its own depth before the same thing happened, which is not a beam. The third check is bearing across the grain, which does not move with the span at all: on the beam drawn it is at 0.38 and it is the one that governs.5101520253000.20.40.60.81span ÷ depthutilisationbendingshearbearing across the grainthey cross at 6.0f_m ÷ f_v = 6.0 for timber and 1.73 for steel
Fig. 3 Three checks on one joist, against span-to-depth. Bending and shear cross at exactly fm/fvf_m/f_v — no load, no width and no span survives the cancellation — which is 6.0 for this timber and 1.73 for steel. The third line is bearing, which does not move with the span at all, and on the beam drawn it is the check that governs.

The failure is not dramatic. The member crushes locally at the support, sinks a few millimetres into whatever it is bearing on, and stops — because crushing across the grain is a ductile mechanism with a long plateau, unlike almost everything else timber does. A “failed” bearing is a floor that has dropped at one end and is otherwise intact, which is why the limit state is written as a serviceability one in some codes and a strength one in others.

Shear governs a beam that steel would not

The crossover between bending and shear is a ratio of two strengths and nothing else.

The bending utilisation of a uniformly loaded rectangular beam is 0.75wL2/(bd2fm)0.75wL^2/(bd^2f_m); the shear utilisation is 0.75wL/(bdfv)0.75wL/(bd\,f_v). Setting them equal cancels the load, the width, and one power of the span, leaving

Ld=fmfv\frac{L}{d} = \frac{f_m}{f_v}

For this timber that is 6.0, and for grade 355 steel it is 1.73. So a timber joist shallower than six times its depth is governed by shear parallel to the grain — an ordinary lintel, a floor joist over a corridor, a beam trimming a stair — and a steel beam would have to be shorter than twice its own depth before the same thing happened, which is not a beam.

And shear parallel to the grain is the least forgiving failure timber has. It is a split running along the member, on the plane where the material is weakest, at a stress that arrives suddenly rather than after any visible warning. It is the reason notches in timber beams are treated with far more care than notches in steel ones: a notch at a support introduces a crack tip on exactly the plane the shear is trying to open.

Shear stress across a sectionThe distribution of shear stress over an I-section, computed as VQ/It by accumulating the first moment of the area above every height. The peak is 0.40 against a mean of 0.20 — a ratio of 1.98 — and it falls at the neutral axis, where the bending stress is zero.neutral axispeak 0.4stressflow, q = VQ ÷ Imean stress 0.20 — the value a shear divided by an area would givepeak 1.98× that, and in the place bending ignoresthe flow is continuous; the stress jumps wherever the width does
Fig. 4 The stress the split is on. Horizontal shear is the same VQ/IbVQ/Ib in timber as anywhere else — what is different is that the material has a plane of weakness lying exactly along it, so the stress that delaminates a glued laminated beam is a material property rather than a bond one.

What the direction actually is

Everything above treats “the grain” as a single direction, and timber has three.

There is the longitudinal direction along the fibres, the radial direction out from the centre of the tree, and the tangential direction round the growth rings. Longitudinal is very stiff and strong; the other two are weak and are not the same as each other — tangential shrinkage is about twice radial, which is why a plank cups as it dries and why the direction of the rings across a section decides which way it will move.

Structural design ignores the distinction and works with “parallel” and “perpendicular”, which is a decision rather than an approximation: the two perpendicular directions differ by a factor of two, and the design value is the worse of them.

The distinction reappears the moment moisture is involved. Shrinkage across the grain is of the order of a per cent for every four per cent change in moisture content, and along the grain it is negligible. A timber frame therefore moves in one direction only, by amounts that accumulate through every horizontal member in a wall, and the detailing rule that follows — keep the number of horizontal members in a load path small — is a consequence of anisotropy with no strength calculation anywhere in it.

Two materials pulled until they stopTwo stress-strain curves — mild steel, concrete — plotted to a strain of 2.0%. One of them has a plateau, so the stress at which yielding starts is something the specimen does rather than something anyone chooses. No offset construction is drawn.00.5%1%2%2%050100150200250300350strainstress, N/mm²mild steelconcrete
Fig. 5 Two isotropic materials, for the comparison. Neither has a direction, so neither needs a second modulus, a Hankinson formula, a bearing check or a moisture rule — and the whole of this essay is about what the third material needs that these two do not.

The section that is chosen for it

Because the properties are so unequal, timber’s structural geometry is not steel’s with different numbers in it. Three consequences show up in what gets built.

Sections are rectangular and deep. There is no timber I-section, because a flange would have to be connected to a web across the grain and the connection would be the weak link — so the whole of the section-shape argument that produces the I-beam is unavailable, and depth is bought directly.

Members are laminated. Glued laminated timber is a way of removing the defects that dominate the scatter: cut a plank into laminations, discard or finger-joint the worst, glue them back up, and the resulting member has a strength closer to the mean of many pieces than to the minimum of one. It is a statistical improvement rather than a material one, and it is why glulam design values are markedly higher than sawn timber’s for the same species.

And the plane of lamination is the plane of shear. A glulam beam’s glue lines run along its length, on exactly the plane the horizontal shear is trying to open — so the shear check on a laminated beam is a check on the material and on the manufacture at once, and a delamination and a shear split are the same failure with different causes.

Every strip counts by the square of its distanceA rectangular section divided into equal strips, with each strip's contribution to the second moment of area drawn beside it. The strips are identical in size; only their distance from the neutral axis differs.neutral axiscontribution of each striptotal I = 225.00 × 10⁶the outer strips do almost all of the work
Fig. 6 The property depth buys. With no flange available, a timber beam gets its second moment the expensive way — by being deep — which is also the direction that makes its shear check worse and its bearing check no better.

Where the same argument appears without timber

Anisotropy is not a timber problem. It is a property of any material made of aligned things, and there are three others in this collection wearing different names.

A corrugated web has an effective modulus along the girder of a thousandth of its modulus across it — an anisotropy ratio of a thousand, larger than any natural material’s, and produced entirely by geometry.

A reinforced concrete slab spanning one way is far stiffer and stronger in that direction than across it, which is why two-way spanning is a design decision rather than a description.

And a fibre composite is a manufactured version of the same thing, with the ratios chosen rather than inherited: a unidirectional laminate has an EE ratio of twenty or more, and the whole design method is about laying up plies so that the resulting orthotropy matches the load.

Which suggests the useful way to hold the idea. Anisotropy is not a defect of a natural material; it is the efficient answer whenever the loads have a direction. Timber is a cantilever optimised by evolution for wind, and every property in the bar chart above is a consequence of a tree not needing to be strong sideways.

Pull it along the girder and it just unfoldsOne period of a 30° trapezoidal corrugation, 300 mm of flat and 260 mm of incline, and the same period pulled along the girder's axis. The fold opens by bending the inclined panels out of the web's own plane, so the axial flexibility contains the plate's t³ where a flat web's would contain t — and the effective modulus that comes back from solving the cell as a frame is 222 N/mm², which is 10.6 parts in ten thousand of the steel's 210 GPa. A web with a thousandth of the stiffness carries a thousandth of the stress, which is why the flanges of a corrugated girder carry the whole moment and why the section has 9 per cent less second moment than the flat-webbed girder it replaces. The fold buys freedom from stiffeners and pays for it here.as builtthe same fold under axial pull, exaggeratedE along the girder = 222 N/mm², against 210 GPa for the plate itselfso the web takes 0.106% of the bending stress and all of the shear
Fig. 7 Anisotropy made on purpose. A corrugated web has a modulus ratio of a thousand between two directions in the same piece of steel, which is the same structural situation as timber’s arriving from geometry rather than from biology.

What the anisotropy is worth, which is a great deal

It would be easy to read all of the above as a list of difficulties, and it would be the wrong reading.

Measured along the grain, timber’s strength-to-weight ratio is comparable with structural steel’s and its stiffness-to-weight ratio is better than concrete’s. A material with a density of 420 kg/m³ carrying 21 N/mm² in compression is doing something no isotropic material of that weight does, and the reason it can is precisely that it has spent nothing on the two directions it does not need.

Anisotropy is what the efficiency is made of. An isotropic material with timber’s density and timber’s longitudinal properties does not exist, because making a material strong in three directions costs three times as much material as making it strong in one.

That reframes the design problem. The checks in this essay — the Hankinson collapse, the bearing limit, the early shear crossover — are not defects to be worked around; they are the bill for an efficiency that has already been taken. A designer’s job with an anisotropic material is to arrange the structure so that the loads arrive along the direction that was paid for, and every timber detailing rule worth knowing is a version of that instruction.

The same material, four waysFour cross-sections of identical area, so identical weight and cost, with the second moment of area computed from each profile's own geometry. Only the arrangement differs, and the stiffest is many times the flattest.the same, laid flatI = 0.07 × 10⁶1.0× the firstsquareI = 1.47 × 10⁶21.4× the firsttall rectangleI = 31.50 × 10⁶459.2× the firstI-sectionI = 64.68 × 10⁶942.8× the firstevery section here has an area of 4200 — only the shape differsthe bar is the second moment of area, to scale
Fig. 8 Comparing sections of equal area is the isotropic version of the same idea: put the material where the load is, and accept that the section is then poor in the direction nothing is asking about. Timber does at the scale of the fibre what an I-section does at the scale of the profile.

Cross-laminated timber, which is the anisotropy cancelled

The most interesting recent thing done with timber is to arrange it so that the direction stops mattering.

Cross-laminated timber is boards glued in alternating layers at right angles, and the effect is a panel with two comparable strong directions instead of one. What it buys is not strength — the crossing layers contribute almost nothing to bending in the other direction, so a five-layer panel is roughly three layers’ worth of material in each direction — but isotropy, which is what makes a panel rather than a beam possible.

The price is paid in shear, and it has a name: rolling shear. The crossing layers carry the panel’s shear across their own grain, on the plane where timber is weakest of all, and the strength there is a fraction of the already-low parallel value. So a cross-laminated panel is governed by shear at span-to-depth ratios where a solid timber beam would not be — the same crossover this essay computed, moved further along the axis by a material property that only exists because the layers cross.

The connection is busiest where the beam is notThe force per unit length the interface has to carry, along a 5 m span under a uniform load, with connectors of stiffness 300. It is largest at the supports and zero at mid-span, which is the shear diagram and not the moment diagram — so the studs go where the bending stress is smallest and the last thing a designer looks at is where the connection works hardest. The peak here is 155.4 against 187.5 for a fully bonded beam of the same section, the difference being that a partly composite beam does not have the full section's shear flow to carry. The total the connectors on one half of the span must transfer is 220.7 kN.010002000300040005000-150-100-50050100150along the span (mm)force per unit length at the interfacewhat the connectors carryVQ/I, if it were bonded
Fig. 9 The plane the crossing layers have to carry. In a solid beam the horizontal shear runs along the grain; in a cross-laminated panel it runs across it in every second layer, at a strength a fraction of the one this page has been calling low.

Where the model stops

Hankinson’s formula is a fit. It has no derivation, its exponent depends on the action being interpolated, and it is applied to compression, to bearing and to bolted connections with different exponents in different codes.

The properties here are characteristic values for one grade. Timber’s scatter is far wider than steel’s — a coefficient of variation of 20 to 30 per cent on strength is ordinary — and the design values used are low percentiles of a distribution rather than measurements of a material.

Nothing here is about duration or moisture, and both are large. Timber’s strength under a permanent load is around 60 per cent of its short-term strength, and its stiffness under one creeps by a factor approaching two; both depend on the service moisture content, and neither has an equivalent in steel design.

And the member is assumed defect-free. Real timber has knots, sloping grain around them, and drying checks — and the strength-reducing effect of a knot is not that it removes area but that it locally rotates the grain direction, which by Hankinson’s formula is a much larger effect.

What the pictures cannot show

The polar curve is drawn as a smooth function of angle, which assumes the grain has a single well-defined direction at the point of interest. Around a knot it does not: the grain sweeps around the knot at every angle from zero to ninety within a few tens of millimetres, so the strength varies over a region rather than following the curve.

Nor can the bar chart show what a designer really works with, which is a species and a grade rather than six numbers. The properties in the chart are inferred from a visual or machine grading of a piece of sawn timber, and the inference — not the measurement — is what the whole design rests on.

The assumption the figure rests on

Every number here assumes the load is applied at a known angle to a known grain direction.

That is the assumption a connection breaks. A bolt in a timber member bears against the wood at whatever angle the force happens to arrive, and the force in a truss diagonal arrives at the angle of the diagonal — so the bearing strength at a joint is a Hankinson value rather than a material property, and it changes with the geometry of the truss rather than with the timber.

Which is why timber connections, rather than timber members, are what timber engineering is mostly about. A member’s capacity is a grade and a section; a joint’s capacity is a set of angles, and the arithmetic on this page says that those angles are worth more than the grade.

Bearing and tear-out against end distanceA 20 mm bolt in a 45 mm plate. Below 165 mm of end distance the bolt tears a channel out to the end and the capacity is proportional to that distance; above it the plate crushes in front of the bolt and the end distance stops mattering. At 60 mm the capacity is 351.82 kN and the mode is tear-out.0204060801001201400200400600800end distance, mmbearing capacity, kN60 mm → 351.82 kNthe corner is at 165 mm, past this plotplate crushesbolt tears out
Fig. 10 The bearing check at a joint, which in timber is a Hankinson value rather than a constant. The same bolt in the same member has a different capacity depending on which way the force it carries is pointing, and nothing about the bolt has changed.

Named alongside this one

Essays reaching for the same objects. Nobody chose these; they are what the concept index makes visible.

The objects this essay names

Each one links to every other essay that touches it.

AnisotropyBearingElastic modulusFractureGrainHankinson formulaLimit stateMoistureNotchOrthotropicShear deflectionShear modulusShear strengthSpan to depthTimber