Internal forces

The force that splits what it pushes on

A prestressing tendon delivers its whole force through a plate a fraction of the section deep. One depth further along the stress is uniform, and the spreading in between requires a transverse tension nobody applied — the force that splits end blocks, and the only number in the design that no equilibrium equation on the member can see.

Assumes When there is no section to design, The load put on backwards and The hole that multiplies the stress by three.

A post-tensioned beam is stressed by pulling a tendon against the concrete and locking it off against a steel plate. On the beam drawn here the force is 1,200 kN and the plate is 200 mm deep in a section 700 mm deep. The bearing stress under the plate is 20 N/mm²; a metre further along the member the stress is 5.7 N/mm² and uniform.

Between those two stations the force has spread out, and spreading is not free. A compression field that starts narrow and ends wide has flow lines that bow outward, and a bowing compression needs something pulling inward to keep it in equilibrium. Nothing outside the beam is pulling. So the concrete does it, in tension, along the axis of the tendon — and concrete’s tensile strength is a tenth of its compressive one.

End blocks split. They split along the line of the tendon, in the first half-metre, and the reinforcement provided to stop them is designed for a force that appears in no equilibrium equation written on the member as a whole.

The force spreads, and the spreading needs a tieThe end block behind an anchorage of 1200 kN on a 200 mm plate, in a section 700 mm deep. Half the force enters at the quarter point of the plate and leaves at the quarter point of the section, so a strut between the two rises 125 mm and needs a transverse tie to turn it. Placing the tie 0.5 depths from the face makes that tie force 214 kN — and at exactly half a depth this reproduces Guyon's 0.25P(1 − a/h) to the digit, which makes that famous coefficient a lever arm somebody chose rather than a property of concrete. The bearing stress under the plate is 20.0 N/mm² against 5.7 once the force has spread.1200 kN214 kN of tiestruts at 20°0.5 huniform from here onGuyon: 0.25 P (1 − a/h) = 214 kN — the same number, from the same lever armbearing 20.0 N/mm² · once spread 5.7 N/mm²
Fig. 1 The design model in one drawing. Half the anchorage force enters at the quarter point of the plate and leaves at the quarter point of the section, so a strut between the two has to rise — and a strut that rises needs a tie to turn it. Where the tie is placed decides how large it is, and the placement is a choice.

Which free body produced the number

Take the half of the end block above the tendon’s axis, bounded by the loaded face, the top face and a section far enough along that the stress has become uniform.

Along the axis, symmetry says the shear is zero. The top face is free. At the loaded end the plate delivers P/2P/2 over the top half of its depth, so that force’s resultant acts at a/4a/4 above the axis. At the far end the same P/2P/2 leaves uniformly over the top half of the section, with its resultant at h/4h/4.

Sum forces along the member and nothing is learned: P/2P/2 in, P/2P/2 out. Sum moments and something is: the two resultants act at different heights, so their moments about any point differ by (P/2)(ha)/4(P/2)(h - a)/4, and there is nothing left to balance it except the transverse stress on the axis.

That difference is the whole of the anchorage-zone problem, and it is a moment rather than a force — which is why the answer depends on the lever arm it is divided by.

A truss drawn inside a solid, and solved as oneA deep member 4000 mm between bearings and 2000 mm deep, carrying 1200 kN at mid-span. The model is two struts and one tie, on a lever arm of 1600 mm, and it is solved by the truss solver rather than by a formula: the tie comes back at 750 kN and each strut at 960 kN, at 38.7° to the horizontal. Spread over a strut width of 812 mm the compression is 3.0 N/mm² against a limit of 15.8 for concrete cracked across its own strut, and the tie needs 1724 mm² of steel. A beam calculation on the same member would have asked the tie for 702 kN, which is 7% less than the model does.1200 kNtie 750 kNstrut 960 kN38.7°z = 1600strut 3.0 N/mm² over 812 mm · limit 15.8bursting across each strut 240 kN · tie steel 1724 mm²
Fig. 2 The lower-bound argument this belongs to. A strut-and-tie model is a load path the designer chooses, justified by the theorem that any equilibrium system the material can sustain is safe. The anchorage zone is the smallest and the most inevitable of these regions: it is a D-region by construction, because the force enters through a plate.

The coefficient that is a lever arm

Choose the tie’s position at half a section depth from the loaded face — which is a claim that the flow has spread by about that much by then — and the tie force follows from the node:

T=P2(ha)/4h/2=P4(1ah)T = \frac{P}{2}\cdot\frac{(h-a)/4}{h/2} = \frac{P}{4}\left(1 - \frac{a}{h}\right)

For the block drawn: 214 kN, from an applied 1,200. That is Guyon’s expression, which has been in every prestressed-concrete text since the nineteen-fifties, and the derivation above is the whole of it. The 0.25 is 12×14×11/2\tfrac12 \times \tfrac14 \times \tfrac{1}{1/2} — three geometric fractions, none of them measured.

Move the tie to a quarter of a depth and the coefficient becomes 0.5. Move it to a whole depth and it becomes 0.125. Nothing about the concrete changed.

A closed force polygonThe forces on a joint, laid tip to tail. Equilibrium is the statement that the polygon closes, and the gap when it does not is the out-of-balance force, to scale.half the anchorage force 600strut 636tie 214starts and ends here
Fig. 3 The node closing, drawn as a polygon. The strut leaves the anchorage at 19.7° to the axis and the tie is the vertical side that closes the triangle. Graphic statics makes the dependence on the angle obvious in a way the algebra does not: a shallower strut needs a smaller tie, and the strut’s angle is set entirely by where the tie was drawn.

What an actual equilibrium field says

The strut-and-tie model is a lower bound and makes no claim to be the stress field. It is worth asking what a field that is one says, and the calculation needs no elasticity at all.

Assume how the longitudinal stress spreads — a block starting at the plate’s width and opening out to the full section over about a depth — and normalise it at every station so that it carries exactly PP. That normalisation is what makes the assumption admissible rather than decorative. Then the two-dimensional equilibrium equations,

σxx+τy=0,τx+σyy=0\frac{\partial\sigma_x}{\partial x} + \frac{\partial\tau}{\partial y} = 0, \qquad \frac{\partial\tau}{\partial x} + \frac{\partial\sigma_y}{\partial y} = 0

give the shear and the transverse stress by integrating down from the free face, with nothing else supplied.

What comes back has the shape every photoelastic study of an end block shows. Directly under the plate the concrete is in transverse compression — the plate is confining it. About a third of a depth in, the transverse stress crosses zero. It peaks in tension at 2.74 N/mm² a little under half a depth in, and decays to nothing by one depth.

Compression under the plate, tension behind itThe transverse stress along the axis of an end block, computed from an assumed spread of the longitudinal stress and the two equilibrium equations — no elasticity anywhere in it, and the far face closes to 5e-11 N/mm², which is what says the assumed flow is an equilibrium field rather than a sketch. It is compressive right under the plate, crosses zero 0.31 depths in, and peaks in tension at 2.74 N/mm² 0.44 depths in. The tension integrates to 174 kN and the compression to -174: nothing pushes the block sideways, so the two are the same force, and the residual on that identity is 0.0%. Guyon's tie for the same block is 214 kN, which is 1.23 times the tensile resultant — a design model deliberately above what the field says.0.00.20.40.60.81.01.21.4-4-202distance from the loaded face ÷ section depthtransverse stress on the axis (N/mm²)2.74 N/mm² of tensioncompression under the plate174 kN of tension against 174 of compression · Guyon's tie is 214
Fig. 4 The transverse stress on the axis, computed from an assumed flow and two equilibrium equations. The check that it is an equilibrium field rather than a sketch is on the figure twice: the far free face comes back to zero to 10⁻¹¹ N/mm², and the tension and the compression are the same force — because nothing pushes the block sideways, so the transverse stress has to integrate to nothing along the axis.

The number is a property of the assumption

Integrate the tensile part and it comes to 174 kN, against the strut-and-tie model’s 214.

Then change the assumed spread — keep the same section, the same plate and the same force, and only alter how fast the flow is imagined to open out. A gentle spread gives 96 kN. A fast one gives 198. All three satisfy equilibrium to machine precision, all three have zero stress on the free faces, and all three integrate to nothing across the axis. The bursting force is not a property of the block.

This is not a failure of the calculation; it is the reason the design is done the way it is. The tensile resultant depends on a flow nobody can observe, so the sensible thing is to pick a lower-bound tie, provide reinforcement for it, and detail that reinforcement so it works wherever the tension actually turns out to be. Guyon’s coefficient sits above all three computed values, which is what a design number should do.

Three times the stress, and it does not matter how big the hole isThe hoop stress around a circular hole in a wide plate pulled at 100 N/mm², from Kirsch's exact solution. At the sides of the hole it is 3.0 times the applied stress — 300 N/mm² — and the factor is the same for a hole of any radius, because the radius cancels. At the top and bottom of the hole it is -1.0 times the applied stress, which is compression in a plate that nothing is pushing. The disturbance dies quickly: the stress is within 5% of the applied value by 3.5 hole radii, which is Saint-Venant's principle with a number on it.pulled at 100 N/mm², left and right300-100 — compressionhoop stress, tinted3.0× at the edgewithin 5% by 3.5 radiithe applied stressdistance from the centre, in hole radii12345
Fig. 5 The same phenomenon in its more familiar clothes. A stress concentration is a local disturbance that decays over a distance of the order of the feature that caused it. An anchorage is a concentration whose “feature” is the whole plate, so its disturbance decays over the section depth — which is Saint-Venant’s principle with a number attached.

Two other tensions in the same region

The bursting tension along the axis is the largest of the anchorage zone’s problems and not the only one.

Spalling. On the loaded face itself, between two anchorages or above a single eccentric one, the concrete is pulled apart parallel to the face. It arises from the same spreading — the flow lines have to leave the face and turn — and it produces cracks that open at the end face and run in a few tens of millimetres. It is small, it is close to the surface, and it is why anchorage zones carry a mesh right at the end face as well as spirals behind the plates.

Equilibrium of the whole end block. An anchorage placed off the centroid puts the section into bending as well as compression, and the end block has to carry that too. With several tendons at different levels — normal, since the profile wants the force low at mid-span — the end block is a small deep beam with several point loads on one face, and it is designed as one.

The zone the tendon has to stay insideThe eccentricities that keep the top fibre out of tension at transfer and the bottom fibre out of tension in service, along a 12 m beam. The two limits cross the section at different rates, and the parabolic profile drawn between them is the tendon: 220 mm at midspan, where the zone is 148 mm deep, and on the centroid at the ends, where a tendon left low would crack the top of a beam carrying nothing but itself.024681012-300-200-1000100200300distance along the span (m)eccentricity below the centroid (mm)above this line the top cracks at transferbelow this line the bottom cracks in service
Fig. 6 Where the tendon is allowed to be, along the member. The eccentricity that the span wants is not the one the end can take, which is why tendons are lifted toward the centroid at the anchorage — a detail that exists to make the end block’s job possible and has nothing to do with the beam’s bending.
The middle third, computedThe kern of a 300 × 700 mm rectangle, computed by asking, for every direction, how far the resultant can move before the far face would be pulled. It reaches ±116.7 mm vertically and ±50.0 mm horizontally, which are h/6 and b/6 exactly, and the region between is a rhombus rather than the ellipse the two numbers suggest — a resultant on a diagonal has less room than either axis allows.rectangle±117 of 700 mm33.3% of the depth
Fig. 7 The kern, which is the same section’s answer to a related question: where a force can act without producing tension anywhere. An anchorage inside the kern still produces bursting, because bursting is caused by the force spreading and not by the force being eccentric. The two limits look similar and are about different things.

Why concrete in particular

Every material spreads a concentrated force this way, and steel end blocks exist too. The reason the anchorage zone is a concrete problem is arithmetic about ratios.

The peak transverse tension here is 2.74 N/mm² under a bearing stress of 20 — about a seventh. In a material whose tensile and compressive strengths are the same, a seventh is nothing. Concrete’s tensile strength is between a twelfth and a fifteenth of its compressive strength, so the ratio the geometry produces and the ratio the material can survive are the same order of magnitude. The transverse direction is exactly as critical as the longitudinal one, in a member being loaded in one direction only.

The crack length at which the strength stops matteringFailure stress against crack length for a toughness of 100 MPa√m, with one steel grade drawn. The falling curve is fracture — Kc divided by Y times the root of pi a — and it does not know what the yield stress is. The horizontal lines are the grades. At 355 N/mm² the two cross at a crack 20.1 mm long. Below that the section yields and the crack is irrelevant; above it the crack decides and the 355 is irrelevant.501001502000100200300400500crack length, mmstress at failure, N/mm²355 N/mm² crosses at 20.1 mmfracture: the crack decides
Fig. 8 What a small tension does to a material with a flaw in it. The end block’s tension is modest by any absolute standard and is acting on unreinforced concrete across a plane the tendon has already defined. The reinforcement provided is not there to raise the cracking load much; it is there so that the crack, when it comes, is crossed by steel and stops.

The reinforcement is designed for a resultant, not a stress

Two consequences follow from designing this region with a tie force rather than a stress field, and both are practical.

The first is that the reinforcement can be spread over the region where the tension is, rather than concentrated where the model drew its tie. A spiral behind the plate, links through the first depth, a mesh at the face: between them they cross every plane the tension could be acting on, and the total area is set by the tie force.

The second is that the design is insensitive to exactly which admissible field the concrete chooses. That is the lower-bound theorem’s whole promise — the structure is safe if some equilibrium field within the material’s strength exists — and the anchorage zone is the case where the promise is most obviously being cashed, because three equally defensible fields give answers a factor apart.

Where a section exists, and where it does notThe same beam divided into the regions the two theories own. Within about one depth of a support, a concentrated load, a corner or an opening, the strain is not linear across the section and every calculation on this site that begins by choosing one is inapplicable — those are the D-regions, marked here. What is left between them is the B-region, where beam theory is exact enough to have been trusted for two centuries. On a beam this deep the D-regions are most of it, which is the practical reason the strut-and-tie model exists at all: 38% of this span is a region a section cannot describe.DBDBDshaded: one depth either side of every discontinuity, where no section describes the strain
Fig. 9 Where beam theory works and where it does not. The shaded regions are within about a depth of a support, a load or a discontinuity, and are exactly the regions in which structures fail. An anchorage creates one at the end of every post-tensioned member, and the region it creates has a tension in it that the member’s own analysis contains nowhere.

The region that was found by watching it fail

The end block is one of the few parts of structural engineering whose theory arrived after the cracks did.

Early post-tensioned members were anchored with whatever plate the system supplied, into an end detail chosen for constructability, and they split. The cracks were longitudinal, they appeared on stressing rather than under load, and they appeared in members whose flexural design was faultless — because the flexural design contains no term that knows about them. The response was reinforcement chosen by eye, then by test, and finally by the symmetric-prism argument that produced the coefficient above.

What makes the sequence worth recording is that the region is created by a design decision rather than encountered. A pre-tensioned member has no plate and no end block; the force arrives through bond over a transmission length and the splitting problem is different. A reinforced member has no anchorage zone at all. The end block exists because somebody chose to introduce a very large force through a very small area, which is exactly the choice a bearing, a base plate or a support makes on a smaller scale, and the tension behind it is the price of that choice rather than a property of the beam.

It is also the clearest case on this site of a region where the section stops being the unit of design. Everything else in a prestressed beam is designed section by section; the last half-metre at each end is designed as a body, with a free body drawn round it and moments taken.

Where the model stops

The block is two-dimensional. A real anchorage spreads in both transverse directions, and the section is usually not rectangular: an I-beam’s anchorage sits in an end block cast solid, and the transition from that block back to the thin web is a second D-region behind the first.

The plate is rigid and the bearing uniform. Neither is quite true, and the difference matters most where the bearing stress is highest — under a plate sized so that the concrete beneath it, locally confined by the spiral, is being worked at several times its cylinder strength.

And the force arrives all at once. Tendons are stressed in sequence, so the end block sees one anchorage loaded, then two, then all of them. The worst case for spalling between two anchorages is often the intermediate one, and no single figure on this page corresponds to a real moment in the construction.

What the pictures cannot show

The transverse stress is drawn as a curve along a line. In the block it is a field over an area, and the tension is spread across a region roughly one depth long and half a depth deep. The crack that eventually forms does not follow the peak; it forms where the concrete happens to be weakest along a plane that is in tension over most of its length.

Nor can the figures show the confinement. The concrete immediately under a plate is triaxially held by the spiral around it and by the mass of concrete surrounding it, and its local strength is far above the value any cylinder test gives. The bearing check that permits 20 N/mm² on a 30 N/mm² concrete is relying on that, and confinement is not drawn anywhere here.

The assumption the figure rests on

The equilibrium field assumes the longitudinal stress is distributed across a growing width with a fixed shape, and normalises it to carry PP at every station. That is enough to make the field admissible and not nearly enough to make it real: the true distribution depends on the elastic properties, on the section’s shape, on the plate’s stiffness and on whether the concrete has already cracked. What survives the assumption is the resultant on the axis being zero and the tension being of the order of a fifth of the applied force — and the design uses only the second of those, with a margin.

The ladder from here

Later rungs on this anchor: the anchorage zone with several tendons at different levels, where the general zone is a deep beam and the local zones sit inside it. Bearing under a rigid plate on confined concrete, where the permissible stress is several times the cylinder strength and the reason is the spiral. Pre-tensioned members, where there is no plate at all and the force enters by bond over a transmission length, with a different and larger splitting problem. Bursting behind a bearing on a bridge pier, which is the same figure with the prestress removed. And the general question of how far a designer may go in choosing an equilibrium field, which is the lower-bound theorem’s practical edge and is where this region’s design has lived for seventy years.

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Anchorage zoneBearing stressBurstingConcrete strengthD regionEquilibriumFree bodyLower bound theoremPrestressReinforcementSaint venants principleSplittingStress trajectoryStrut and tieTransverse tension