Stability

The load that chooses its own length

Every other load in this collection arrives over a length somebody decided. A wheel on a crane girder does not — the flange bends under it and spreads it along the web, and how far it spreads is an output of the flange's own stiffness against the web's own strength. The effective length is 5.6 times the bearing that produced it.

Assumes The plate that ripples, and the width that is left, The section that cannot reach its own strength and The hole that goes oval, and the one that tears to the edge.

Almost every load in this collection arrives over a length that somebody chose. A bearing is detailed at 150 mm because that is what the drawing says; a stiffener is 200 mm wide; a bay is 7.2 m. The length is an input, and the calculation divides by it.

A wheel is different. So is a launching bridge on its rollers, a column landing on an unstiffened beam, and a girder being lifted on slings. The load arrives over a length so short that the flange under it bends, and the bending spreads the load along the web — over a length that nobody decided and that has to be computed.

The bearing is one length and the web is loaded over anotherA load applied over a stiff bearing of 100 mm on the flange of a girder with a 1200 × 8 mm web. The flange bends under it and the yield lines that form spread the load along the web over 559 mm — 5.6 times the bearing, and 82% of the yield resistance is that spread rather than the bearing. The effective length is not a decision anybody made: it is what the flange's own bending stiffness against the web's own strength works out to.s_s = 100l_y = 559flangewebspread 5.6 times the bearingyield resistance 1586 kN · elastic critical 510 kNresistance 450 kN at a slenderness of 1.76
Fig. 1 A load applied over a 100 mm bearing on the flange of a girder with a 1,200 × 8 mm web. The flange bends under it, yield lines form, and the web is loaded over 559 mm — 5.6 times the bearing. That length is a result, and 82% of the yield resistance is the spread rather than the bearing.

Which free body produced the number

Take the flange as a beam sitting on the web, loaded over the bearing length and supported continuously along the web line beneath it.

Push hard enough and the flange forms plastic hinges: one under each edge of the bearing and one further out where the bending has run out. The load between the outer hinges is delivered to the web, and the distance between them is the effective loaded length y\ell_y.

Doing that yield-line calculation gives

y=ss+2tf(1+m1+m2),m1=fyfbffywtw,m2=0.02(hwtf) ⁣2\ell_y = s_s + 2t_f\left(1 + \sqrt{m_1 + m_2}\right), \qquad m_1 = \frac{f_{yf}\,b_f}{f_{yw}\,t_w}, \qquad m_2 = 0.02\left(\frac{h_w}{t_f}\right)^{\!2}

where m1m_1 compares the flange’s plastic strength with the web’s, and m2m_2 carries the web’s slenderness. For the girder above, m1=37.5m_1 = 37.5 and m2=72.0m_2 = 72.0, so the square root is 10.46, and

y=100+2×20×11.46=559  mm\ell_y = 100 + 2 \times 20 \times 11.46 = 559\;\text{mm}

Note where the bearing length appears: as an additive constant, and only there. Everything else is a property of the section. A bearing of zero length still spreads the load over 459 mm, because the flange is still there.

Prying action in a tee stubA tee stub pulled by its web with 200 kN per bolt. The 20 mm flange is in the mechanism regime, so the prying force at the flange tip is 64.55 kN and the bolt carries 264.55 kN — 1.32 times what was applied. The flange stops prying entirely at 31.84 mm thick, and collapses on its own at 157.78 kN.200 kN appliedbolt 264.55 kNprying 64.55 kNm = 45n = 55flange 20 mm · mechanismbolt force is 1.32 times the applied load
Fig. 2 The same yield-line arithmetic in the connection field, where this collection met it first: a tee flange bending under a bolt force, with hinges at the web face and at the bolt line. A patch load is a prying calculation turned upside down — the plate is bending under the load rather than over it, and the same plastic mechanism sets the length.

Three failures, one curve

The web now has a length to be loaded over, and three separate things can go wrong with it.

It can yield. The load simply crushes the web over its effective length: Fy=fywtwy=1,586F_y = f_{yw}\,t_w\,\ell_y = 1{,}586 kN. This is web crushing, and it is the answer for a stocky web — the same crushing limit a bolt in bearing meets against the plate it presses into.

It can buckle elastically. The web is a plate loaded on one edge, and its critical load is Fcr=0.9kFEtw3/hw=510F_{cr} = 0.9\,k_F\,E\,t_w^3/h_w = 510 kN, with kFk_F from the panel geometry. This is the answer for a very slender web.

And in between it does something that is neither, which is the case every real girder is in.

One curve, and every patch-loaded girder is a point on itThe reduction factor against the slenderness built from the two resistances — the square root of the yield resistance over the elastic critical one. It is the same construction as the column curve and the plate curve on this site, with a different pair of limits underneath it. Every girder in the two sweeps beside this figure is a dot here: the one drawn sits at a slenderness of 1.76 and keeps 28% of what its web could yield at.00.511.522.533.500.20.40.60.81slenderness √(F_y ÷ F_cr)fraction of the yield resistance kept28%the girder drawnevery dot is agirder from thetwo sweeps
Fig. 3 The reduction factor against the slenderness built from the two resistances, λ=Fy/Fcr\lambda = \sqrt{F_y/F_{cr}}. It is the same construction as the column curve and the plate curve on this site, with a different pair of limits underneath it. The girder drawn sits at a slenderness of 1.76 and keeps 28% of what its web could yield at.

χ=0.5/λ1\chi = 0.5/\lambda \le 1, so FRd=χFy=450F_{Rd} = \chi F_y = 450 kN. The web could yield at 1,586 kN and buckle at 510, and it does neither: it fails at 450, below both, which is exactly the pattern the plate curve and the column curve share and that the imperfect column explains and for the same reason — imperfections and residual stress make the transition region worse than either bound.

A 8 mm plate, and the width it can beThe elastic critical stress of a plate in compression against its width, with the yield stress drawn across it. Below 370 mm the plate reaches yield before it buckles; above it the plate ripples first, and the fraction of the width still carrying load falls away — at 2400 mm only 15 per cent of it is still working.5001000150020000200400600plate width (mm)slender beyond 370 mmyieldcritical stress — inverse square in the widthwhat the plate actually delivers, over its full width
Fig. 4 The construction as this collection first drew it, for a plate in uniform compression: a squash limit, an elastic critical limit, and a reduction between them. Every local stability check on this site is this picture with different constants — which is a claim about how the subject is organised rather than about any one member.

The web thickness, squared

A resistance that is very nearly square in a thickness that appears onceThe three resistances against web thickness. The yield resistance is the web thickness times an effective length times a stress and is therefore nearly linear; the elastic critical resistance goes as the cube; and the reduction factor between them, 0.5 divided by the slenderness, restores about half of that. What comes out is a resistance going as the 1.95 power of the web thickness — so a web a millimetre thicker is worth far more than a shear check on the same web would suggest.68101214161820222401000200030004000web thickness (mm)resistance (kN)yield, F_yelastic, F_crwhat is leftpower 1.95
Fig. 5 The three resistances against web thickness. The yield resistance is nearly linear in it, the elastic critical resistance goes as the cube, and the reduction factor between them returns about half of that difference — leaving a resistance that goes as the 1.95 power.

The exponent is worth deriving rather than reading off, because the route is short and the answer is surprising.

FytwyF_y \propto t_w \ell_y and Fcrtw3F_{cr} \propto t_w^3, so λ=Fy/Fcry/tw\lambda = \sqrt{F_y/F_{cr}} \propto \sqrt{\ell_y}/t_w and χ=0.5/λtw/y\chi = 0.5/\lambda \propto t_w/\sqrt{\ell_y}. Therefore

FRd=χFy    twytwy=tw2yF_{Rd} = \chi F_y \;\propto\; \frac{t_w}{\sqrt{\ell_y}} \cdot t_w \ell_y = t_w^2 \sqrt{\ell_y}

and y\ell_y depends only weakly on twt_w. The measured exponent over 5 to 25 mm of web is 1.95.

That is a strong dependence and it is not what a designer’s intuition supplies. A shear check on the same web is linear in the thickness; a bending check does not contain it at all to first order. Here, taking the web from 8 to 12 mm — a half as much again — multiplies the resistance by 2.20, and 1.51.95=2.201.5^{1.95} = 2.20 to three figures.

The flange thickness, hardly at all

A thicker flange spreads the load further and carries almost nothing moreThe same three resistances against flange thickness. The effective loaded length grows with the flange, which is the whole reason a flange helps at all — but the two yield-line terms it is built from scale in opposite directions, one with the flange and one inversely with it, and their sum is nearly constant. Fitted over this range the resistance goes as the 0.19 power of the flange thickness, which is close enough to nothing that a flange chosen for bending is a flange chosen for this.10152025303540455005001000150020002500flange thickness (mm)resistance (kN)yield, F_yelastic, F_crwhat is leftpower 0.19
Fig. 6 The same three resistances against flange thickness. The effective length does grow — from 481 mm at a 10 mm flange to 900 mm at 50 — and the resistance goes from 417 to 571 kN, which is a fitted exponent of 0.19.

This is the result that inverts the expectation, and the mechanism is in the two yield-line terms.

y\ell_y contains 2tfm1+m22t_f\sqrt{m_1 + m_2}. The m1m_1 term is independent of tft_f, so its contribution grows linearly with the flange. The m2m_2 term is 0.02(hw/tf)20.02(h_w/t_f)^2, so m21/tf\sqrt{m_2} \propto 1/t_f and its contribution to 2tfm22t_f\sqrt{m_2} is 0.283hw0.283\,h_wa constant, with no flange thickness in it at all.

So a thicker flange grows one half of the spread and leaves the other alone, and since m2m_2 dominates for a slender web, most of the effective length does not know how thick the flange is. Add the square root in FRdtw2yF_{Rd} \propto t_w^2\sqrt{\ell_y} and the flange’s influence is halved again.

The practical version: improving a patch-load resistance is a web problem. Doubling the flange from 20 to 40 mm buys 18%. Adding half again to the web buys 120%. And the cheapest answer of all is not a thickness at all.

The answer that is not a thickness

A bearing stiffener under the load changes the problem completely rather than improving it. The load is delivered into a member designed to carry it as a short column, the web’s own patch resistance stops being the check, and the calculation becomes a stub-column one.

That is why the check matters most where a stiffener cannot be put: under a moving wheel, which is not at a stiffener; under a launching bridge’s rollers, which travel; at a support during erection before the stiffeners are welded on.

The worst position is not the obvious oneThree axles totalling 320 units, marched across a span of 24 in steps of 0.02. The envelope is the largest moment each station ever sees; its peak is 1480.2 at 11.88 along the span, which is 0.12 off midspan and occurs under the axle nearest the resultant rather than under the heaviest one. Barré's construction, which places midspan halfway between that axle and the resultant, independently gives 1480.2 at 11.88. The dashed curve is the envelope the same total weight would produce as one load rather than three: its peak is 1920.0, which is 30% more — spreading a load out is worth something.12012080resultantmidspan05101520050010001500station along the spangreatest moment ever seen there1480.2 at 11.88Barré: 1480.2 at 11.88
Fig. 7 The load that will not stay still, which is where a patch load usually comes from. A wheel occupies whatever part of the span it happens to be on, and the web has to have the resistance everywhere rather than at the places a stiffener was drawn.
The bearing is one length and the web is loaded over anotherA load applied over a stiff bearing of 100 mm on the flange of a girder with a 1200 × 8 mm web. The flange bends under it and the yield lines that form spread the load along the web over 559 mm — 5.6 times the bearing, and 82% of the yield resistance is that spread rather than the bearing. The effective length is not a decision anybody made: it is what the flange's own bending stiffness against the web's own strength works out to.s_s = 100l_y = 559flangewebspread 5.6 times the bearingyield resistance 1586 kN · elastic critical 210 kNresistance 288 kN at a slenderness of 2.75
Fig. 8 The same girder loaded at its end rather than in a panel. The buckling coefficient falls from 6.32 to 2.60, because a panel with an edge nearby has less plate to buckle into, and the resistance falls from 450 to 288 kN. The most awkward place to apply a patch load is the end of the member.

Where the web has already gone

There is a case where the web has buckled and the girder is still working, and it is worth putting beside this one because the two look similar and are not.

A buckled panel is a truss that nobody drewA 1000 × 1000 panel of 6 mm web, at d/t = 167. It buckles in shear at 63.8 N/mm², which is 383 kN — and it then carries 696 kN, 1.82 times as much, because the tension diagonal takes over from the compression one that has gone. The band runs at 22.5° with a membrane stress of 252 N/mm² over a width of 541 mm, and it pulls on the flange at 221.3 N per millimetre of its length. A web that never buckled at all would have reached 953 kN, so the panel ends at 73% of a stocky web's capacity on a fraction of its steel.stiffeners at 1000 mmthe band at 22.5°the truss it has becomestiffener in compression,web in tensionbuckles at 383 kN · carries 696 kN · a stocky web would reach 953 kNσ in the band 252 N/mm² over 541 mm
Fig. 9 A panel that carries more after it fails: a web that has buckled in shear and reorganised into a tension field, with the flanges and stiffeners completing the truss. That reserve exists for shear and does not exist for a patch load — a crippled web has nowhere to reorganise to, because the load is coming in at right angles to any band it could form.

The asymmetry is worth naming. Shear buckling of a web is a serviceability event with a strength reserve behind it. Patch-load failure of a web is not: the web folds locally under the load, the flange follows it down, and there is no second mechanism. Which is why the reduction curve is used as a strength limit rather than as a warning.

The column curveFailure load against slenderness, as a fraction of the squash load. A stocky column crushes; a slender one buckles at the Euler load; the crossover is where the two curves meet, and real columns fall below both near it.5010015020000.20.40.60.811.2slenderness (effective length ÷ radius of gyration)they cross at λ = 76squashingEuler bucklingreal columns, which are neither
Fig. 10 And the family the whole construction belongs to: two limits and a curve between them, with the horizontal axis a slenderness assembled from the ratio of the two. A column, a plate, a web under a wheel — three members, one picture, and the constants are where the physics has gone.

Four places it decides something

A crane girder is the case the check was written for. A wheel load of a hundred kilonewtons or more travels the whole length of the girder, arrives on a rail bolted to the top flange, and cannot be met with a stiffener because it is never in the same place twice. The girder’s web thickness is very often set by this check and not by shear or bending — which is a member sized by a load case that occupies a few hundred millimetres of it.

A launched bridge is worse, because the girder passes over the rollers nose first with its full self-weight behind it, and every section of the web is subjected to the reaction in turn. Launching noses and roller spacings are designed around this, and a launched girder frequently carries a thicker web over its whole length for the sake of a condition that exists for a few weeks.

A column landing on a beam puts a concentrated load into an unstiffened flange, and the same yield-line spread applies. Here the answer is usually a stiffener and the interest is in what happens if one is left out — which happens, because the column above is drawn on one drawing and the beam below on another.

The depth is decided by how far it moves, not by what it can carryA column carrying 2000 kN landing 6 m into a 12 m transfer member. The free body is the member itself, cut under the column: M = P·a(L − a)/L = 6000 kNm, with 1000 kN of shear on one side of the cut and 1000 on the other. At an allowable stress that moment asks for 1.29 m of depth — the dashed outline — and keeping the settlement it causes inside the floors' own bending asks for 2.11 m, which is the member drawn solid. 63% more depth is bought by nothing the strength calculation can see. The depth grows as √(P·a), so four times the load is exactly twice the depth, and depth in a transfer member is a storey nobody occupies.P = 2000 kNfrom 10 storeys abovea = 6 mstrength wants 1.29 mstiffness wants 2.11 mslope 1000 kN1000 kN6000 kNm under the column12 m
Fig. 11 A column that stops and hands its load to the beam beneath it. Everything about that transfer is usually discussed as a bending problem in the beam; the first thing the load meets is the beam’s top flange, and the length over which it arrives there is the subject of this page.

And a beam sitting on a bearing is the same problem from below. The reaction is not applied to the member; the member is resting on something, and the length over which that something answers is decided by the same flange bending. It is the one case where a designer has usually written down a length — the bearing plate’s — and it is not the length the web sees.

None of the four has a stiffener available at the point where the load actually is, and that is what they have in common. Where a stiffener can be put, this check is replaced by a different and easier one; where it cannot, the web’s own resistance is the whole answer, and it is a function of a length nobody drew.

And a beam sitting on a bearing is the same problem from below. The reaction is delivered into the bottom flange over the bearing’s length, spreads through the flange, and loads the web — so a support is a patch load too, and it is the one place a designer is most likely to have assumed the length was the bearing plate’s.

The one number worth carrying

If a single figure survives from this page it should be the ratio 5.6, and it should be carried as an order of magnitude rather than a value.

A concentrated load on a girder flange is delivered to the web over a length several times the bearing that produced it, and the multiple is largest for exactly the girders that most need help — a deep slender web has a large m2m_2, which lengthens the spread. The plate that looks least able to take a wheel is the one whose flange spreads the wheel furthest.

That is a genuinely unusual arrangement, and it is worth stating as a general shape: a mechanism that relieves the member in proportion to how badly it needs relieving is rare, and this is one. The spread is not a design allowance being claimed; it is a plastic mechanism that happens whether anybody counts it or not, and counting it is the difference between a resistance of 284 kN and one of 450.

Where the model stops

The expressions are semi-empirical. The yield-line derivation gives the form of y\ell_y; the constants — the 0.02 in m2m_2, the 0.9 in FcrF_{cr}, the 0.5 in χ\chi — are fitted to tests. They are not derivable and they differ between codes by more than the difference between a 20 and a 40 mm flange.

Bending is assumed absent. A girder carrying a patch load is usually also carrying a moment, and the two interact — the web’s compression from bending reduces what is left for the patch load. The interaction is checked separately and is not in any figure here.

The load is assumed perpendicular to the flange. A wheel on a crane girder also applies a horizontal surge, and a launching bridge’s rollers apply friction. Both put a horizontal force into the top flange at exactly the point where the vertical one is being spread.

And the flange is assumed to stay flat. A wide thin flange under a concentrated load dishes, so the load is delivered to the web over less width than the yield-line model assumes and the flange itself may fail before the web does.

What the pictures cannot show

The spread figure draws the yield lines as two straight dashes from the bearing edges to the web. The real mechanism is a set of hinge lines across a plate in two dimensions, and the drawing is a section through it.

The reduction curve places every girder in the two sweeps as a dot, which makes the curve look densely evidenced. It is one expression evaluated many times, not a set of measurements, and the tests behind the expression scatter by more than the width of the line.

And nothing here draws the failure. A web that crumples under a wheel does so over a length of a few hundred millimetres and a depth of a few tens, and the deformed shape is a local fold in a plate — which no elevation of a 1,200 mm girder can show at a scale where the girder is visible.

The ladder from here

Later rungs on this anchor: the interaction between patch loading and bending, which is where the check actually bites on a crane girder. Bearing stiffeners as stub columns, including the effective web width that acts with them. Launching, where the patch load travels the whole length of the girder and every section is checked at the worst position. Web crippling in cold-formed sections, where the same problem has an entirely empirical treatment because no yield-line model fits a rounded corner. Wheel loads on rails, where the rail spreads the load further still and the rail-to-flange interface becomes the model. And the historical case: the plate girder’s web was made thin long before anybody could compute what a wheel did to it, and the resulting failures are why crane gantries carry stiffeners at every wheel position on drawings from the 1900s.

Named alongside this one

Essays reaching for the same objects. Nobody chose these; they are what the concept index makes visible.

The objects this essay names

Each one links to every other essay that touches it.

BearingCrane girderEffective loaded lengthLaunchingLocal bucklingPatch loadingPlate bucklingReduction factorSlendernessStiffenerWeb cripplingYield line