Stability

The mode between the two that get checked

A thin-walled strut has three ways of buckling and two of them have design rules. The third has a half-wavelength several times the section depth, a shape in which the fold lines themselves move, and an elastic stress that no effective-width calculation can produce.

Assumes The plate that ripples, and the width that is left, Held everywhere, and it forgets its length and What is left after it ripples.

Plot the elastic buckling stress of a thin-walled strut against the half-wavelength it buckles in, and something appears that no single design check contains: a curve with three minima.

The first is local buckling, at a wavelength of the order of a plate width, where the flats ripple between fold lines that stay put. The last is column buckling, where the section keeps its shape entirely and the member goes as a whole. Both have rules, and both are in every textbook.

The one in the middle is the one this essay is about.

Three minima, and only two of them get a checkElastic buckling stress against half-wavelength for a 200 × 65 × 15 × 1.5 mm lipped channel in uniform compression. The local minimum is at 200 mm and 41 N/mm²; the distortional at 689 mm and 287; the global curve falls away to the right and reaches 489 at the 1.5 m member. The distortional branch is a strut on an elastic foundation — the flange and lip rotating about the web junction, restrained by the web's own bending at 627 N·mm per radian per millimetre — so its minimum is at π(EC_w/k_φ)^¼ and its value is (2√(EC_wk_φ) + GJ)/I₀, the same closed form a continuously braced strut has. The elastic stresses are in the order local, distortional, global, and the mode that governs the strength is not the lowest of them, because they have very different amounts of post-buckling reserve.32100316100031620200400600800half-wavelength (mm, logarithmic)buckling stress (N/mm²)localdistortionalglobalyield287 at 689 mmthe distortional minimum is 2√(EC_wk_φ) + GJ over I₀, at π(EC_w/k_φ)^¼
Fig. 1 The signature curve for a 200 × 65 × 15 × 1.5 mm lipped channel in uniform compression. Local buckling bottoms out at 41 N/mm² and 200 mm; the distortional branch at 287 N/mm² and 689 mm; and the global curve falls away to the right, reaching 489 at the 1.5 m member drawn.

Which free body produced the number

Cut the section at the web-to-flange fold and take the flange with its lip.

In the distortional mode that piece moves as a rigid pair rotating about the junction. The flange swings out of its own plane and the lip swings with it, and the whole of the section’s resistance comes from two places: the flange-lip assembly’s own reluctance to rotate along the member, and the web’s reluctance to let the fold line turn.

The second is a spring. A web bent by a rotation imposed at its edge is a plate strip in single curvature, so its rotational stiffness per unit length of member is

kϕ=2Dhw=627 Nmm/rad per mmk_\phi = \frac{2D}{h_w} = 627\ \mathrm{N\,mm/rad\ per\ mm}

for the section here — and a strut restrained continuously by a spring is exactly the object the continuously braced strut turned out to be.

The first is a torsional buckling problem about a fixed pole. The flange-lip pair rotating about the junction has a polar second moment I0I_0 about that line, a St Venant constant JJ, and a sectorial constant CwC_w — and it is CwC_w that carries the surprise.

The whole distortional stiffness is the lip

The sectorial coordinate about a pole is the perpendicular distance from the pole to the tangent of the wall, integrated along it. For the flange that distance is zero, because the flange’s own line passes straight through the junction it is rotating about.

So the flange contributes nothing at all to CwC_w, and the lip contributes all of it:

Cw=tb2dl33C_w = \frac{t\,b^2 d_l^3}{3}

which for the section drawn is 7.13×106mm67.13 \times 10^6\,\mathrm{mm^6}, and which goes as the cube of the lip length.

That is worth sitting with, because it inverts the usual reading of a lipped channel. The lip is normally described as a stiffener for the flange’s local buckling — a way of making the flange a supported plate rather than an outstand — and that is true and is the smaller half of what it does. Its larger job is that it is the only thing preventing the flange from rotating about the web.

Take it away and the distortional stress collapses from 287 N/mm² to 41, which is where local buckling already was.

Three modes, told apart by what movesThe deformed cross-section at each of the three minima of the signature curve, drawn at exaggerated amplitude. In the local mode the fold lines stay put and the flats ripple between them, at a half-wavelength of 200 mm and a stress of 41 N/mm². In the distortional mode the flange and its lip rotate as a rigid pair about the web junction, which the fold lines cannot do in the first mode and which no effective-width calculation contains: 689 mm and 287 N/mm². In the global mode the section keeps its shape entirely and the member goes as a column: 489 N/mm² at the 1.5 m drawn. The middle one is the only one where the section changes shape without any plate rippling, which is exactly why the two ordinary checks miss it.local41 N/mm² at 200 mmdistortional287 N/mm² at 689 mmglobal489 N/mm² at 1500 mm200 × 65 × 15 × 1.5 mm lipped channel in compressionamplitudes exaggerated; the shapes are what distinguish the modes
Fig. 2 The three modes, told apart by what moves. In the local mode the fold lines stay put and the flats ripple; in the distortional mode the fold line itself rotates and the flange and lip go with it; in the global mode the section keeps its shape and the member does not. Only the middle one changes the cross-section without any plate rippling, which is precisely why the other two checks cannot see it.

The closed form is one this collection already has

Put the two pieces together and the distortional stress at a half-wavelength LL is

σd(L)=π2ECwL2+GJ+kϕL2π2I0\sigma_d(L) = \frac{\dfrac{\pi^2 E C_w}{L^2} + GJ + \dfrac{k_\phi L^2}{\pi^2}}{I_0}

which is a term falling as 1/L21/L^2, a constant, and a term rising as L2L^2 — and a function of that shape has a minimum:

σd,min=2ECwkϕ+GJI0atLd=π(ECwkϕ)1/4\sigma_{d,\min} = \frac{2\sqrt{E C_w k_\phi} + GJ}{I_0} \qquad\text{at}\qquad L_d = \pi\left(\frac{E C_w}{k_\phi}\right)^{1/4}

That is the same closed form as the strut on an elastic foundation2kEI2\sqrt{kEI} at a half-wavelength of π(EI/k)1/4\pi(EI/k)^{1/4} — with the sectorial constant where the second moment goes and the web’s rotational spring where the foundation goes. Asking the site’s own strutOnFoundation routine for the continuum answer with those substitutions returns 689 mm, which is the number in the figure.

So the mode nobody checks is not exotic. It is a strut on a foundation, and the foundation is the rest of the section.

The restraint chooses the buckling length, and it is not the member'sA compression flange 9 m long held sideways not at points but everywhere, by a restraint of 0.8 N/mm per mm of length. Unrestrained it would buckle at 307 kN in a single half-wave, drawn faintly. Restrained it buckles at 2870 kN — 9.3 times as much — in two half-waves, because the sum n²π²EI/L² + kL²/n²π² has its minimum there and every other n is worse. The effective length that answer implies is 2944 mm, which is 0.33 of the member and is a property of the restraint rather than of the span.2870 kNthe restraint: 0.8 N/mm per mmtwo half-waves, each 4500 mmunrestrained 307 kN in one half-wave, drawn faintly · effective length 2944 mm
Fig. 3 The same expression in the form this collection derived it in. A continuously restrained strut forgets its own length: its critical load is 2kEI2\sqrt{kEI} with no LL in it anywhere, and its half-wavelength is a property of the strut and the restraint together. A distortional half-wavelength is that number, and it is why the mode has a size of its own that has nothing to do with how long the member is.

Why the lowest elastic stress is not the one that governs

On this section local buckling is at 41 N/mm² and distortional at 287 — a factor of seven — and it is the distortional mode that decides the member.

The reason is post-buckling reserve, and the two modes have very different amounts of it. When a flat plate buckles locally it sheds its middle and the load migrates to the supported edges, which are still straight and still stiff; the effective-width method is a whole design philosophy built on how much load that migration can carry, and for a slender plate it is several times the elastic buckling load.

When a section buckles distortionally there is nowhere for the load to migrate to. The fold line that would have been the stiff edge is the thing that is moving. So the reserve is small, the curve of strength against slenderness lies below the local one, and a section whose elastic distortional stress is seven times its local one can still be governed by the distortional check.

It is also more sensitive to imperfections, for the same structural reason: the mode has less to fall back on, so the slope of the post-buckling path is flatter and the knockdown larger.

Twice the metal is more than twice the sectionThe squash load of the effective section against its thickness, with the gross section's above it. The gross line is straight, because area is linear in thickness. The effective one is not: a thicker plate is both larger and less slender, so it keeps a greater fraction of itself as well as being bigger, and the capacity goes as t^1.47 fitted over the whole sweep. The gap between the two lines is what local buckling has taken — 48% of the section at 1.5 mm — and it closes only at a thickness at which nobody would be cold-forming anything.1.02.03.04.05.06.07.08.0020040060080010001200thickness (mm)squash load of what is left (kN)the section drawnthe section that works126 kNfitted power 1.47 · a section that never buckled gives exactly 1
Fig. 4 The method that cannot see this mode. Effective width computes what is left of each plate after it ripples, one plate at a time, with the fold lines between them treated as supports. A mode in which the supports move is outside its vocabulary entirely.

The lip has an optimum, and past it the lip is the problem

CwC_w goes as the cube of the lip, so a longer lip raises the distortional stress steeply — from 159 N/mm² at 8 mm to 287 at 15 and 453 at 25.

It cannot go on. The lip is itself a plate, free along one edge, and its own local buckling stress falls as the square of its length: 780 N/mm² at 15 mm, 281 at 25. The two curves cross.

A lip is bought for one mode and paid for in anotherThe distortional buckling stress against lip length, with the lip's own local buckling on the same axes. The whole distortional stiffness is the lip — the flange's own line runs through the pole it rotates about, so it contributes nothing to the sectorial constant — and the distortional stress therefore rises steeply with lip length. The lip is a plate free along one edge, at a coefficient of 0.425, so its own stress falls as the square of the same length. The two cross at a lip of 21 mm, 32 per cent of the flange width, at 390 N/mm² — and past that point a longer lip makes the section worse. That is why the ratio in the tables is a ratio and not a minimum.00.10.20.30.40.50.60100200300400500600700lip ÷ flange widthbuckling stress (N/mm²)distortionalthe lip itselfyieldbest at 32% of the flangethe flange contributes nothing to the sectorial constant: its own line runs through the pole
Fig. 5 What a lip is worth, against what it costs. The distortional stress rises as the cube of the lip and the lip’s own buckling stress falls as its square, so there is a best length — 21 mm here, 32 per cent of the flange width, at 390 N/mm² — and beyond it a longer lip makes the section worse.

Which is why the guidance in the tables is a ratio and not a minimum. A lip between about 0.2 and 0.3 of the flange width is not a lower bound that could be exceeded for extra safety; it is a maximum of a curve, and both directions from it are downhill.

The same arithmetic explains the return-lip section — a lip with a further short fold at its end — which raises the lip’s own buckling stress without lengthening it, and moves the crossing point to the right.

What decides which mode a section is in

The three minima move independently, and the design of a cold-formed section is largely a matter of arranging them.

Thickness helps local buckling as t2t^2 and distortional as roughly t1.5t^{1.5}CwC_w and kϕk_\phi both contain tt, and I0I_0 contains it too, so the net dependence is weaker than the plate’s. Taking the section from 1.5 mm to 2.5 mm takes local buckling from 41 N/mm² to 115 and distortional from 287 to 512, which closes the gap between them.

Web depth softens kϕk_\phi, because a deeper web is a longer plate strip and a longer strip is a softer spring. A deep section is therefore more distortionally slender than a shallow one of the same flange, which is the opposite of the direction depth usually helps.

And member length decides only the global curve. That is the practical signature of the middle mode: brace a member harder and the third minimum does not move at all, because LdL_d is a property of the cross-section. A member braced at 500 mm centres still has a distortional half-wavelength of 689, and whether the bracing interferes with the mode depends on whether it restrains the flange rather than the section as a whole.

A 1.5 mm plate, and the width it can beThe elastic critical stress of a plate in compression against its width, with the yield stress drawn across it. Below 69 mm the plate reaches yield before it buckles; above it the plate ripples first, and the fraction of the width still carrying load falls away — at 240 mm only 27 per cent of it is still working.501001502000200400600plate width (mm)slender beyond 69 mmyieldcritical stress — inverse square in the widthwhat the plate actually delivers, over its full width
Fig. 6 The mode at the left-hand end, which is the one the whole cold-formed design method is built on. Its coefficient is computed against a plate width with the fold lines treated as supports — an assumption that is exactly right for this minimum and exactly wrong for the next one along.

The mode is also why a purlin is checked twice

Cold-formed sections are not usually struts. They are purlins and rails, in bending, restrained along one flange by the sheeting they carry — and the distortional question arrives there in a form that looks like a different question entirely.

Under gravity load the sheeting is fixed to the compression flange, which restrains it; under wind uplift the compression flange is the free one, and it has nothing but the web’s rotational stiffness holding it. The two load cases therefore have completely different distortional capacities, and the uplift one is worse by a wide margin.

That is why a purlin’s capacity tables have two columns, and why the smaller number is usually the wind case rather than the snow case even though the loads are similar in size. The sheeting is not doing a small amount of good in one direction and a small amount in the other; it is removing a buckling mode in one direction and leaving it in the other.

It also explains a detail that looks like belt and braces. Anti-sag ties, cleats and the sheeting’s own fixings all restrain the purlin at intervals, and the interval that matters is not the one that controls the global mode — it is whether anything is holding the free flange over a length comparable with a distortional half-wavelength.

A brace on the wrong flange never gets there, however stiff it isThe critical moment of a 6 m beam against the stiffness of a single midspan brace, drawn three times for the three heights the brace could sit at. On the compression flange it climbs from 231 kNm to the two-half-wave plateau of 780 — the beam braced into two 3.0 m beams — and reaches 99% of it at 1097 kN/m. At the shear centre it needs 6766 kN/m, 6.2 times as much. On the tension flange it never arrives at all: at the stiffness that would have done the job on the other flange it has bought a factor of 1.034, and a stiffer brace in the same place buys the same nothing. Past the plateau the beam stops using the brace, which is where the idea of an ideal stiffness comes from.05001000150020000200400600800brace stiffness (kN/m)critical moment (kNm)compression flangeshear centretension flange1097 kN/m is enougha rigid brace buys 3.38, not two
Fig. 7 How much a restraint has to be worth before it counts. A brace on the free flange of a purlin is asked for very little force and a definite amount of stiffness, and whether it is delivering that stiffness is a question about the cleat rather than about the rod.

What a finite-strip analysis is really doing

The curve at the top of this page is what a finite-strip analysis produces, and it is worth saying what that computation is, because the picture is so unlike an ordinary buckling result.

The section is divided into strips along its length, and each strip’s displacement is written as a half sine wave along the member times an unknown shape across it. That reduces a plate-buckling problem in two dimensions to an eigenvalue problem in one — the cross-section — for each assumed half-wavelength separately. Sweep the wavelength and each solve returns the lowest stress at which the section can buckle with that wavelength imposed.

So the curve is not a load path and not a sequence: it is a family of independent answers, and the minima are the wavelengths the section is willing to buckle at cheaply. Reading it as a curve a member travels along is the commonest mistake made with it, and the reason the three minima are usually described as three “modes” rather than as three local minima of one continuous function.

Three paths out of the same critical loadLoad against sideways movement past the critical load, for three systems whose critical loads are identical. The stable one climbs, so a real structure with a small crookedness reaches nearly the full load and keeps going. The unstable one falls symmetrically, so the imperfect structure has a maximum below the critical load and it matters not at all which way it leans. The asymmetric one falls one way and climbs the other, so the direction of the imperfection decides everything. All three are drawn at an imperfection of 0.02 radians.stable symmetric — a columnan imperfection is a nuisancecritical89%unstable symmetric — a shellan imperfection is a demolitioncritical77%asymmetric — a frameand it matters which waycritical
Fig. 8 What happens after each of them. The three minima are three critical loads and say nothing about what the section does next — and what it does next is the whole reason the middle one governs a strength calculation that the lowest one does not.

Where the model stops

The flange and lip are treated as rigid in their own planes. They are, very nearly, in the distortional mode — the mode is a rotation — but a real distortional shape has some plate bending in the flange too, which softens it and lowers the stress by a few per cent.

The web’s spring is taken as 2D/hw2D/h_w, which assumes the two flanges rotate symmetrically outward and the web bends in single curvature. An antisymmetric mode, where one flange goes in and the other out, sees a different stiffness; and a web carrying its own compression is softer still, because its axial stress reduces its bending stiffness — an effect that matters most for exactly the deep webs where distortional buckling is worst.

The local curve is computed element by element with simply supported junctions. That underestimates the local minimum, because the flange restrains the web and vice versa, and the underestimate is why the gap between the first two minima here is wider than a finite-strip analysis would give.

And the whole essay is about uniform compression. A section in bending has a different stress distribution over its plates, a different local coefficient, and a distortional mode that involves only the compression flange — which is a different eigenvalue problem with the same mechanism.

What the pictures cannot show

The signature curve is a plot of eigenvalues against an assumed half-wavelength, and every point on it is a different buckling problem. It is not the response of any one member: a real strut of a given length does not travel along it.

What a real member does is buckle in whichever mode its length permits, at whichever stress that mode reaches — and a member long enough for the distortional wavelength to fit will find it. The curve is a map of what is available, and the member’s length decides what it may reach.

Nor can the deformed shapes show what a distortional failure looks like on a test rig, which is a section whose flanges have opened outward like a book over a length of half a metre, with the lips folded and the web still nearly flat. It is not a subtle failure. It is only subtle in the calculation.

The assumption the figure rests on

Every number here assumes the fold line between web and flange is a hinge with a known rotational stiffness and no other freedom.

That is an idealisation of a corner with a radius of several thicknesses, formed by bending, work-hardened, and carrying residual stresses from the forming operation. The radius softens the spring; the work hardening raises the local yield stress at the one point of the section that carries the most curvature; and the residual stresses are self-equilibrating through the thickness and mean the section starts life bent.

The consequence is that distortional buckling is the mode where a section’s manufacturing history matters most, because it is the mode whose stiffness lives entirely in the corner and in the lip — the two parts of the profile that the roll-forming line, rather than the designer, decides.

A channel has three critical loads, not oneThe three critical loads of a channel in compression, against its length, with the load it actually buckles at drawn over them. At 2600 mm the flexural loads are 25315 kN about the major axis and 4179 kN about the minor, while twisting about the shear centre takes 2470 kN. The lowest root is 2372 kN, and the column twists. The shear centre sits 109.7 mm from the centroid, so the modes cannot happen separately: the lowest root of the coupled problem is 4.0 per cent below the lowest of the three, and the Wagner coefficient β is 0.60. The governing mode changes at 5813 mm: below that length the column twists, above it, it bends — because the torsional resistance keeps a term that does not grow when the member is shortened, and the flexural loads have none.4000600080001000012000140000500100015002000length of the column (mm)critical load (kN)flexural about ytorsionalflexural about zthe mode changes at 5813 mmthe lowest root — what the column actually does
Fig. 9 The mode this one is a restrained version of. A whole section twisting about its own shear centre is torsional buckling; a flange twisting about the web junction is the same equation applied to a piece of the section, with the rest of it acting as the restraint.

Named alongside this one

Essays reaching for the same objects. Nobody chose these; they are what the concept index makes visible.

The objects this essay names

Each one links to every other essay that touches it.

Cold formed sectionDistortional bucklingEffective widthElastic foundationHalf wavelengthImperfection sensitivityLipLocal bucklingPlate bucklingPost bucklingRotational restraintSignature curveSlendernessTorsional bucklingWarping