Dynamics

The machine that shakes the building

Put a machine on springs to keep its vibration out of the floor, and below a frequency ratio of root two the springs make things worse. Every transmissibility curve ever drawn passes through exactly one at that ratio, whatever the damping — so a soft mount either works well or fails badly, with nothing in between.

Assumes The only thing that stops it and The floor that is strong and unusable.

A fan on a roof runs at 900 rpm — 15 Hz — and its rotor is not perfectly balanced, so it applies a rotating force of a few hundred newtons to whatever it stands on. Bolted directly to the slab, that force goes into the building and is felt three floors down.

The remedy is to put the fan on springs, and the remedy has a trap in it.

How much of a force a mount lets through, at three damping ratiosThe force transmitted to the support divided by the force applied, against the ratio of the forcing frequency to the structure's own, at 2%, 5%, 20% of critical damping. Every curve passes through exactly 1 at a frequency ratio of root two, whatever the damping: below that ratio a mount amplifies what it was installed to isolate, and above it more damping lets more through.00.511.522.533.540510152025forcing frequency ÷ natural frequencyforce out ÷ force in√2 — nothing gained, at any damping2% damping5% damping20% damping
Fig. 1 The fraction of a machine’s force that reaches the floor beneath it, against the ratio of the machine’s running frequency to the natural frequency of the machine on its mounts. Every curve passes through exactly 1.000 at a ratio of √2 — for every damping ratio, without exception. To the left of that line the mount transmits more than a rigid connection would; to the right it transmits less.

The crossing at root two

The transmissibility is

T=1+(2ζβ)2(1β2)2+(2ζβ)2T = \sqrt{\frac{1 + (2\zeta\beta)^2}{(1-\beta^2)^2 + (2\zeta\beta)^2}}

and setting β2=2\beta^2 = 2 makes (1β2)2=1(1-\beta^2)^2 = 1, so the numerator and denominator become identical and T=1T = 1 exactly, for every ζ\zeta. It is not an approximation and it is not a coincidence of the algebra — it is the frequency at which the spring’s force and the inertia force are equal and opposite in a way that leaves the transmitted force unchanged.

The practical content is a design rule with a hard edge:

Below √2 the mount amplifies. At a ratio of 1.2 with 5% damping the transmissibility is 2.21 — the floor receives more than twice what it would have received without any springs. At the resonance itself it is 10.

Above √2 the mount isolates, and increasingly: 0.34 at a ratio of 2, 0.13 at 3, 0.047 at 5.

So a mount is either right or badly wrong, and the boundary is not where intuition puts it. A mount whose natural frequency is anywhere near the machine’s running speed is worse than no mount at all, and the natural frequency of a machine on springs is not something a supplier’s catalogue always makes obvious.

The static deflection is the specification

There is one number a mount designer actually works with, and it comes from a rearrangement of the frequency formula. The natural frequency of a mass on a spring that deflects δ\delta under its own weight is

fn=12πgδ15.8δf_n = \frac{1}{2\pi}\sqrt{\frac{g}{\delta}} \approx \frac{15.8}{\sqrt{\delta}}

with δ\delta in millimetres — the same 18/δ18/\sqrt{\delta} family as a floor’s frequency, with a different constant because the mass is concentrated rather than distributed.

That makes the specification concrete. To get the 15 Hz fan to a ratio of 3, its mounts must have a natural frequency of 5 Hz, which needs a static deflection of 10 mm. To get to a ratio of 5, the mounts need 25 mm.

A vibration isolator is specified by how far it sags, and everything else follows. That is why isolators are catalogued by deflection, why a heavier machine on the same springs isolates better, and why the commonest installation error — a mount so stiff that it barely deflects — produces a machine that is bolted to the floor through an expensive spring.

Damping, which helps in one place and hurts in the other

How much of a force a mount lets through, at three damping ratiosThe force transmitted to the support divided by the force applied, against the ratio of the forcing frequency to the structure's own, at 1%, 5%, 30% of critical damping. Every curve passes through exactly 1 at a frequency ratio of root two, whatever the damping: below that ratio a mount amplifies what it was installed to isolate, and above it more damping lets more through.0123450510152025forcing frequency ÷ natural frequencyforce out ÷ force in√2 — nothing gained, at any damping1% damping5% damping30% damping
Fig. 2 The same curves over a wider range and with a heavily damped mount included. At the resonance the 30% mount transmits 1.9 against the 1% mount’s 50 — an enormous benefit. At a ratio of 4 it transmits 0.28 against 0.07 — four times worse. The damping that saves the machine during run-up is the damping that spoils it at running speed.

The reason is in the numerator of the transmissibility. A dashpot connects the machine to the floor directly, and a dashpot’s force is proportional to velocity, so it grows with frequency: at high ratios the dashpot is the main path by which force reaches the floor, and the spring has stopped being the problem.

That produces a genuine engineering trade with no clever answer:

A machine that starts and stops often has to pass through its mount’s resonance twice per cycle of operation. Passing through quickly helps — the build-up needs cycles, not seconds — and damping helps.

A machine that runs continuously wants as little damping as possible.

The usual compromise is a mount with 5–10% damping, and for the run-up problem the better answer is often a snubber: a device that does nothing at all during normal running and limits the motion only when the amplitude exceeds a threshold, so that the damping is present at resonance and absent at running speed.

5 kN at 1.00 times the natural frequency, on a structure of 0.200 s periodDisplacement against time for a single-degree-of-freedom structure of natural period 0.200 s and 5.0% damping, under 5 kN at 1.00 times the natural frequency. The static deflection under the same peak force is 10.13 mm and the peak response is 101.32 mm — a factor of 10.00.012345678-100-5050100time (s)displacement (mm)5 kN at 1.00 times the natural frequencysteady amplitude 101.32 mmstatic, 10.13 mmpeak 101.32 mm at 8.00 s
Fig. 3 What happens if the mount is wrong. The same machine, the same unbalanced force, at exactly the mount’s own frequency: the amplitude builds over about eight cycles to ten times the static deflection, and everything it produces goes into the floor. A machine that passes through this on the way to running speed does so in a second or two and survives; a machine that runs here does not.
What the shape of a load in time is worth, for one load shapeThe peak displacement as a multiple of the static deflection, against the load's duration divided by the structure's natural period, for one load shape: a load that rises linearly, then stays. The lines are closed forms and four dots are the peak of a complete time integration of an oscillator of 0.200 s period under that load, agreeing with the line to within 0.00% everywhere.00.511.522.500.511.52load duration ÷ natural periodpeak ÷ static deflectiontwice the static answerthe static answera load that rises linearly, then stays
Fig. 4 And the reason passing through quickly helps, in its most general form: a load applied over a rise time comparable with the natural period produces almost no dynamic effect at all. A machine that accelerates through its mount’s resonance in a fraction of the build-up time never develops the response the steady-state curve threatens.

The same curve, read backwards

5 kN at 3.00 times the natural frequency, on a structure of 0.200 s periodDisplacement against time for a single-degree-of-freedom structure of natural period 0.200 s and 5.0% damping, under 5 kN at 3.00 times the natural frequency. The static deflection under the same peak force is 10.13 mm and the peak response is 4.78 mm — a factor of 0.47.0123456-20-101020time (s)displacement (mm)5 kN at 3.00 times the natural frequencysteady amplitude 1.27 mmstatic, 10.13 mmpeak 4.78 mm at 0.049 s
Fig. 5 The isolated machine’s own motion at three times its mount frequency: the mass moves very little, and what motion there is settles immediately. The isolation is not achieved by the mount absorbing anything — it is achieved by the machine’s own inertia refusing to follow the force, so that the force is spent accelerating the machine rather than pushing the floor.

That reading explains the identity the transmissibility curve hides: the fraction of a force that gets through a mount equals the fraction of a motion that gets through it.

Isolating a machine from a floor and isolating an instrument from a floor are the same calculation read in opposite directions. In the first, the source is the machine and the receiver is the building; in the second, the source is the building and the receiver is an electron microscope, an optical table or a recording studio. The equation does not distinguish them, so an isolation table for a microscope is specified in exactly the same way — by static deflection, with the same √2 warning, and with the same requirement that the mount’s frequency be well below whatever is shaking the floor.

Which is why the two problems have the same failure. A microscope table with a 5 Hz mount, in a building whose floor has a 5 Hz mode, amplifies exactly what it was bought to remove.

Two-stage isolation, and why it is used

When a single mount cannot reach the ratio needed — because the machine’s speed is low, or the isolation demanded is severe — the answer is to isolate twice: machine on springs, on an inertia block, on a second set of springs.

The reason it works is worth stating, because it looks like a series arrangement and behaves like one only in part. Above both resonances the transmissibility of two stages falls as the fourth power of the frequency ratio rather than the second — so where a single stage at a ratio of 3 gives 0.13, two stages give something nearer 0.02. The price is a second resonance to pass through and a system with two closely spaced modes, which is the arrangement a mass on a spring on a spring always produces.

20% of the mass, hung on a spring, against the peak it removesThe magnification of a structure with 2.0% damping, with and without a tuned mass damper of 20.0% of its mass, tuned to 0.8333 of its frequency with 25.0% damping of its own. The bare peak is 25; with the absorber the single peak becomes two of 3.11, a reduction to 12% — a factor of 8.0. The marked points at frequency ratios 0.763 and 1.041 are the fixed points: the response there is the same whatever damping the absorber is given, which is what makes the optimum a question with an answer. The absorber's own stroke at the worse of the two peaks is 5.4 times the structure's static deflection, and that stroke is what decides whether it fits.11.522.530510152025forcing frequency ÷ the structure's ownamplitude ÷ static deflectionno absorber — peak 2520.0% absorber — peak 3.11a factor of 8.0, for 20.0% of the mass
Fig. 6 Two masses and two springs, drawn as the two-degree-of-freedom system they are. The two peaks are the two modes of the combined system, and past the upper one the response falls much faster than a single-stage curve does. A tuned mass damper and a two-stage isolator are the same system with different design intents: one arranges the two modes to be small, the other arranges to work above both of them.

The inertia block, and why the floor is not rigid

Everything above assumes the floor beneath the mounts does not move. It does, and the assumption fails in the case that matters most.

The mount’s isolation is really the ratio of the machine’s stiffness to the floor’s. If the floor is very stiff compared with the mounts, the calculation above holds. If the floor is a long-span composite deck with its own 5 Hz mode and a modest modal mass, the “rigid support” the springs are reacting against is itself a spring, and the two-degree-of-freedom system that results does not behave like either.

The standard remedy is a inertia block: a concrete raft, several times the machine’s mass, sitting on the isolators with the machine bolted to it. It works in three ways at once, and only the first is obvious.

It lowers the natural frequency for a given spring, because the mass is larger — improving the ratio.

It reduces the machine’s own motion, because the unbalanced force now accelerates a much larger mass. That matters for the machine’s alignment and bearings rather than for the building.

It presents a large mass to the floor, so that the floor’s own modal mass is no longer small compared with what is standing on it, which is the condition under which the rigid-support assumption becomes reasonable again.

Which floor frequencies a 2 Hz pace punishesThe response factor of a floor of 12 tonnes modal mass and 3.0% damping, against its own natural frequency, under a walker at 2 steps per second. The peaks are at 2, 4, 6, 8 Hz — the harmonics of the pace — and they fall away sharply: four peaks, each smaller than the one below it, because the harmonics of walking get smaller. A floor at 2 Hz reaches R = 31 and one at 8 Hz reaches 6. Between them the floor is quiet.2345678910051015202530floor frequency (Hz)response factor1× pace2× pace3× pace4× pace5 Hz — R = 2
Fig. 7 Why the floor’s own dynamics cannot be ignored: the same floor plate that a walker excites at particular frequencies is the support a machine mount reacts against. A mount tuned without reference to the floor’s modes is a calculation about a support that does not exist.
Where the energy goes: one loop in force against displacementThe force the supports feel — the spring's and the damper's together — against the displacement, for one mechanism. viscous, 5% of critical, enclosing 11.07 kJ over the record drawn. The viscous loop is an ellipse whose area is proportional to the frequency it is traced at.-100-5050100-40-202040displacement (mm)restoring force (kN)viscous, 5% of critical — 11.07 kJ
Fig. 8 Where the energy goes while a mount is at its resonance: the force the floor feels, plotted against the machine’s motion. The loop’s area is the energy the mount’s dashpot dissipates, and the ellipse’s height is the force reaching the structure — which at resonance is ten times the unbalanced force. Both quantities are what a mount exists to control, and they are controlled by different parts of it.

The commonest way it is got wrong

Three failures account for most unsatisfactory installations, and none of them is a calculation error.

The mount is chosen for the load rather than for the deflection. A supplier’s mount rated for the machine’s weight may deflect 3 mm under it, giving a natural frequency of 9 Hz, which for a 15 Hz machine is a ratio of 1.7 — barely past √2, transmitting 70% of the force. The right question is never “will it carry the machine” but “how far will it sag”.

The mounts are not equally loaded. A machine whose centre of gravity is not at the centre of its mount pattern sits with some springs compressed further than others, so the mount frequencies differ, the machine rocks, and the rocking modes are lower than the bouncing one. Levelling a machine by adjusting its mounts is a dynamic operation dressed as a fitting one.

Something rigid was left connected. Conduit, drain, duct, or a handrail welded to both the machine frame and the building. The mount’s transmissibility of 0.05 and the pipe’s transmissibility of 1.0 are in parallel, and parallel paths add.

All three share a shape worth noticing: the calculation was right and the installation was not, and no analysis of the design would have found any of them. This is a field where commissioning matters more than modelling, which is the same conclusion the tuned mass damper reached from a different direction.

What the picture cannot show

Six degrees of freedom, not one. A machine on mounts can bounce, rock in two planes, and yaw, and each of those has its own frequency. The bouncing mode is the one the curve above describes; the rocking modes are usually lower and are the ones that produce the complaint. A mount layout is chosen to keep the rocking frequencies out of trouble, which is a geometry problem rather than a stiffness one.

The excitation is not one frequency. A rotating machine produces its running speed, twice it from misalignment, blade-passing frequencies, gear-mesh frequencies, and bearing defect frequencies — a whole comb. A mount that isolates the fundamental isolates the higher ones better, which is the one part of this that is easy.

Pipes, ducts and conduit bypass everything. A perfectly isolated machine connected to the building by a rigid pipe is not isolated. Flexible connections at every service are as important as the mounts and are more often forgotten, and the mechanism is the series-spring argument — the stiffest parallel path wins, and a steel pipe is very stiff.

Static deflection is not the whole of a mount. A rubber mount’s stiffness depends on frequency and temperature; a steel spring’s does not, but a steel spring transmits high frequencies through its own internal resonances, which is why spring mounts are usually fitted with a rubber pad in series.

Why this is a serviceability problem with a strength tail

Almost everything in this essay is about comfort and function rather than about collapse, and it is worth saying where the exception is.

A badly isolated fan makes a building unpleasant. A badly isolated reciprocating machine — a compressor, a press, an engine — applies forces large enough to matter structurally, and a resonance can put a genuine multiple of them into a floor that was designed for a static equivalent. The tell is that the unbalanced force of a rotating machine goes as the square of the speed, so a machine that is acceptable at half speed can be ten times worse at full speed while nothing else about it changed.

There is a second tail, and it is fatigue. A mount running near its resonance transmits an amplified force at a rate of 15 per second, which is half a million cycles a day. Nothing about the magnitude has to be dramatic for that to matter to a welded detail, and machine-induced fatigue cracking in supporting steelwork is a recognised failure that leaves no trace on any static calculation.

Where the ladder goes

The immediate rung down is the machine foundation as a whole: a heavy reciprocating machine on the ground, where the “floor” is soil, the support stiffness is a soil property and the damping is radiation into the half-space rather than anything material. It is the one place in structural engineering where the damping is both large and calculable.

The rung sideways is what to do when isolation is impossible because the machine must be rigidly connected — in which case the remedy moves to the receiver, and becomes an added mass on the structure rather than a spring under the source.

And the rung up is the observation that this whole essay is one figure read carefully. The transmissibility curve contains the isolation rule, the damping trade, the specification by deflection, and the identity between force isolation and motion isolation. It is the most economical picture in the field, and the crossing at √2 is the reason it repays being drawn rather than remembered.

It is also the field’s clearest instance of a general habit worth carrying out of it. The rule “put it on springs” is not wrong; it is a rule with a domain, and the domain has a boundary at a specific and calculable place. Almost every rule of thumb in this collection is like that — the equal-displacement rule, the check-the-furthest-bolt rule, “raise the frequency above 4 Hz” — and the useful question about any of them is never whether it is true but where it stops.

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DampingFrequency ratioInertia blockMachine foundationResonanceServiceabilityTransmissibilityVibration isolation