Internal forces

The moment that will not lie flat

A plane cut exposes three actions. A real cut exposes six, and the fourth of them behaves unlike the others — torsion is resisted by a loop of shear, and one slit down the length of a tube destroys it.

Assumes What a cut reveals, and why it was there all along and The shear nobody draws.

A cut through a beam exposes three quantities: an axial force, a shear force and a bending moment. That is the plane problem, and it is the whole of most of this subject.

A cut through a member in three dimensions exposes six — three forces and three moments, one of each along and about each axis. Two of the extra three are simply the plane case turned on its side: a second shear and a second bending moment, obeying every rule the first pair obeys. The sixth is different in kind.

Torsion is the moment about the member’s own axis, and nothing else on the list resists the way it does. A bending moment is carried by direct stress varying linearly across the section, which makes the second moment of area the governing property. A torsional moment is carried by shear stress circulating around the section — and whether it can circulate at all depends on something no other action cares about: whether the section is a closed loop.

One slit, and the torsional stiffness falls by a factor of hundreds. A 200 by 200 box of 8 mm wall, drawn closed and then slit along its length. Closed, the torque runs round the wall as a shear flow and the torsion constant is 5.66×10⁷ mm⁴; slit, the loop is broken and only each wall's own thickness resists, giving 1.31×10⁵ mm⁴. The ratio is 432 to one, so the same torque twists the slit section 432 times as far and raises a peak shear stress 36 times as high. Nothing about the material changed.
Fig. 1 The same box of steel drawn twice: closed, and then slit along its whole length. The wall thickness, the outside dimensions, the material and the applied torque are identical. The torsion constant falls by a factor of 432, and the twist rises by the same factor — from 0.19° over three metres to 81°. Nothing about the amount of material changed; a saw cut of zero width removed the loop.

That factor is not a detail. It is the reason a member expected to twist is specified as a hollow section, and the reason an eccentric load on an I-beam is normally resolved by adding a member to take the eccentricity out rather than by calculating the twist. Torsion is the one action in this subject that is more often designed away than designed for, and the ratio above is why: the cheapest torsional design is almost always a load path that does not produce any.

Two mechanisms, and only one of them is a loop

A closed section carries torque by shear flow: a constant flow qq running all the way round the wall, at every point tangential to it. Bredt’s formula follows from equilibrium alone. Take moments of the flow about any point inside the section, and the total is 2Amq2A_m q where AmA_m is the area the wall’s centreline encloses — twice the area, because a flow round a closed loop sweeps the enclosed area twice in the moment integral. So

q=T2Am,J=4Am2ds/tq = \frac{T}{2A_m}, \qquad J = \frac{4A_m^2}{\oint \mathrm{d}s/t}

Both of those are properties of the hole, not of the metal. The enclosed area appears squared in the torsion constant, which is why a hollow section’s torsional stiffness is so brutally sensitive to its outside dimensions and so mildly sensitive to its wall.

Slit the tube and the loop is gone. There is no path for a circulating flow, and all that remains is each wall plate twisting through its own thickness — a shear flow that runs up one face of the plate and back down the other, cancelling at the mid-thickness. Its lever arm is the plate’s thickness rather than the section’s size, and the resulting constant is

J=13bt3J = \frac{1}{3}\sum b t^3

with the thickness cubed. For a wall a fortieth of the section’s width, the ratio between the two mechanisms is on the order of a thousand.

One slit, and the torsional stiffness falls by a factor of hundreds. A 200 by 200 box of 4 mm wall, drawn closed and then slit along its length. Closed, the torque runs round the wall as a shear flow and the torsion constant is 3.01×10⁷ mm⁴; slit, the loop is broken and only each wall's own thickness resists, giving 1.67×10⁴ mm⁴. The ratio is 1801 to one, so the same torque twists the slit section 1801 times as far and raises a peak shear stress 74 times as high. Nothing about the material changed.
Fig. 2 The same comparison with the wall halved to 4 mm. The closed section’s constant falls by about a factor of two, as Bredt’s formula says it must, because the wall appears once. The open section’s falls by a factor of eight, because the thickness appears cubed — so halving the wall makes the ratio between them four times worse. Thin-walled open sections are the worst possible torsion members and they are the commonest shapes in the steel catalogue.

There is a second thing hiding in J=13bt3J = \frac{1}{3}\sum bt^3, and it is stranger than the cube. The formula contains the plate lengths and the plate thicknesses and nothing about how the plates are arranged. Fold a strip into a channel, bend it into an angle, leave it flat: the torsion constant does not move.

Closed or open, and after that the shape has nothing to say. The torsion constant of six sections on a logarithmic axis, all of them made from plate of the same thickness. The two closed cells stand orders of magnitude above everything else, because a closed loop can carry a shear flow all the way round and an open one cannot. Below them the open sections are almost level with one another: J_open = Σbt³/3 contains the plate lengths and thicknesses and nothing about the arrangement, so a channel, an angle and a flat strip rolled from the same plate are the same section in torsion. No other property in this collection behaves that way — second moment of area, radius of gyration, section modulus and shear centre all change completely between those three.
Fig. 3 The torsion constant of six sections on a logarithmic axis, every one of them made from plate of the same thickness. The two closed cells stand orders of magnitude above the rest, because a closed loop can carry a shear flow all the way round and an open one cannot. Below them the open sections are almost level with one another — a channel, an angle and a flat strip rolled from the same plate are the same section in torsion.

No other property in this collection behaves that way. Second moment of area, radius of gyration, section modulus and shear centre all change completely between a flat strip and a channel folded from it, and each of them is a statement about where the material was put. The torsion constant of an open section is not: it is a statement about how much plate there is and how thick it is, and the arrangement that every other calculation turns on has no vote.

Which free body produced the number

Take the closed 200 × 200 × 8 box. The wall centreline dimensions are 192 by 192, so the enclosed area is Am=36,864 mm2A_m = 36{,}864\ \text{mm}^2 and the centreline perimeter is 768 mm.

Bredt: J=4Am2/(ds/t)=4×36,8642/(768/8)=5.44×109/96J = 4 A_m^2 / (\oint \mathrm{d}s/t) = 4 \times 36{,}864^2 / (768/8) = 5.44 \times 10^9 / 96, which the figure prints as 5.66×107 mm45.66 \times 10^7\ \text{mm}^4.

The open case: J=13×768×83=1.31×105 mm4J = \frac{1}{3} \times 768 \times 8^3 = 1.31 \times 10^5\ \text{mm}^4. The ratio is 432, and the closed form for a square tube — Jclosed/Jopen=3b2/4t2J_{\text{closed}}/J_{\text{open}} = 3b^2/4t^2 — reproduces it exactly — 3×1922/(4×82)=4323 \times 192^2 / (4 \times 8^2) = 432 — which is the independent check the generator is held to. Halve the wall and the same two formulas give 1801, because one of them contains the thickness once and the other contains it three times.

The free body in each case is a slice of the member one unit long, cut on two planes perpendicular to the axis. The torque applied to that slice must be balanced by the moment of the shear stresses on the cut face about the axis. For the closed section those stresses run round the loop and their moments add. For the open one they run up and back within each plate, and their moments nearly cancel — what survives is the small residue from the two halves of the plate being at slightly different radii, and “slightly” is the whole factor of hundreds.

The assumption the figures rest on is that the section is free to warp: that nothing at the ends prevents the cross-section from distorting out of its own plane. That assumption is what makes JJ the only property needed, and the next section is about what happens when it fails.

Warping, which no other stress resultant does

Under torsion, an open section does something unique among the six stress resultants: the cross-section does not stay plane. The flanges of an I-section displace along the beam’s length, one forward and one back, so a plane cut becomes a warped surface. Plane sections staying plane — the assumption the whole of bending theory rests on — is simply false here, and not as a small correction.

If the warping is free, nothing follows from it; the section warps and that is all. If it is restrained — at a fixed end, at a stiffener, at a moment connection — then the fibres that wanted to move along the beam cannot, and direct stresses appear to stop them. Those stresses are not in any of the six stress resultants. They are a seventh action, the bimoment, and warping torsion is a separate calculation added to the St Venant one.

The two mechanisms share the torque in a proportion that depends on length:

T=GJθSt Venant+EIwθwarpingT = \underbrace{GJ\,\theta'}_{\text{St Venant}} + \underbrace{-EI_w\,\theta'''}_{\text{warping}}

The first term does not care about length; the second does, and dominates for short members. So a short cantilevered I-section in torsion is held mostly by warping restraint, and a long one mostly by the feeble St Venant mechanism — the opposite of the intuition that a short member is stiffer in every respect.

This is the same IwI_w that appears in lateral-torsional buckling, and for the same reason: a beam buckling sideways twists as it goes, and the twist is resisted by both mechanisms at once. The two-regime shape of the buckling curve is this equation’s shape.

The flow that also does the shearing

The shear flow in torsion is the same object as the shear flow that carries transverse shear — the same qq, in the same wall, measured in force per unit length. The two superpose.

The interaction has a consequence that catches people out. In a closed section under combined shear and torsion, the two flows add on one wall and cancel on the opposite one, so the critical wall is not the one carrying the most shear and not the one carrying the most torsion, but the one where they happen to agree in sign. That asymmetry is why a box girder on a curved alignment carries a heavier wall on the outside of the curve than on the inside, from a torque that is the same all the way round.

The cleanest demonstration that two flows in the same wall subtract is a box with a wall shared between two loops.

The web down the middle carries no torsion at all. A 2-cell box 3.0 m wide and 1.5 m deep under 4000 kNm of torque. Statics gives one equation, T = 2 Σ q_i A_i, and there are 2 unknown flows — so the section is torsionally redundant and the missing statements are that every cell twists by the same amount. Solving that system gives 444.4 and 444.4 N/mm in the cells, so the internal web carries 0.00 N/mm — 0.00 per cent of the outer wall's. J is 2.3679e+12 mm⁴ against 2.3679e+12 for the same outline with no internal web at all, a ratio of 1.000000. The same walls slit open would give 7.413e+10, so closure is worth 32 times and the internal web is worth what the ratio says.
Fig. 4 A two-cell box 3.0 m wide and 1.5 m deep under 4,000 kNm of torque. Statics supplies one equation — the torque is twice the sum of each flow times its own enclosed area — against two unknown flows, so the section is torsionally redundant, and the missing statement is that both cells twist by the same amount. Solving that gives 444.4 N/mm in each cell, so the flows meeting in the internal web run opposite ways and cancel exactly: the web carries 0.00 N/mm.

The consequence is worth stating plainly, because it contradicts what a web looks like it is for. The torsion constant of that box is 2.3679 × 10¹² mm⁴, and the constant of the same outline with the internal web deleted is 2.3679 × 10¹² — a ratio of 1.000000. The web is carrying no torsion whatever. Slit the outer walls and the same section gives 7.413 × 10¹⁰, so closure is worth a factor of 32 and the internal web is worth nothing at all; it is in the girder to carry vertical shear and to stop the plates from distorting, and neither of those is this action.

The shear centre of a channel. A channel of 80 by 200, with the shear flow in its flanges drawn. Those flows form a couple, so the load has to be applied 31.7 outside the web to leave the section untwisted — a point in the air, outside the material entirely.
Fig. 5 The point through which a transverse load must pass if it is not to twist the section — and for a channel it lies outside the metal entirely. This is where torsion enters a structure that nobody intended to twist: a load applied anywhere but here carries a torque equal to the load times its offset, and an open section receives that torque with the feeblest of the six resistances.

The shear centre is where the two subjects meet. It is defined by torsion — it is the point about which the transverse shear flow has no net moment — and it is the reason ordinary beams end up twisting: the load is applied at the web, the shear centre is somewhere else, and the difference is a torque.

The stiffness ratio and the stress ratio are not the same number

The figure above reports two comparisons between the closed box and the slit one, and they are a factor of twelve apart. The torsion constant falls by 432. The peak shear stress rises by only 36 — from 8.5 N/mm² to 305. Both are correct, and the gap between them is worth understanding because it decides which check governs.

The two ratios measure different things. Stiffness is torque per unit twist, and it compares JJ directly. Stress is torque per unit of area-times-lever, and the two mechanisms distribute their stress over different amounts of material:

τclosed=T2Amt,τopen=TtJopen\tau_{\text{closed}} = \frac{T}{2A_m t}, \qquad \tau_{\text{open}} = \frac{T\,t}{J_{\text{open}}}

so their ratio is 2Amt2/Jopen=2×36,864×64/1.31×105=362A_m t^2/J_{\text{open}} = 2 \times 36{,}864 \times 64 / 1.31\times10^5 = 36, against the 432 in stiffness. The open section is a twelfth as bad in stress as it is in stiffness, because the feeble circulating flow it does manage is spread over both faces of every plate rather than concentrated anywhere.

The relationship between the two penalties is not a coincidence of this box, and the thin circular tube is where it can be seen exactly.

The stiffness penalty is the square of the stress penalty. For a thin circular tube the comparison between closed and open is exact and contains nothing but the slenderness of the wall: J_closed/J_open = 3(r/t)² and τ_open/τ_closed = 3(r/t). Both curves are drawn against r/t. At r/t = 19 — the tube this family draws — the stiffness ratio is 1055 and the stress ratio 56. The gap between them is why an open section in torsion almost never fails by shear: it twists out of usefulness first, by a factor of r/t, and a serviceability limit arrives long before a strength one.
Fig. 6 For a thin circular tube the closed-against-open comparison contains nothing but the slenderness of the wall: the stiffness penalty is 3(r/t)² and the stress penalty is 3(r/t), both drawn against r/t. At the r/t of 19 this family draws, they are 1055 and 56. The stiffness penalty is the square of the stress penalty, so the gap between them is r/t itself and it widens with every thinner wall.

That is the general form of the twelve. The two ratios are not independent numbers to be looked up; one is the square of the other, and the factor separating them is the wall slenderness — nineteen for the tube drawn, twelve for the square box computed above. A thinner wall makes an open section worse in stress and very much worse in twist, and the second gets worse faster.

The consequence is a rule about which limit arrives first. Take a member sized so that both versions are at the same fraction of their strength: the open one is then twisting twelve times more than the closed one at the same utilisation. Push it to a working stress of, say, 100 N/mm² and the closed box has rotated by almost nothing while the slit one has rotated through an angle that would be visible from the ground.

So an open section in torsion is a serviceability member, not a strength member. It runs out of acceptable rotation long before it runs out of shear capacity — twelve times sooner on this geometry — and a check that computes only the stress will report a comfortable pass on a member that has twisted a cladding panel off its fixings. Stiffness is not strength is the general form of that, and torsion is where the gap between the two is widest of anything in this collection.

It also explains a piece of practice that looks like superstition. The usual response to a torsion problem is to close the section — a plate across the open face of a channel, a bottom flange plate on a spandrel — rather than to thicken it. Thickening buys stress capacity, which was not the binding constraint; closing buys the two orders of magnitude in stiffness, which was.

Where the model stops

Thin walls. Bredt’s formula assumes the shear flow is uniform across the wall thickness, which is accurate when the wall is thin compared with the section’s size and progressively wrong as it thickens. For a solid section neither formula applies, and the classical solutions — Saint-Venant’s, obtained by solving a Poisson equation over the cross-section — are needed instead. A solid circular shaft is the one case where the elementary treatment is exact.

A soap film over a hole, and its volume is the torsion constant. The stress function for Saint-Venant torsion of a square of 100 mm, relaxed on a 97 by 97 grid until it stopped moving — 385 sweeps. Its contours are the lines the shear stress runs along, its slope is the magnitude of that stress, and twice its volume is the torsion constant: 1.4053e+7 mm⁴ against a closed form of 1.4058e+7, an error of -0.035 per cent. The steepest slope is 67.515 at the boundary, at the point on it nearest the centre — which is why the peak shear in a solid section is at the middle of the longest side and never at a corner, where the film comes down to zero from two directions and its slope vanishes.
Fig. 7 Saint-Venant’s stress function for a solid 100 mm square, relaxed on a 97 by 97 grid until it stopped moving — 385 sweeps. Its contours are the lines the shear stress runs along and its slope is the magnitude of that stress, and twice the volume under it is the torsion constant: 1.4053 × 10⁷ mm⁴ against a closed-form 1.4058 × 10⁷, an error of 0.035 per cent. The steepest slope is 67.515, on the boundary at the point nearest the centre.

That last number settles a question the elementary theory gets exactly wrong. The peak shear in a solid section is at the middle of the longest side, where the surface comes down most steeply, and it is zero at the corners, where the film descends to nothing from two directions at once and its slope vanishes. Coulomb’s circular result, carried over to a rectangle, predicts the opposite — maximum stress at the corners, furthest from the axis — and it is the corners that a free surface forbids from carrying any shear across itself at all.

Multiple cells. A box girder with internal webs has more than one loop, and the flows in them are not independently determined by statics: the section is torsionally redundant, and compatibility of twist between cells has to be enforced. A three-cell box is a small simultaneous system before it is anything else.

Distortion. A thin-walled box under eccentric load does not only twist; the cross-section also distorts, the rectangle becoming a parallelogram in its own plane. Distortion is neither torsion nor bending, it has its own stresses, and it is the reason box girders carry internal diaphragms at intervals.

Uniform torque. The two-mechanism split assumes the torque is applied at the ends and constant along the member. A torque applied gradually along the length — as it is on a curved girder, or on a spandrel beam picking up a floor along one edge — makes the twist a function with its own differential equation, and the proportions carried by each mechanism vary from point to point.

Plasticity. Everything above is elastic. The plastic torsional capacity of a closed section is reached when the shear flow yields all the way round, which is a clean sand-heap analogy and a much larger capacity than first yield suggests.

The figures cannot show the deformation they are about. Twist is a rotation per unit length along an axis pointing out of the page, and the drawing is of the cross-section, so what the reader sees is a shape with arrows on it and a number in words beneath. The one honest way to convey the difference is the number itself: at 5 kNm over 3 metres the closed section here twists by 0.19 degrees, which nobody would see, and the slit one by 81 degrees, which is not a structural member any more. The peak shear stress tells the same story from the other side — 8.5 N/mm² against 305, from the identical torque on the identical steel.

The section that is closed and the section that is nearly closed

Between the box and the slit box there is a case that arises constantly and behaves like neither: the section closed by something that is not the parent material — a cover plate on bolts, a concrete slab on shear studs, a lipped channel whose lips nearly touch.

The rule is unforgiving. A loop is a loop only if it can carry the flow all the way round, so the connection closing it must carry the full q=T/2Amq = T/2A_m along its entire length. Get that right and the section has the closed constant; get it wrong anywhere and it has the open one. There is no intermediate: the flow either completes the circuit or it does not.

This is the same requirement that turns two plates into one built-up section, and it is the more severe version of it, because a bending connection that is locally weak sheds a little load to its neighbours while a torsional loop that is locally broken is simply not a loop.

The ordinary cut diagram of this collection cannot draw any of it. A cut exposes a shear force and a bending moment, and both can be found by summing what is on one side and drawn as an arrow in the plane of the page. Torsion is a moment about an axis pointing along the beam and therefore out of the page — the one stress resultant with no representation in the plane the whole subject is drawn in, which is why the membrane figure above is the only picture on this page that shows the action itself rather than the section it acts on.

That is worth dwelling on, because it explains why torsion is under-taught rather than merely difficult. Every drawing convention in statics is two-dimensional. Shear and bending have natural pictures; torsion has a curly arrow that means “into the page and round”, which is a symbol rather than a depiction. A subject drawn on paper will tend to neglect the action that paper cannot show.

The generalisation

The pattern that makes torsion behave unlike its five siblings is worth stating on its own, because it recurs whenever a structural action is resisted by a circulation rather than by a distribution.

Bending, shear and axial force are all resisted by stresses that integrate across the section; their capacity is an integral of material times lever arm, and adding material anywhere helps a little. Torsion in a closed section is resisted by a loop, and a loop is a topological object. Its capacity depends on the area the loop encloses, which is not a property of any material at all — a fact made vivid by the observation that the enclosed area in Bredt’s formula includes the hole, where there is nothing.

The consequence is that torsional capacity can be destroyed without removing material. A slit of zero width, taking away no steel, divides the constant by hundreds. Nothing else in structural engineering has that property: there is no cut that halves a section’s bending capacity without removing anything.

The same material, three ways. Three cross-sections of identical area, so identical weight and cost, with the second moment of area computed from each profile's own geometry. Only the arrangement differs, and the stiffest is many times the flattest.
Fig. 8 Three sections of identical area. In bending, the I-section and the hollow section are close and both beat the rectangle handsomely — the argument that shape beats material runs on the second moment of area. In torsion the ranking changes completely: the hollow section beats the other two by two orders of magnitude, and the I-section is the worst of the three. One property, ranked two ways, depending on which of the six actions is being asked about.

Coulomb solved the circular shaft in 1784, and the result is so clean — plane sections stay plane, stress proportional to radius — that it was assumed to generalise. It does not: applied to a rectangular bar it predicts the maximum stress at the corners, where the true stress is zero, since a free surface cannot carry shear across itself. Saint-Venant sorted it out in 1855 with the warping function, and Prandtl gave the memorable version in 1903 with the membrane analogy — stretch a soap film over a hole shaped like the section, blow gently, and the volume under the film is proportional to the torsion constant while the slope is the shear stress. The analogy makes the whole of this essay obvious in one image: a film over a long thin slot bulges hardly at all, and a film over a closed annulus is a different problem entirely.

The ladder from here

Later rungs on this anchor: warping torsion in full, with the bimoment as a stress resultant in its own right. The multi-cell box and its torsional redundancy. Distortion and the diaphragm. Combined bending, shear and torsion, and the interaction surface. Plastic torsion and the sand-heap analogy. And the curved girder, in which bending and torsion are inseparable because the geometry couples them — the case where torsion stops being an accident to be avoided and becomes part of the primary load path.

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Hollow sectionOpen sectionShear centreShear flowStress resultantTorsionTorsion constantWarping