Series

Distributed load — the series

One essay so far on this idea, and more questions about it than one essay answers.
  1. A triangular load and the force that replaces it. A triangular distributed load with its resultant computed by integration: an area of 24.0 acting at 5.33 from the left. The two moment diagrams below show what the substitution costs — the reactions are identical and the peak moment is not.

    The load that is spread out, and the force that replaces it

    A distributed load can be swapped for a single force at its centroid. The reactions come out identical and the bending moment does not, and knowing which side of the cut the swap is legitimate on is most of the skill.

    part 1 · equilibrium

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